Bell Ringer: Define to the best of your ability the definition of: Current Voltage Resistance
|
|
|
- Ruby Chapman
- 5 years ago
- Views:
Transcription
1 Bell Ringer: Define to the best of your ability the definition of: Current Voltage Resistance Explain the behavior of the current and the voltage in a Series Circuit. Explain the behavior of the current and the voltage in a Parallel Circuit.
2 Notes 7.4: Parallel Circuits This lesson promises to be ELECTRIFYING!
3 Learning on Your Own: All About Circuits All About Circuits Combination All About Circuits Analysis Technique All About Circuits Redrawing Combination Circuits
4 Lesson Objective: Recall the behavior of voltage, current, and resistance when objects are in series with one another. Recall the behavior of voltage, current, and resistance when objects are in parallel with one another. Determine how to solve for the voltage, current, resistance, and power when you have a combination circuit (series-parallel).
5 Combination Circuits: The world of circuitry is not strictly split into series circuits and parallel circuits. For instance, two objects may be in parallel with one another, but their total resistance may be in series with another resistor. Or two objects in series may have a total resistance that is in parallel with another resistor. Before we get started analyzing combination circuits, let s refresh on the behavior of voltage, current, and resistance in series and in parallel.
6 Series Circuits:
7 Series Circuits: Current is the same throughout. Anywhere current is measured, you will measure it to be the same as the total current in the circuit. Voltage change. Voltage is divided up between the different resistors but not equally. Series circuit is also called a voltage divider. V Battery = V 1 + V 2 + V 3 The total resistance between two or more resistors in series is given by: R eq = R 1 + R 2 + R 3
8 Parallel Circuits:
9 Parallel Circuits: Current changes. Current is split between the three resistors but not equally. Their total should add up to the total current before is divided by the two or more pathways. I T = I 1 + I 2 + I 3 Voltage stays the same. When two or more resistors are in parallel, they will always have the same voltage. The total resistance between two or more resistors in parallel is given by: R eq = 1 1 R1 + 1 R R 3
10 We can still use the table we have used before which I highly recommend. V=IR I=V/R R=V/I P=IV R 1 R 2 R 3 Total
11 Sample Problem 1
12 Sample Problem 1: Use the table method to determine the voltage, current, and resistance of each resistor.
13 Sample Problem 1: Use the table method to determine the voltage, current, and resistance of each resistor.
14 Sample Problem 1: Step 1: R 2 and R 3 are in parallel so combine the two resistors by using the equation R 2,3 = 1 1 R R3 = 3.3 Ω.
15 Sample Problem 1: R 2 and R 3 are in parallel so we can redraw this circuit as pictured below. Now we see the equivalent of R 2,3 is 3.3 Ω and it is in series with R 1.
16 Sample Problem 1: Since R 1 and R 2,3 are in series then we can simply add them to find the total resistance in the circuit. R T = R 1 + R 2,3 = 23.3 Ω.
17 Sample Problem 1: Since R 1 and R 2,3 are in series then we can simply add them to find the total resistance in the circuit. R T = R 1 + R 2,3 = 23.3 Ω.
18 Now, we have our table where know the total voltage is from the battery, and we have already calculated the total resistance. V=IR I=V/R R 1 R 2 R 3 Total 30 V R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
19 All we need are two objects to be able to calculate another quantity. Well we have our total voltage and total resistance so we can calculate our total current as: I = V R I = 1.3 A = 30 V 23.2 Ω V=IR I=V/R R=V/I P=IV Total 30 V 23.3 Ω
20 Now our chart looks like below. So what do we do next? R 1 R 2 R 3 Total V=IR 30 V I=V/R 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
21 Sample Problem 1: We trace the path of current. We know that the current is split between R 2 and R 3 but it is undivided as it goes through R 1. Therefore, I 1 is equivalent to the total current in the circuit.
22 Now our chart looks like below. Can we calculate anything else? R 1 R 2 R 3 Total V=IR 30 V I=V/R 1.3 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
23 We can calculate the voltage through resistor 1. V 1 = I 1 R 1 V 1 = (1.3 A)(20 Ω) V 1 = 26 V V=IR I=V/R R=V/I P=IV R A 20 Ω
24 Now our chart looks like below. Can we find V 2 and V 3? R 1 R 2 R 3 Total V=IR 26 V 30 V I=V/R 1.3 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
25 Since V 2 and V 3 are in parallel, we know their voltage will be the same. We also know that R 2,3 is in series with R 1. So what does that mean about the voltage? It means that V T = V 1 + V 2,3. V T = V 1 + V 2,3 30 V = 26 V + V 2,3 V 2,3 = 30 V 26 V V 2,3 = 4 V
26 Since V 2 and V 3 are in parallel than they are the same. R 1 R 2 R 3 Total V=IR 26 V 4 V 4 V 30 V I=V/R 1.3 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
27 Now we should be able to calculate I 2 and I 3 using I=V/R. R 1 R 2 R 3 Total V=IR 26 V 4 V 4 V 30 V I=V/R 1.3 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
28 I 2 + I 3 = 1.3 A which equals the total. R 1 R 2 R 3 Total V=IR 26 V 4 V 4 V 30 V I=V/R 1.3 A 0.4 A 0.9 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
29 Now we just have the power to find so let us use the equation P=IV. R 1 R 2 R 3 Total V=IR 26 V 4 V 4 V 30 V I=V/R 1.3 A 0.4 A 0.9 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV
30 Therefore our chart should be filled out as below: R 1 R 2 R 3 Total V=IR 26 V 4 V 4 V 30 V I=V/R 1.3 A 0.4 A 0.9 A 1.3 A R=V/I 20 Ω 10 Ω 5 Ω 23.3 Ω P=IV 33.8 W 1.6 W 3.6 W 39 W
31 Pay special attention to the total power. R 1 R 2 R 3 Total P=IV 33.8 W 1.6 W 3.6 W 39 W The reason why is because P T = P 1 + P 2 + P 3. Power is a great check to see if you did everything correctly. It DOES NOT MATTER if the circuit is in series, parallel, or any type of combination, the sum of the powers should add up to the total power. If P T = P 1 + P 2 + P 3 and P T = I T V T give the same result then you can be certain that you have done everything correctly.
32 Sample Problem 2
33 Sample Problem 2: Use the table method to determine the voltage, current, and resistance of each resistor.
34 Sample Problem 2: What do we notice about this circuit?
35 R 1 and R 2 are in series. We also see that that the total of R 1 and R 2 are in parallel with R 3.
36 Let s combine R 1 and R 2 by adding them together since they are in series. R 1,2 = R 1 + R 2 = 15Ω + 10 Ω = 25 Ω
37 Now we see that R 1,2 is in parallel with R 3. Now we have to find our total resistance.
38 R T = R T = 1 1 R 1,2 + 1 R3 1 1Τ 25 Ω + 1 Τ5 Ω R T = Ω R T = 4.17 Ω
39 Now let us fill out our table. R 1 R 2 R 3 Total V=IR 50 V I=V/R R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
40 Is there anything we can solve for now? R 1 R 2 R 3 Total V=IR 50 V I=V/R R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
41 Is there anything we can solve for now? I T = I T = V T RT 50 V 4.17 Ω I T = 12.0 A V=IR I=V/R R=V/I P=IV Total 50 V 4.17 Ω
42 Now our table looks like below. So what next? R 1 R 2 R 3 Total V=IR 50 V I=V/R 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
43 Well we know that the voltage across the resistor R 1,2 and R 3 will be the same as the battery voltage since they are in parallel with the battery (and the current does not go across another resistor before dividing between the two pathways). Therefore, V 1,2 = 50 V V 3 = 50 V
44 NOTE: Since the pathway of V 1,2 actually has two resistors which are in series on it than that means the voltage is split between the two resistors. In equation form: V 1 + V 2 = 50 V.
45 So, we don t actually know the voltage across R 1 or R 2 yet except that they add up to 50 V. V=IR I=V/R R 1 R 2 R 3 Total 50 V 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
46 However, we do know the voltage across R 3 is V 3 = 50 V. R 1 R 2 R 3 Total V=IR 50 V 50 V I=V/R 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
47 This allows us to find I 3 = 50 VΤ 5 Ω = 10 A. R 1 R 2 R 3 Total V=IR 50 V 50 V I=V/R 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
48 Does I 3 = 10 A make sense? R 1 R 2 R 3 Total V=IR 50 V 50 V I=V/R 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
49 Absolutely because current wants to take the path of least resistance. R 1 R 2 R 3 Total V=IR 50 V 50 V I=V/R 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
50 Are we able to determine the current going through the R 1,2 pathway? When objects are in parallel than we know that we can apply the equation: I T = I 1,2 + I 3 And in our case we have: 12 A = I 1, A I 1,2 = 12 A 10 A = 2 A
51 We also know that R 1 & R 2 are in series so what does that mean? They share the same current.
52 Since they share the same current, then that means: I 1 = 2 A I 2 = 2 A
53 So let us continue filling out our table. R 1 R 2 R 3 Total V=IR 50 V 50 V I=V/R 2 A 2 A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
54 We are homeward bound, lets go find our voltage across R 1 & R 2 i.e. V 1 and V 2. R 1 R 2 R 3 Total V=IR 50 V 50 V I=V/R 2 A 2A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
55 V 1 = I 1 R 1 = 2 A 15 Ω = 30 V V 2 = I 2 R 2 = 2 A 10 Ω = 20 V R 1 R 2 R 3 Total V=IR 28.5 V 19 V 50 V 50 V I=V/R 2 A 2 A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
56 Does V 1 and V 2 add up to 50 V? If so then your answer is correct. R 1 R 2 R 3 Total V=IR 30 V 20 V 50 V 50 V I=V/R 2 A 2A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV
57 Let s find our powers now using P=IV. R 1 R 2 R 3 Total V=IR 30 V 20 V 50 V 50 V I=V/R 2 A 2A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV 60 W 40 W 500 W 600 W
58 Does P 1 + P 2 + P 3 = 600 W? R 1 R 2 R 3 Total V=IR 30 V 20 V 50 V 50 V I=V/R 2 A 2A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV 60 W 40 W 500 W 600 W
59 If so then that means you have done everything correctly. R 1 R 2 R 3 Total V=IR 30 V 20 V 50 V 50 V I=V/R 2 A 2A 10 A 12 A R=V/I 15 Ω 10 Ω 5 Ω 4.17 Ω P=IV 60 W 40 W 500 W 600 W
60 Exit Ticket
61 Complete the table to solve the circuit below.
62 Table will look like below. R 1 R 2 R 3 R 4 R 5 R 6 Total V=IR I=V/R R=V/I P=IV
63 EXAM EXTRA CREDIT
64 EXTRA CREDIT (15 Points): The current in resistance 6 is i 6 = 1.40 A and the resistances are R 1 = R 2 = R 3 = 2.00 Ω, R 4 = 16.0 Ω, R 5 = 8.00 Ω, and R 6 = 4.00 Ω. What is the emf of the ideal battery?
65 EXTRA CREDIT (15 Points): Determine current I 1 and I 2 in the circuit below:
Bell Ringer: Define to the best of your ability the definition of: Current Voltage Resistance
Bell Ringer: Define to the best of your ability the definition of: Current Voltage Resistance Explain the behavior of the current and the voltage in a Series Circuit. Explain the behavior of the current
Series and Parallel Circuits. Series Connection
Series and Parallel Circuits When devices are connected in an electric circuits, they can be connected in series or in parallel with other devices. A Series Connection When devices are series, any current
Unit 8 Combination Circuits
Unit 8 Combination Circuits Objectives: Define a combination circuit. List the rules for parallel circuits. List the rules for series circuits. Solve for combination circuit values. Characteristics There
AP Physics - Problem Drill 14: Electric Circuits
AP Physics - Problem Drill 14: Electric Circuits No. 1 of 10 1. Identify the four electric circuit symbols. (A) 1. AC power 2. Battery 3. Light Bulb 4. Resistor (B) 1. Ammeter 2. Resistor 3. AC Power 4.
Date Period Name. For each description on the left, write the letter of the matching item.
Date Period Name CHAPTER 23 Study Guide Series and Parallel Circuits Vocabulary Review For each description on the left, write the letter of the matching item. Section 23.1 1. a circuit in which all current
Circuits and Circuit Elements
Circuits and Circuit Elements Schematic Diagrams A diagram that depicts the construction of an electrical apparatus is called a schematic diagram These diagrams use symbols to represent the bulb, battery,
Strand G Unit 3: Electrical Circuits. Introduction. Learning Objectives. Introduction. Key Facts and Principles.
Learning Objectives At the end of this unit you should be able to; Represent an electrical circuit using a circuit diagram. Correctly identify common components in a circuit diagram. Calculate current,
Unit 3. Electrical Circuits
Strand G. Electricity Unit 3. Electrical Circuits Contents Page Representing Direct Current Circuits 2 Rules for Series Circuits 5 Rules for Parallel Circuits 9 Circuit Calculations 14 G.3.1. Representing
Closed circuit complete path for electrons follow. Open circuit no charge flow and no current.
Section 1 Schematic Diagrams and Circuits Electric Circuits, continued Closed circuit complete path for electrons follow. Open circuit no charge flow and no current. short circuit closed circuit, no load.
PHYS 102 Quiz Problems Chapter 27 : Circuits Dr. M. F. Al-Kuhaili
PHYS 102 Quiz Problems Chapter 27 : Circuits Dr. M. F. Al-Kuhaili 1. (TERM 002) (a) Calculate the current through each resistor, assuming that the batteries are ideal. (b) Calculate the potential difference
18-3 Circuit Analogies, and Kirchoff s Rules
18-3 Circuit Analogies, and Kirchoff s Rules Analogies can help us to understand circuits, because an analogous system helps us build a model of the system we are interested in. For instance, there are
Chapter 26: Direct current circuit
Chapter 26: Direct current circuit Resistors in circuits Equivalent resistance The nature of the electric potential and current in circuit Kirchhoff s rules (for complicated circuit analysis) Resistors
Combined Series and Parallel Circuits
Combined Series and Parallel Circuits Objectives: 1. Calculate the equivalent resistance, current, and voltage of series and parallel circuits. 2. Calculate the equivalent resistance of circuits combining
Series and parallel resistor networks (Revision)
Series and parallel resistor networks (Revision) In Grade 10 and Grade 11 you learnt about electric circuits and we introduced three quantities which are fundamental to dealing with electric circuits.
Circuitry II. Name: Date: Section C D F. Mr. Alex Rawson Physics
Name: Date: Section C D F Circuitry II Mr. Alex Rawson Physics 1. Three resistors of 100, 140, and 80 are placed in a series circuit. a. Find the equivalent resistance. (Your answer should be between 0
The following symbols are used in electric circuits:
Circuit Electricity The following symbols are used in electric circuits: Four devices are commonly used in the laboratory to study Ohm s law: the battery, the voltmeter, the ammeter and a resistance. The
Circuits. Ch. 35 in your text book
Circuits Ch. 35 in your text book Objectives Students will be able to: 1) Draw schematic symbols for electrical circuit components 2) Calculate the equivalent resistance for a series circuit 3) Calculate
CHAPTER 2 PROBLEMS 12V V 2. Fig. 2.1 I 1. 9mA I 0. Fig Find the resistance of the network in Fig. 2.3 at the terminals A-B. Fig. 2.
7 CHPTER PROLEMS.1 Determine the voltages and V in the networ in Fig..1 using voltage division. 1V Ω Ω Ω Ω V Fig..1. Find the currents 1 and 0 in the circuit in Fig.. using current division. Ω Ω 1 Ω 1Ω
Chapters 35: Electric Circuits
Text: Chapter 35 Think and Explain: 1-10 Think and Solve: 1-4 Chapters 35: Electric Circuits NME: Vocabulary: ammeter, voltmeter, series, parallel, equivalent resistance, circuit, short circuit, open circuit
Electric Circuits Notes 1 Circuits
Electric Circuits Notes 1 Circuits In the last chapter we examined how static electric charges interact with one another. These fixed electrical charges are not the same as the electricity that we use
Kirchhoff s laws. Objectives. Assessment. Assessment. Assessment. Assessment 5/27/14. Apply Kirchhoff s first and second laws.
Kirchhoff s laws Objectives Apply Kirchhoff s first and second laws. Calculate the current and voltage for resistor circuits connected in parallel. Calculate the current and voltage for resistor circuits
Series and parallel resistances
Series and parallel resistances Objectives Calculate the equivalent resistance for resistors connected in both series and parallel combinations. Construct series and parallel circuits of lamps (resistors).
Chapter 23 Circuits. Chapter Goal: To understand the fundamental physical principles that govern electric circuits. Slide 23-1
Chapter 23 Circuits Chapter Goal: To understand the fundamental physical principles that govern electric circuits. Slide 23-1 Chapter 23 Preview Looking Ahead: Analyzing Circuits Practical circuits consist
ELECTRIC CIRCUIT PROBLEMS 12 AUGUST 2014
ELECTRIC CIRCUIT PROBLEMS 12 AUGUST 2014 In this lesson we: Lesson Description Discuss the application of Ohm s Law Explain the series and parallel connection of resistors Discuss the effect of internal
Experiment #4: Voltage Division, Circuit Reduction, Ladders, and Bridges
SCHOOL OF ENGINEERING AND APPLIED SCIENCE DEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING ECE 2110: CIRCUIT THEORY LABORATORY Experiment #4: Division, Circuit Reduction, Ladders, and Bridges EQUIPMENT
Physics 227: Lecture 11 Circuits, KVL, KCL, Meters
Physics 227: Lecture 11 Circuits, KVL, KCL, Meters Lecture 10 review: EMF ξ is not a voltage V, but OK for now. Physical emf source has V ab = ξ - Ir internal. Power in a circuit element is P = IV. For
Electric Circuits. Alternate Units. V volt (V) 1 V = 1 J/C V = E P /q V = W/q. Current I ampere (A) 1 A = 1 C/s V = IR I = Δq/Δt
Electric Circuits Quantity Symbol Units Charge Q,q coulomb (C) Alternate Units Formula Electric Potential V volt (V) 1 V = 1 J/C V = E P /q V = W/q Work, energy W, E P joule (J) W = qv E P = qv Current
Mixed Series & Parallel Circuits
Add Important Mixed Series & arallel Circuits age: 477 Mixed Series & arallel Circuits NGSS Standards: N/A MA Curriculum Frameworks (006): 5. A hysics 1 Learning Objectives: 5.B.9.1, 5.B.9., 5.B.9., 5.C..1,
Lesson 21: If-Then Moves with Integer Number Cards
Student Outcomes Students understand that if a number sentence is true and we make any of the following changes to the number sentence, the resulting number sentence will be true: i. Adding the same number
Electric Circuits. Physics 6 th Six Weeks
Electric Circuits Physics 6 th Six Weeks Electric Circuits (a review) A circuit is a path through which electricity can flow Electric Circuits always contain 3 things: a voltage source, a conductor (usually
R V I P. i 1 = i 2 = I total. Kirchoff s Laws and Their Use for Circuit Analysis. Equations. Kirchoff s Laws. V=IR i
Kirchoff s Laws and Their Use for Circuit Analysis Equations s i V=I i P=IV p i i Kirchoff s Laws Loop Law The total potential change around a closed circuit equals zero. Current Law for a Point For an
PhysicsAndMathsTutor.com 1
PhysicsAndMathsTutor.com 1 1. The figure below shows a circuit containing a battery of e.m.f. 12 V, two resistors, a light-dependent resistor (LDR), an ammeter and a switch S. The battery has negligible
Ohm s and Kirchhoff s Circuit Laws. Abstract. Introduction and Theory. EE 101 Spring 2006 Date: Lab Section #: Lab #2
EE 101 Spring 2006 Date: Lab Section #: Lab #2 Name: Ohm s and Kirchhoff s Circuit Laws Abstract Rev. 20051222JPB Partner: Electrical circuits can be described with mathematical expressions. In fact, it
PH213 Chapter 26 solutions
PH213 Chapter 26 solutions 26.6. IDENTIFY: The potential drop is the same across the resistors in parallel, and the current into the parallel combination is the same as the current through the 45.0-Ω resistor.
Ohm's Law and DC Circuits
Physics Lab II Ohm s Law Name: Partner: Partner: Partner: Ohm's Law and DC Circuits EQUIPMENT NEEDED: Circuits Experiment Board Two Dcell Batteries Wire leads Multimeter 100, 330, 560, 1k, 10k, 100k, 220k
Series and Parallel DC Circuits
Series and Parallel DC Circuits asic Circuits n electric circuit is closed loop of conductive material (metal wire) that connects several circuit elements together (batteries, resistors, capacitors, etc.)
Series Circuit. Addison Danny Chris Luis
Series Circuit Addison Danny Chris Luis Series A circuit is in series whenever the current (flow of charge) is in sequence An example of this could be a person holding a screwdriver. The charge from the
Series Circuit: Electric Circuits
/0/ Electric Circuits Do Light Bulb Demo Electric Circuits here are two different types of electrical circuits. Series Parallel Series Circuit: Circuit in which a current flows through each component,
Resistors in Series or in Parallel
Resistors in Series or in Parallel Key Terms series parallel Resistors in Series In a circuit that consists of a single bulb and a battery, the potential difference across the bulb equals the terminal
Electric Circuits I. Simple Resistive Circuit. Dr. Firas Obeidat
Electric Circuits I Simple Resistive Circuit Dr. Firas Obeidat 1 Resistors in Series The equivalent resistance of any number of resistors connected in series is the sum of the individual resistances. It
Analog Electronics Computer and Electronics Engineering
Analog Electronics Computer and Electronics Engineering Roger Sash Herb Detloff Alisa Gilmore Analog Electronics Objectives: The objectives of this module are to: # Become familiar with basic electrical
Lecture Week 5. Voltage Divider Method Equivalent Circuits Review Lab Report Template and Rubric Workshop
Lecture Week 5 Voltage Divider Method Equivalent Circuits Review Lab Report Template and Rubric Workshop Voltage Divider Method The voltage divider is a method/tool that can be used to: Design voltage
ELECTRIC CIRCUITS PREVIEW QUICK REFERENCE. Important Terms
ELECTRC CRCUTS PREEW Conventional current is the flow of positive charges though a closed circuit. The current through a resistance and the voltage which produces it are related by Ohm s law. Power is
Designing Information Devices and Systems I Spring 2019 Lecture Notes Note Introduction to Electrical Circuit Analysis
EECS 16A Designing Information Devices and Systems I Spring 2019 Lecture Notes Note 11 11.1 Introduction to Electrical Circuit Analysis Our ultimate goal is to design systems that solve people s problems.
Lesson 5: Understanding Subtraction of Integers and Other Rational Numbers
\ Lesson 5: Understanding Subtraction of Integers and Other Rational Numbers Student Outcomes Students justify the rule for subtraction: Subtracting a number is the same as adding its opposite. Students
PHY 132 Summer 2000 LAB 9: LRC Circuit (Phases) 1
PHY 132 Summer 2000 LAB 9: LRC Circuit (Phases) 1 Introduction In this lab we will measure the phases (voltage vs current) for each component in a series LRC circuit. Theory L C V_in R Fig. 1 Generic series
Electric Circuits. Have you checked out current events today?
Electric Circuits Have you checked out current events today? Circuit Symbolism We can simplify this circuit by using symbols All circuits have an energy source and a load, with wires completing the loop
I = q/ t units are C/s = A (ampere)
Physics I - Notes Ch. 19-20 Current, Resistance, and Electric Circuits Electromotive force (emf = ε = V; units are volts) charge pump ; source that maintains the potential difference (voltage) in a closed
Introduction to Computers and Engineering Problem Solving Spring 2012 Problem Set 10: Electrical Circuits Due: 12 noon, Friday May 11, 2012
Introduction to Computers and Engineering Problem Solving Spring 2012 Problem Set 10: Electrical Circuits Due: 12 noon, Friday May 11, 2012 I. Problem Statement Figure 1. Electric circuit The electric
Chapter 28. Direct Current Circuits
Chapter 28 Direct Current Circuits Outline 28.1 Electromotive Force 28.2 Resistors in Series and Parallel 28.3 Kirchhoff s Rules 28.1 Electromotive Force (emf) Because the potential difference at the battery
Level 3 Physics, 2017
91526 915260 3SUPERVISOR S Level 3 Physics, 2017 91526 Demonstrate understanding of electrical systems 2.00 p.m. Monday 20 November 2017 Credits: Six Achievement Achievement with Merit Achievement with
Electromagnetism Unit- Current Sub-Unit
4.2.1 Electrical Current Definitions current unit: or requires: Example #3 A wire carries a current of 50 amperes. How much charge flows through the wire in 10 seconds? How many electrons pass through
Resistance Measurements (Measure all of your resistors, since even those that are labeled the same can be at least a little different)
Resistors We begin by learning how to read the values of resistors and to measure the values using a digital multimeter (DMM). Resistors are the most common and simplest electrical component. In an electrical
ENGR-4300 Fall 2006 Project 3 Project 3 Build a 555-Timer
ENGR-43 Fall 26 Project 3 Project 3 Build a 555-Timer For this project, each team, (do this as team of 4,) will simulate and build an astable multivibrator. However, instead of using the 555 timer chip,
Parallel Circuit. Cory, Kinsey, Alexis, Tori, Sophie
Parallel Circuit Cory, Kinsey, Alexis, Tori, Sophie Basic Definitions Resistors: Limits the flow of a charge in the circuit (measure resistance) - R total =Σ of all resistances Voltage Drop: Loss of electrical
A battery transforms chemical energy into electrical energy. Chemical reactions within the cell create a potential difference between the terminals
D.C Electricity Volta discovered that electricity could be created if dissimilar metals were connected by a conductive solution called an electrolyte. This is a simple electric cell. The Electric Battery
Lecture # 3 Circuit Configurations
CPEN 206 Linear Circuits Lecture # 3 Circuit Configurations Dr. Godfrey A. Mills Email: gmills@ug.edu.gh Phone: 0269073163 February 15, 2016 Course TA David S. Tamakloe CPEN 206 Lecture 3 2015_2016 1 Circuit
Physics 25 Chapters Dr. Alward
Physics 25 Chapters 19-20 Dr. Alward Electric Circuits Batteries store chemical energy. When the battery is used to operate an electrical device, such as a lightbulb, the chemical energy stored in the
ECE 202 (Talavage) Exam #3
ECE 202 (Talavage) Exam #3 23 November 2015 Name: INSTRUCTIONS This is a closed book, closed notes exam. The exam consists of 8 thematic problems (19 parts) worth a total of 100 points. No computers, cell
EXPERIMENT 4: RC, RL and RD CIRCUITs
EXPERIMENT 4: RC, RL and RD CIRCUITs Equipment List An assortment of resistor, one each of (330, 1k,1.5k, 10k,100k,1000k) Function Generator Oscilloscope 0.F Ceramic Capacitor 100H Inductor LED and 1N4001
Electronics I. Midterm #1
The University of Toledo s6ms_elct7.fm - Electronics I Midterm # Problems Points. 4 2. 5 3. 6 Total 5 Was the exam fair? yes no The University of Toledo s6ms_elct7.fm - 2 Problem 4 points For full credit,
Fig [5]
![Fig [5]](/thumbs/82/85456687.jpg "Fig [5]")
1 (a) Fig. 4.1 shows the I-V characteristic of a light-emitting diode (LED). 40 I / 10 3 A 30 20 10 0 1.0 1.5 2.0 V / V Fig. 4.1 (i) In Describe the significant features of the graph in terms of current,
Standard Grade Physics
Standard Grade Physics North Berwick High School Physics Department UNIT 2 Homework Sheets Working at Home TO THE PUPIL Each day you have physics at school, you should set aside time for work at home.
CHAPTER 7. Response of First-Order RL and RC Circuits
CHAPTER 7 Response of First-Order RL and RC Circuits RL and RC Circuits RL (resistor inductor) and RC (resistor-capacitor) circuits. Figure 7.1 The two forms of the circuits for natural response. (a) RL
Electric Currents 2 D V. (1)
Name: Date: Electric Currents 2. A battery is connected in series with a resistor R. The battery transfers 2 000 C of charge completely round the circuit. During this process, 2 500 J of energy is dissipated
Lab 11: Circuits. Figure 1: A hydroelectric dam system.
Description Lab 11: Circuits In this lab, you will study voltage, current, and resistance. You will learn the basics of designing circuits and you will explore how to find the total resistance of a circuit
Validation of Push Pull Current
Montana Tech Library Digital Commons @ Montana Tech Proceedings of the Annual Montana Tech Electrical and General Engineering Symposium Student Scholarship 2016 Validation of Push Pull Current Randy Ford
Filter Design, Active Filters & Review. EGR 220, Chapter 14.7, December 14, 2017
Filter Design, Active Filters & Review EGR 220, Chapter 14.7, 14.11 December 14, 2017 Overview ² Passive filters (no op amps) ² Design examples ² Active filters (use op amps) ² Course review 2 Example:
D V (Total 1 mark)
1. One electronvolt is equal to A. 1.6 10 19 C. B. 1.6 10 19 J. C. 1.6 10 19 V. D. 1.6 10 19 W. 2. A battery of internal resistance 2 Ω is connected to an external resistance of 10 Ω. The current is 0.5
Solution: Based on the slope of q(t): 20 A for 0 t 1 s dt = 0 for 3 t 4 s. 20 A for 4 t 5 s 0 for t 5 s 20 C. t (s) 20 C. i (A) Fig. P1.
Problem 1.24 The plot in Fig. P1.24 displays the cumulative charge q(t) that has entered a certain device up to time t. Sketch a plot of the corresponding current i(t). q 20 C 0 1 2 3 4 5 t (s) 20 C Figure
Series and Parallel Circuits Basics 1
1 Name: Symbols for diagrams Directions: 1. Log on to your computer 2. Go to the following website: http://phet.colorado.edu/en/simulation/-construction-kit-dc Click the button that says Play with sims
electronics fundamentals
electronics fundamentals circuits, devices, and applications THOMAS L. FLOYD DAVID M. BUCHLA chapter 6 Identifying series-parallel relationships Most practical circuits have combinations of series and
(a) (i) Is the transformer in the diagram being used as a step-up transformer or as a step-down transformer? ) in the box next to your answer. ...
Q1.The diagram shows a transformer. (a) (i) Is the transformer in the diagram being used as a step-up transformer or as a step-down transformer? Put a tick ( ) in the box next to your answer. a step-up
Figure 1. (a) The wire in an unused probe has a resistance of Ω and a length of 0.50 m. Calculate the diameter of the wire.
A wire probe is used to measure the rate of corrosion in a pipe carrying a corrosive liquid. The probe is made from the same metal as the pipe. Figure shows the probe. The rate of corrosion of the wire
The equation which links current, potential difference and resistance is:
Q1.An electrical circuit is shown in the figure below. (a) The current in the circuit is direct current. What is meant by direct current? Tick one box. Current that continuously changes direction. Current
Transformers. Question Paper. Save My Exams! The Home of Revision. Subject Physics (4403) Exam Board. Keeping Things Moving. Page 1.
Transformers Question Paper Level IGCSE Subject Physics (4403) Exam Board AQA Unit P3 Topic Keeping Things Moving Sub-Topic Transformers Booklet Question Paper Time Allowed: 58 minutes Score: /58 Percentage:
Refer to your text book (page 349 to 352) (1) Draw a circuit diagram to represent the wiring in a typical parallel circuit.
SERIES and PARALLEL CIRCUITS Refer to your text book (page 349 to 352) (1) Draw a circuit diagram to represent the wiring in a typical parallel circuit. (2) What are some of the advantages of using parallel
In this section you will learn about Ohm's Law as applied to a single resistor circuit. Phillips Textbook pp including some maths on notation.
Ohms Law (these theory notes support the ppt) In this section you will learn about Ohm's Law as applied to a single resistor circuit. Phillips Textbook pp. 43-59 including some maths on notation. At the
VCE PHYSICS AOS 2 UNIT 3. Circuit Design and Application
VCE PHYSICS AOS 2 UNIT 3 Circuit Design and Application The Components design, investigate and analyse circuits for particular purposes using technical specifications related to potential difference (voltage
P2 Quick Revision Questions. P2 for AQA GCSE examination 2018 onwards
P2 Quick Revision Questions Question 1... of 50 How can an insulator become charged? Answer 1... of 50 Electrons being transferred from one material to another by friction. Question 2... of 50 Fill the
Project 3 Build a 555-Timer
Project 3 Build a 555-Timer For this project, each group will simulate and build an astable multivibrator. However, instead of using the 555 timer chip, you will have to use the devices you learned about
8866 H1 Physics J2/ D.C. Circuits
7. D.C. CIRCUITS Content Practical circuits Series and parallel arrangements Learning Outcomes Candidates should be able to: (a) (b) (c) (d) (e) recall and use appropriate circuit symbols as set out in
Air. Radar 4- Television. Radio. Electronics UNITED ELECTRONICS LABORATORIES LOUISVILLE FILL KENTUCKY OHM'S LAW ---PARALLEL C CUITS ASSIGNMENT 8B
Electronics Radio Air Television Radar 4- UNITED ELECTRONICS LABORATORIES LOUISVILLE KENTUCKY FILL REVISED 1966 Or COPYRIGHT 1956 UNITED ELECTRONICS LABORATORIES OHM'S LAW ---PARALLEL C CUITS ASSIGNMENT
Designing Information Devices and Systems I Spring 2015 Homework 6
EECS 16A Designing Information Devices and Systems I Spring 2015 Homework 6 This homework is due March 19, 2015 at 5PM. Note that unless explicitly stated otherwise, you can assume that all op-amps in
Name: Period: Date: 2. In the circuit below, n charge carriers pass the point P in a time t. Each charge carrier has charge q.
