TCS PATTERN WITH SUDOCO AND PUZZLES

Transcription

1 01 If a x =b, b y =c and c z =a, then xyz = 01 (a) 1 (b) 0 (c) abc (d) abc 01 (a) (a) 01 First 2 eqns imply c = a xy. Put this in 3 rd eqn. a xyz =a or xyz =1 Six persons Andy,Bandy,Candy,Dandy,Endy and Fendy are sitting in two rows, three in each. Endy is not at the end of any row Dandy is second to the left of Fendy. Candy the neighbour of Endy, is sitting diagonally opposite to Dandy. Bandy is the neighbour of Fendy? Which of the following are sitting diagonally opposite to each other? (a) Fendy,Candy (b) Dandy,Andy (c) Andy,Candy (d) Andy,Fendy 02 (d) If f(u) = u and the value of the expression f(2a) 2 f(a) = 383, then a= 03 (a) 8 (b) 7 (c) 6 (d) 4 03 (d) 03 Put eqn 1 in 2. 8a (a 3 +1)=383 a=4 The probability of getting a sum of 35 on the visible sides of two dies rolled on a wooden floor is (a) 5/6 (b) 1/6 (c) 7/12 (d) 2/3 04 (a) [a] Sum of visible sides = 35 implies sum of invisible sides = 7. Possibilities are (1 and 6, 2 and 5,3and4,4and 3,3,5and2,6and1). 04 Probability = 6/36 = 1/6 05

2 y 3 - x 3 =? 05 (a) 604 (b) 612 (c) 216 (d) (a) What was the day on 16 Apr 2000? 06 (a) Sunday (b) Monday (c) Tuesday (d) Wednesday 06 (a) How many February 29ths occur in a centenary? 07 (a) 100 (b) 101 (c) 99 (d) (c) The reflex angle in degrees between the hands of a clock at is: 08 (a) 180 (b) (c) 195 (d) (d) Angle traced by hr hand in 125/12 hrs = deg Angle traced by min hand in 25 min = = 150 deg 08 Reflex angle = 360 ( ) deg = deg A manufacturer sells a pair of glasses to a wholesaler at a profit of 18%. The wholesaler sells the same to a retailer at a profit of 2% more than wholesaler. The retailer in turn sells them to a customer for Rs , earning 25% gain. 09 The CP for manufacturer in Rs is 09 (a) 15 (b) 16 (c) 17 (d) (c) Let the CP for manufacturer be Rs x % of 120% of 118% of x = or x = 17 4/5 th of the voters in Bellary promised to vote for Sonia Gandhi and the rest promised to vote for Sushma Swaraj. Of these voters, 10% of the voters who had promised to vote for Sonia Gandhi, did not vote on the election day while 20% of the voters who had promised to vote for Sushma Swaraj did not vote on the election day. What is the total number of votes polled if Sonia Gandhi got votes? 10 (a) 200 (b) 300 (c) 264 (d) (b) total vote =x 10 4/5 for sonia but in during election 4/5*0.90x=216 so x=300 A person walking takes 26 steps to come down on a escalator and it takes 30 seconds for him for walking. The same person while running takes 18 second 11 and 34 steps. How many steps are there? 11 (a) 50 (b) 48 (c) 46 (d) (c) 11 Let's suppose that escalator moves n steps/sec.

3 It is given that if he walks he takes 30 sec and covers 26 steps. So in that 30 sec escalator would have covered 30n steps. Hence the total number of steps on the escalator is n----(1) Similarly when he runs he takes 18 sec and covers 34 steps. So in 18 sec escalator covers 18n steps. Hence total steps on the escalator must be n (2) Equating (1) & (2) n = n we get n= 2/3 Hence no. steps is 26+30(2/3) = 46. Vicky's salary is 75% more than Ashu's.Vicky got a raise of 40% on his salary while ashu got a raise of 25% in his salary.by what % Vicky's salary is more 12 than Ashu's? 12 a) 96 b) 51.1% c) 90% d) none of these 12 (a) Vicky's salary is 3/4(75%)th more than Ashu's salary. So it will be easier to solve the problem if we take Ashus salary as a multiple of 4. So we take their salary as: Ashu = 40 Vicky 1.75 * 40 = 70 New salary 40*125/100 = 50 70*140/100 = 98 Vicky's salary is more than Ashu's saalry by (98-50)=48 12 So percentage will be 48/50*100 = 96% If x y +y x =1234, how many positive integer value pairs of x and y satisfy this 13 condition? 13 (a) 1 (b) 2 (c) 3 (d) 4 13 (b) Any no raised to power 1 is itself and 1 raised to any power is is effectively So (x,y)= (1233,1) or (1,1233) There are 8 bags among which 7 have the same weight and one is slightly heavier. You have a balance of infinite capacity. What is the minimum of turns 14 required by you to find the odd bag? 14 (a) 0 (b) 1 (c) 2 (d) 3 14 (c) Keep 3 bags on either side of the balance. CASE 1: They weigh equal Weigh the other two bags and find the heavier one. CASE 2: One side is heavier. Take two bags from the heavier side. If one side is heavy, then it is the required bag. 14 If they are equal again, the third bag is the heaviest. Eight books are kept one over the other counting from the top the second, fifth and sixth books are on plays. 15 Two books on plays are between two books on composition.

4 One book of plays is between two books on poetry. While the book at the top of the book of literature is a book of composition. Which book is fourth from the top? 15 (a) plays (b) poetry (c) composition (d) literature 15 (c) Let C denote 'composition', P denote 'plays', Po denote 'poetry' and L denote 'literature' _ P P P _ C P P C _ Po P Po _ C L So the arrangement becomes: Po P Po C P P C L 15 Clearly the fourth book from the top is on composition. DIRECTIONS FOR Q16: Study the following passage and answer the question that follows It is not unusual to see the ball fall into a black slot on a roulette wheel four times in a row. But for it to fall five or six times in a row into the same color is very unusual. Therefore you can win money by waiting for a run of five of the same color and then betting against that color. If the roulette wheel in question is a fair wheel, which of the following observations or facts, if it were true, would best reveal a fallacy in the logic? (a) If there were a reliable way to win at roulette it would be well-known by now. (b) It is hard for a player to keep track of what went before for the time required. (c) The probability of getting a particular color decreases with the number of times the color has appeared. (d) The probability of getting a particular color is always the same no matter what has gone before. 16 (d) In critical reasoning questions many of the answer choices can be factually correct or reasonable sounding, and so eliminating without understanding the question is not possible. Your job is to find the best answer to the specific question, so read carefully. A fallacy in the logic is an error in the thinking behind the proposal. The person concludes that if you wait for a run of five of the same color and then bet against the color, you WILL win. Now the logic behind that suggests that the probability of getting that same color again is low. But just as tossing a fair coin always gives an even chance of a head or 16 tail no matter what has gone before, the probability of getting a color is

5 always the same no matter what has gone before. 6 boys and 6 girls sit at random in a row. What is the probability that all girls 17 are together? 17 (a) 1/7 (b) 1/132 (c) 1/66 (d) 8/17 17 (b) 17 7! * 6! / (12)! = 1/132 4 circles are drawn with their centres lying on the vertices of a square such that the length of the side of the square equals the diameter of each circle. The ratio of the area between the circles to the square of the largest distance between 18 any two points lying on any of the circles is 18 (a) (b) (c) (d) 18 (a) Let side of square be a. Radius of each circle = a/2 Adjacent Circles intersect at a mid-point of square s side. Area between circles = area of square 4 times area of quadrant of circle = area of square area of 1 circle = a 2 - ( ) Largest distance in the diagram is between opposite ends of opposite circles = radius + diagonal of square+ radius = a + a 2 18 Required ratio = [a 2 - ( ) ] / [a + a 2] 2 = 19 If a fourth of twenty is 4, then what is a ninth of 30? 19 (a) 1/3 (b) 2/3 (c) 4/3 (d) 8/3 19 (d) ¼ th of 20 is 5 and 1/9 th of 30 is :4 :: 10/3 :? 19 Ans is (10/3) / (4/5) = 8/3 A cube with an edge of 12. If this cube is divided into smaller rectangular solids with dimensions 2 by 2 by 4, how many times greater is the combined surface areas of all these smaller rectangular solids than the surface area of 20 the larger cube? 20 (a) 16 (b) 3 (c) 8 (d) 5 20 (d) cube = 12 x 12 x 12 area = 12 x 12 x 6 = 144 x 6 = 864 (4 sides, top and bottom ) block is 2 x 2 x 4 > 12/2 = 6 > 12/4 = 3 so we get 6 x 6 x 3 blocks in the cube = 36 x 3 = 108 area of 4 x 2 x 1 = 4(4 x 2) + 2 (2 x 2) = (4 x 8) + (2 x 4) = =40 each block 40 * 108 = /864 = 5 so 5 times is E

