The calculation of short-circuit current in the electrical design of traction substation
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1 Advances in Engineering Research (AER), volume International Conference on Engineering and Advanced Technology (ICEAT-16) The calculation of short-circuit current in the electrical design of traction substation DeSheng Zhong Guidaojiaotong Polytechnic Institute, Shenyang 12, China Keywords: short-circuit current, traction substation, traction substation. Abstract. This paper mainly studies the calculation of short-circuit current in the electrical design of a domestic electrified railway traction substation power supply system. The choice of short-circuit point depends on the main transformer capacity that determined according to the traction substation main connection mode and load calculation results, calculation of short-circuit current, Completed the main electrical equipment and selection of busbar according to the results of the short circuit calculation. 1. Introduction The power supply system of electrified railway traction substation that we studied in this paper, use the AT power supply mode, it is double line, section of ascending and descending parallel power supply. Combined with the actual situation of substation, the choice of connection mode is feeder circuit breaker 50% spare. ecause of the 220/10kV distribution substation built with the substation together, leads to two private electricity transformers from 10 kv bus bar for the needs of the resources reasonable use and safety of power supply. Traction transformer capacity should be able to bear the maximum load of substation, and meet the requirements of railway transport normal, therefore chooses four kva single-phase traction transformer. According to J/T , choose D-QY50000 traction transformer, its parameters are shown in table 1. Table 1 The parameters of single-phase traction transformer High Voltage Low Voltage Connection (kv) (kv) Symbol 220±2 2.5% Ii0 o-load loss (kw) 40 Load loss o-load Short-circuit (kw) Current Impedance % 12% 2. The required raw materials for Calculate Feeding section1 n=.5, =140pair/day, 1k=180pair/day; Feeding section2 n=.8, =150pair/day, 1k=200pair/day; n interval number; The train logarithm of the feeding section; 1k Maximum number of train. The rest of the original calculation data are shown in table 2. Copyright 2017, the Authors. Published by Atlantis Press. This is an open access article under the CC Y-C license ( 60
2 Feeding section Table 2 The required raw materials for Calculate The total running The energy consumption Electricity running time of train in t( t time t(min) t g (min) g ) A(kVA.h) up train down train up train down train up train down train Calculation of short-circuit current Short circuit is a low edance short sub on conductive part of different potential, includes conductive parts to ground between subs. The main purpose of the calculation of short-circuit current is complete electrical equipment selection and busbar selection, In this design, the calculation of short-circuit current in accordance with the three phase short circuit calculation, and assumes that the system for the infinite power[1]. nit reactance of transmission lines x 1 = 0.4Ω/km, ase Capacity voltage = (Average voltage rating of power lines). av.n = MVA,reference (1) Equivalent circuit diagram and the calculation of each component reactance etwork diagram of this design is slified according to the main connection mode selection and operation mode for a long time, draw the network diagram as shown in figure 1, T1, T2 are the two 50 mva single-phase traction transformer in figure. First of all, short-circuit point selection, according to the analysis can select k1, two short-circuit point to calculate short circuit current, as shown in figure kv side SES is a bridge connection, when the switch is closed, when run in parallel with two way power supply, it is the largest operation mode, slified equivalent calculation of network diagram is shown in figure 2. G1 G2 220kV k 1 G 220kV k 1 1 T 1 T 2 2 kv k 2 kv Fig.1 Short circuit network wiring diagram Fig.2 Equivalent network diagram According to the provisions in China standard, take 220 kv voltage benchmark of =20kV. Set G1, G2 short-circuit point from k1 distance of l1=l2=km, The MAO value of linear reactance is: * * 1 = 2 = xl 11 = 0.4 = Above formula: x 1 Line reactance, Ω/m ; l line length, m. (2) The calculation of short-circuit current 1The calculation of short-circuit current of k1 point The current benchmark is: k 2 61
3 Above formula: I = = = (ka) S Three-phase power value, Generally take MVA; Voltage reference value, kv. The MAO value of total reactance: * * * = 1 / / 2 = = The MAO value of three phase short circuit current cycle componen: * 1 I = = 25 k1 * 1 Impact currentfor of three-phase short-circuit: i = 2.55I = (ka) Maximum RMS of the three-phase short-circuit current: I = 1.52I = 9.5 (ka) Maximum continuous working current: S (50 50) 10 Igmax = 1.05 = 1.05 = The calculation of short-circuit current of point Approximate equivalent circuit of V/ wiring traction transformer as shown in figure (a), Y type equivalent circuit as shown in figure (b) (A) Z 2 I Z 1 2Z T s I T E I F F Z T F 4Zs Z1 Z2 2Z Z s 1 4Zs Z1 Z (a) The approximate equivalent circuit (b) Y type equivalent circuit Fig. Equivalent circuit of V/ wiring traction transformer 2 * 2 * 2 System edance: Zs = Zs. = 1. = 0.04 = 0. ( Ω ) Analyzing the characteristics of the V/ wiring traction transformer connection, and according to the single-phase traction transformer parameters are known to be elected in table 2: k(1-2) (%)= k(1-) (%)=12 Traction transformer primary side after short circuit edance seen from secondary side is: k(1-2) (%) 12 Z12 = 12 = = = 1.82 ( Ω ) ST 50 Similarly, Traction transformer primary side after short circuit edance seen from tertiary side is: k(1-) (%) 12 Z1 = 1 = = = 1.82 ( Ω ) ST 50 When T busbar one-phase ground fault at kv side, short circuit current is: I = dt Z Z Z = 2Z Z = (ka) s 1 2 s 1 2 E T E F 62
4 When F busbar one-phase ground fault at kv side, short circuit current is: I = df Zs Z1 Z = 2Zs Z = (ka) 1 When phase fault between F and T busbar at kv side, short circuit current is: 55 I = dtf IdT 8Zs 4Z1 Z2 Z = 4Zs Z1 Z < 12 From the above analysis, When F or T busbar one-phase ground fault at kv side, Short circuit current is greater than phase fault between F and T busbar at kv side, so I =I dt =I df =11.6kA. short circuit act current is: i = 2.55I = (ka) The biggest valid values for short circuit current: I = 1.52I = (ka) Maximum continuous working current is: S (50 50) 10 Igmax = 1.05 = 1.05 = Electrical equipment and the choice of bus According to the actual short circuit state calibration, is to check the thermal stability and dynamic stability of electrical equipment[2]. It is concluded that the choice of the electrical equipment as shown in table : Table Electrical equipment (A) Electrical Equipment Type Model Primary Cut-Out Vacuum Circuit reaker ZW-2 High Voltage Isolator 220kV Side Disconnector 2 kv Side Disconnector GW4-220 GW kV Side Current Transformer LCW7-220 Current Transformer 2 kv Side Current Transformer LDG-5 220kV Side Voltage Transformer JDCF-220 Voltage Transformer 2 kv Side Voltage Transformer JDZ- The choice of the bus: LGJ - 95/15 type steel core aluminum stranded wire is chosen as the 220 kv busbar side bridge[];choose LF - 21 y type aluminum manganese alloy tubular busbar as 2 x kv bus side. 5. Summary According to the result of short circuit calculation, and considering the actual situation of the traction substation, completed the selection of electrical equipment and bus, provide the basis for the whole electrical design of traction substation of electrified railway power supply system. References [1] D. L. Garrett and K. A. Wallace, A critical analysis of grounding practices for railroad tracks in electric utility systems, in IEEE PES Winter Meeting, ew York, 1992, Paper o: 92 WM 6
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