Enumerative Combinatoric Algorithms. Gray code

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1 Enumerative Combinatoric Algorithms Gray code Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, 27

2 Standard binary code: Ex, 3 bits: b = b = b = 2 b = 3 b = 4 b = 5 b = 6 b = 7 Binary code Problem: In the transition from 3 to 4 every bit changes. Thus, if timing is not absolutely perfect (it never is) then any number from to 7 can be read. e.g.: position encoder, electronic circuits,... Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, 27 2

3 Gray code a.k.a. reflected binary code (Frank Gray, 947) binary Gray code: successive values differ in only one bit generate a Gray code (G(n)) for n bits from G(n ): reflected binary code G(n) G(n ) G(n ) n=: n=2: n=3: Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, Observe that this way also the last and the first number differ only in one position.

4 Uses applications initially for analog to digital conversion for compatible color television signals also used in telegraphy and position encoders (linear and rotary) error correction in digital communications genetic algorithms solving puzzles (Towers of Hanoi, Chinese rings puzzle, Spin-out,...) Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, 27 4

5 binary Gray code conversion b n b n 2... b b g n g n 2... g g b n = g n i < n b i = b i+ XOR g i g i = b i+ XOR b i X Y X XOR Y Ex: standard binary b? Ex: Gray code g? Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, 27 5

6 Puzzle: Tower of Hanoi Given: A stack of n different sized disks, arranged from largest on the bottom to smallest on top, placed on a rod, A. Plus two more empty rods, B and C. Valid move: move one disk from one rod to another one but not placing a larger disk on top of a smaller disk. Task: Move the stack (tower) from rod A to rod B (using rod C) (... with minimum number of moves) Solution (recursive): to move a tower, T (n), of size n from A to B using C: move T (n ) from A to C using B, then the largest disk from A to B, and then move T (n ) from C to B using A. Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms,

7 Tower of Hanoi vs. Gray code label the disks from (smallest) to n (largest) g n g n 2... g g... a number in Gray code The changes in the Gray code (if bit i changes) define the disk (disk i) that has to be moved: disk always cw (or always ccw, depending on parity) disks i, < i < n, unique way to move Ex: n = 4 A start: all 4 disks on A goal: all 4 disks on B n is even move ccw Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, C B

8 Tower of Hanoi vs. Gray code A B C Ex: n = 4 A start: all 4 disks on A goal: all 4 disks on B n is even move ccw Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, C B

9 Tower of Hanoi vs. Gray code M. Gardner proved (957,59) that the Tower of Hanoi problem is isomorphic to finding a Hamiltonian path on an n-hypercube. n-hypercube has 2 n vertices a path visiting them all has 2 n edges at least 2 n moves Ex: n = 4 A start: all 4 disks on A goal: all 4 disks on B n is even move ccw Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, C B

Another puzzle: Spin-out very similar to Chinese Rings puzzle 7 spinners take one of two possible orientations:, initially all are ; the goal is that all are problem:

10 Another puzzle: Spin-out very similar to Chinese Rings puzzle 7 spinners take one of two possible orientations:, initially all are ; the goal is that all are problem: only the rightmost spinner can rotate and any spinner which is the left neighbor of the rightmost Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms,

11 Another puzzle: Spin-out Solution: n spinners from left to right g n... g spinner i is g i = ; spinner i is g i = traverse the Gray code from... to... in reverse direction Ex: n = 4 done Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms,

12 Generate next Gray code number G[i] G[i + ] count the number # of s in G[i] if # is even then flip g of G[i] to get G[i + ] else flip the left neighbor (bit position) of the rightmost func nextgray(g):... g = g[n ]... g[] if (#(g) is even) then flip g[]; else r index of rightmost of g if (r < n ) then flip g[r+]; else flip g[r]; fi fi return (g)... next Gray number (G[] if input was G[2 n ]) Oswin Aichholzer (slides TH): Enumerative Combinatoric Algorithms, 27 9

An Efficient Implementation of Tower of Hanoi using Gray Codes

GRD Journals Global Research and Development Journal for Engineering National Conference on Computational Intelligence Systems (NCCIS 17) March 2017 e-issn: 2455-5703 An Efficient Implementation of Tower