Lecture 8 Amplifiers (Basics)

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Transcription:

Lecture 8 Amplifiers (Basics)

EE 101 Schedule Version 10-10-11 (supersedes version of 11-5-11 -- date mistake) Class Lecture Date Topic Reading Ahead Homework Quiz 1 1 9-23-11 Introduction Review Math 2 2 9-26-11 Fundamentals of Electrical Engineering A & S Ch 1 Pre-Req 3 3 9-28-11 Circuit Laws, Voltage & Current Dividers A & S Ch 2 4 4 9-30-11 Node/Loop Analysis A& S Ch 3 Hmwk 1 Due 5 5 10-3-11 Node/Loop Analysis 1 6 6 10-5-11 Thévenin Equivalent Circuits A & S Ch 4 7 7 10-7-11 Norton Equivalent Circuits Hmwk 2 Due 8 8 10-10-11 Amplifiers A & S Ch 5 9 10-12-11 Review for Midterm 1 10 10-14-11 Midterm 1 11 9 10-17-11 Op Amps Hmwk 3 Due 2 12 10 10-19-11 Op-Amp Circuits 13 11 10-21-11 Op-Amp Circuits Hmwk 4 Due 14 12 10-24-11 Inductance and Capacitance A & S Ch 6 3 15 13 10-26-11 First Order Transient Response A & S Ch 7 16 14 10-28-11 RC/RL Circuits, Time Dependent Op Amp Circuits Hmwk 5 Due 17 15 10-31-11 Second Order Transient Response 18 11-2-11 Review for Midterm 2 Hmwk 6 Due 4 19 11-4-11 Midterm 2 20 16 11-7-11 Sinusoidal Signals, Complex Numbers, Phasors 21 17 11-9-11 Phasor Circuits Hmwk 7 Due 11-11-11 Veteran s Day 22 18 11-14-11 AC Power, Thevenin 23 19 11-16-11 Fourier Analysis, Low Pass Filters, Decibels 24 20 11-18-11 Bode Plot, High Pass Filter, Series Resonance Hmwk 8 Due 5 24 21 11-21-11 High Pass Filters, 2nd Order Filters, Active Filters, Resonances 25 22 11-23-11 Magnetic Circuits, Materials Hmwk 9 Due 11-25-11 Thanksgiving Day 26 23 11-28-11 Mutual Inductance & Transformers 27 24 11-30-11 TBD Hmwk 10 Due 6 12-2-11 Review for Final at normal class time and place Final Exam Thursday, December 8th (noon to 3 pm)

Overall Goals 1. Use various amplifier models to calculate amplifier performance for given sources and loads. 2. Compute amplifier efficiency. 3. Understand the importance of input and output impedances of amplifiers.

Outline (Lecture 8) Basic amplifier concepts Cascaded amplifiers Power supplies and efficiency

Essence of an Amplifier

BASIC AMPLIFIER CONCEPTS Ideally, an amplifier produces an output signal with identical waveshape as the input signal, but with a larger amplitude.

Inverting and Non-inverting Amps

Inverting versus Non-inverting Amplifiers Inverting amplifiers have negative voltage gain, and the output waveform is an inverted version of the input waveform. