Do Now: Do Now Slip. Do Now. Lesson 20. Drawing Conclusions. Quiz Tomorrow, Study Blue Sheet. Module 1 Lesson 20 Extra Practice.
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1 Lesson 20 Drawing Conclusions HW Quiz Tomorrow, Study Blue Sheet Do Now: Do Now Slip Oct 20 1:03 PM Do Now 1. CB is parallel to DE 2. <1 <2 2. If parallel lines are cut by a transversal then corresponding angles are congruent Oct 23 9:09 PM 1
2 1. O is the midpoint of DG 2. DO OG 2. A midpoint divides a segment into two congruent parts 1. YT bisects <XYZ 2. <1 <2 2. a bisector divides an angle into two congruent parts Oct 20 1:09 PM <CAB <BAD 1. AB bisects <CAD 2. <CAB <BAD 2. a bisector divides an angle into two congruent parts 1. E is the midpoint of SG 2. SE EG 2. A midpoint divides a segment into two congruent parts Oct 20 1:09 PM 2
3 AB BC 1. DE bisects AC at B 2. AB BC Given 2. a bisector divides a segment Oct 20 1:09 PM 1. <1 <2 1. vertical angles are congruent 1. JT bisects CM at P 2. CP MP 2. a bisector divides a segment Oct 20 1:09 PM 3
4 1. c l d 2. <3 and <4 are right angles 3. <3 <4 2. Perpendicular lines form right angles 3. all right angles are congruent 1. AB l CD, BC l DC 2. <B and <C are right angles 3. <B <C 2. Perpendicular lines form right angles 3. all right angles are congruent Oct 20 1:09 PM 1. AE l BC 2. <BEA and <CEA are right angles 3. <BEA <CEA 2. Perpendicular lines form right angles 3. all right angles are congruent Oct 20 1:10 PM 4
5 1. AE is the perpendicular bisector of BD 2. <BCA and <DCA are right angles 3. <BCA <DCA 2. Perpendicular lines form right angles 3. all right angles are congruent 4. BC <DC 4. a bisector divides a segment Oct 20 1:10 PM Oct 23 7:47 PM 5
6 1. <GBD <ECA 2. <GBD + <GBA = 180 <ECA + <ECD = <GBD+<GBA= <ECA + <ECD 4. <ABG <DCE 2. Linear pairs form supplementary angles 3. Substitution Property of Equality 4. Subtraction Postulate Oct 14 8:36 AM 1. <6 <7 2. <5 + <6 = 180 <7 + <8 = Linear pairs form supplementary angles 3. <5 + <6= <7 + <8 3. Substitution Property of Equality 4. <5 <8 4. Subtraction Postulate Oct 14 8:37 AM 6
7 1. <ACB <DCE 1. vertical angles are congruent Oct 14 8:37 AM 1. AD bisects BE 2. CB CE 2. a bisector divides a segment 1. CB is parallel to DE 2. <1 <2 2. If parallel lines are cut by a transversal then corresponding angles are congruent Oct 14 8:37 AM 7
8 1. <A <D 2. AB is parallel to DE 2. If alternate interior angles are congruent then parallel lines are cut by a transversal Oct 14 8:37 AM AE EC DE EB 1. BD and AC bisect each other at E 2. AE EC 3. DE EB 2. a bisector divides a segment 3. a bisector divides a segment 1. <1 <2 2. CB is parallel to DE 2. If corresponding angles are congruent then parallel lines are cut by a transversal Oct 14 8:37 AM 8
9 1. B is the midpoint of CD 2. CB BD 2. A midpoint divides a segment into two congruent parts Oct 14 8:38 AM 2. AC is parallel to DF 1. <ACB <FDE 2. If parallel lines are cut by a transversal then alternate exterior angles are congruent 1. BD EC 2. CD CD 3. BC + CD = BD 4. CD + ED = EC 5. BC + CD ED + CD 6. BC ED 2. Reflexive Property 3. Addition Postulate 4. Addition Postulate 5. Substitution Property 6. Subtraction Postulate Oct 14 8:38 AM 9
10 1. AB l BE, FE l EB 2. <B and <E are right angles 3. <B <E 2. Perpendicular lines form right ang 3. all right angles are congruent Oct 14 8:38 AM 1. <ACD <FDC 2. <ACD + <ACB = 180 <FDC + <FDE = <ACD+<ACB= <FDC + <FDE 4. <ACB <FDE 2. Linear pairs form supplementary angles 3. Substitution Property of Equality 4. Subtraction Postulate 1. AC AE 2. <C <E 2. In a triangle, angles opposite congruent sides are congruent Oct 14 8:38 AM 10
11 1. AB bisects DF 2. DE FE 2. a bisector divides a segment Oct 19 11:54 AM Given: AD l CE Prove: <ABE is a right angle C Exit Ticket A B D E Oct 20 1:08 PM 11
12 Oct 19 11:54 AM Oct 19 11:55 AM 12
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