6 A shopkeeper increases the price of an article by X% and then decreases it by X%. As a result the price of the article is reduced by Rs180. After one more such change 21 the price is further reduced by Rs153 Find the original price of the article in rupees. 21 (a) 1000 (b) 1200 (c) 1400 (d) (b) let x = X/100, and let the original price = P P - P(1+x)(1-x) = 180 P(1-1+x^2) = 180 P= 180/x^2... [ I ] (P-180) - (P-180)(1-x^2) = 153 (P-180) = 153/x^2... [ II ] [ I ] / [ II ] P/(P-180) = 180/ P = 180(P-180) 27P = 180* P = Find the missing number in the series: 1,8,2,6,1,2,3,5,7,? 22 (a) 9 (b) 1 (c) 3 (d) 5 22 (b) 22 These are the first digits of the cubes of natural numbers from 1. In a certain language, BAC is written as 345, CTD is written as Then 23 FOOD is written as 23 (a) (b) (c) (d) none of these 23 (a) 23 Pattern is B + A = 2+1=3, A+C = 1 +4 = 5, C + B(first letter)=3+2 =5. So The determinant of a skew-symmetric matrix is (a) zero (b) a perfect (c) Either a or (d) None of these 24 square b 24 (c) 24 It is zero for odd order and a perfect square for even order. There are 12 pipes that are connected to a tank. Some of them are fill pipes and the others are drain pipes. Each of the fill pipes can fill the tank in 8 hours and each of the drain pipes can drain the tank completely in 6 hours. If all the fill pipes and drain pipes are kept open, an empty tank gets filled in 24 hours. How many of the 12 pipes are fill 25 pipes? 25 (a) 8 (b) 7 (c) 4 (d) 5 25 (b) Let there be 'n' fill pipes attached to the tank. Therefore, there will be 12 - n drain pipes attached to the tank 25 Each fill pipe fills the tank in 8 hours. Therefore, each of the fill pipes will

7 fill th of the tank in an hour. Hence, n fill pipes will fill of the tank in an hour. Each drain pipe will drain the tank in 6 hours. Therefore, each of the rain pipes will drain th of the tank in an hour. Hence, (12 - n) drain pipes will drain th of the tank in an hour. When all these 12 pipes are kept open, it takes 24 hours for an empty tank to overflow. Therefore, in an hour th of the tank gets filled. Hence,. i.e. or 7n - 48 = 1 => 7n = 49 or n = 7. Find the total number of signals that can be made by five flags of different colour when any number of them may be used in any signal (a) 125 (b) 225 (c) 325 (d) (b) Case I : When only one flag is used.no. of signals made = 5P1 = 5. Case II : When only two flag is used. Number of signals made = 5P2 = 5.4 = 20. Case III : When only three flags are used. Number of signals is made = 5P3 = = 60. Case IV : When only four flags are used. Number of signals made = 5P4 = = 120. Case V : When five flags are used. Number of signals made = 5P5 = 5! = Hence, required number = = 325. If each of the m points in one straight line be joined to each of the n points on the other straight line, the excluding the points on the 27 given two lines. Number of points of intersection of these lines is (a) mn(m-1)(n- (b) mn(m+1)(n (c) (m + 1)(n (d) none of these 27 1)/4-1)/4-1) 27 (a) To get one point of intersection we need two points on the first line and two points on the second line. These can be selected out of n-points in nc2 ways and 27 for m points in mc2 ways.

8 Therefore Required number = mc2 nc2 = (m(m-1))/2!. (n(n-1))/2! = 1/4 m n (m - 1)(n - 1) Bucket P has thrice the capacity as bucket Q. IT takes 60 turns for bucket P to fill the empty drum. How many turns it will take for both the buckets and Q, having 28 each turn together to fill the empty drum? 28 (a) 30 (b) 45 (c) 50 (d) (b) Let capacity of P be x litres. Then, capacity of Q = x/3 litres. Capacity of the drum = 60x litres. 28 Required number of turns = 60x/(x + x/3) = 45 A can do a piece of work in 20days, B in 15 days and C in 12 days. In how many days can A finish the work if he is assisted by B on one day and C on the next, 29 alternately? 29 (a) 8 (b) 4 (c) 3 (d) (a) Length of tunnel to be dug(assume) = lcm of 20,15 and 12 = 60ft (assume) Day1: A digs 3 ft and B 4 ft. Total 7 ft Day2:A 3ft,C 5 ft total 8 ft. So in 2 days 15 ft. 29 Reqd days = 60/15 times 2 days = 8 days 3 men or 6 women can do a piece of work in 20 days. In how many days will men and 8 women do the same work? 30 (a) 7/2 (b) 15/4 (c) 4 (d) 5 30 (b) 3 men in 20 days so 1 man in 60 days. 6 women in 20 days so 1 woman in 120 days. 12 men and 8 women means 12/60 + 8/120 = 32/120 = 4/15 30 Or they will complete it in 15/4 days.