Name: Period: Date: IB-1 Practice Electrical Currents, Resistance, and Circuits Multiple Choice Questions 1. In the circuit below, which meter is not correctly connected? A 1 3 A 2 4 A. 1 B. 2 C. 3 D.
Introduction to Engineering ENGR Electrical Engineering. Dr. Coates
Introduction to Engineering ENG 1100 - Electrical Engineering Dr. Coates Branches of Electrical Engineering Circuits/Microelectronics Communications Computer Hardware and Software, Digital Logic, Microprocessor
Series and Parallel Resistors
Lab 8. Series and Parallel Resistors Goals To understand the fundamental difference between resistors connected in series and in parallel. To calculate the voltages and currents in simple circuits involving
Conceptual Physics. Chapter 23: ELECTRIC CURRENT
Conceptual Physics Chapter 23: ELECTRIC CURRENT Electric Potential Unit of measurement: volt, 1 volt 1 joule 1 coulomb Example: Twice the charge in same location has twice the electric potential energy
Q3.: When switch S is open, the ammeter in the circuit shown in Fig 2 reads 2.0 A. When S is closed, the ammeter reading: (Ans: increases)
Old Exams-Chapter 27 T081 Q1. Fig 1 shows two resistors 3.0 Ω and 1.5 Ω connected in parallel and the combination is connected in series to a 4.0 Ω resistor and a 10 V emf device. The potential difference
A battery transforms chemical energy into electrical energy. Chemical reactions within the cell create a potential difference between the terminals
D.C Electricity Volta discovered that electricity could be created if dissimilar metals were connected by a conductive solution called an electrolyte. This is a simple electric cell. The Electric Battery
charge time Electric Current and Circuits Current HEAT will flow if there is a difference in temperature
Electric Current and Circuits Electrons will flow if there is a difference in electric pressure. Electric pressure is called Potential, and is measured in Volts. If there is no difference in pressure from
Ohm s Law. 1 Object. 2 Apparatus. 3 Theory. To study resistors, Ohm s law, linear behavior, and non-linear behavior.
Ohm s Law Object To study resistors, Ohm s law, linear behavior, and non-linear behavior. pparatus esistors, power supply, meters, wires, and alligator clips. Theory resistor is a circuit element which
Configurations of Resistors
Configurations of Resistors Safety and Equipment Multimeter with probes or banana leads. Two of 50Ω and one of 100Ω resistors 5 connecting wires with double alligator clips Introduction There are two basic
21.1 Resistors in Series and Parallel
808 Chapter 21 Circuits and DC Instruments Explain why batteries in a flashlight gradually lose power and the light dims over time. Describe what happens to a graph of the voltage across a capacitor over
The Non Inverting Buffer
The Non Inverting Buffer We now spend some time investigating useful circuit elements that do not directly implement Boolean functions. The first element is the non inverting buffer. This is logically
A resistor adds resistance to a circuit. Describe what the effect of adding resistance would have on the current flowing in the circuit.
A. Current, Potential Difference and Resistance 1a A student builds a circuit. The circuit is shown in Figure 1. Label the components shown in Figure 1. (3) Figure 1 Voltmeter Power Supply Diode Resistor
Semiconductor theory predicts that the current through a diode is given by
3 DIODES 3 Diodes A diode is perhaps the simplest non-linear circuit element. To first order, it acts as a one-way valve. It is important, however, for a wide variety of applications, and will also form
EXPERIMENT 3 Half-Wave and Full-Wave Rectification
Name & Surname: ID: Date: EXPERIMENT 3 Half-Wave and Full-Wave Rectification Objective To calculate, compare, draw, and measure the DC output voltages of half-wave and full-wave rectifier circuits. Tools
AP Physics 1 Multiple Choice Questions - Chapter 12
1 If a current of 125 ma exists in a metal wire, how many electrons flow past a given cross section of the wire in 10 minutes? a 6.25 x 10 21 electrons b 3.98 x 10 19 electrons c 5.35 x 10 22 electrons
Unit 3.C Electrical Theory, Circuits Essential Fundamentals of Electrical Theory, Circuits
Unit 3.C Electrical Theory, Circuits Essential Fundamentals of Electrical Theory, Circuits Early Booklet E.C.: + 1 Unit 3.C Hwk. Pts.: / 36 Unit 3.C Lab Pts.: / 50 Late, Incomplete, No Work, No Units Fees?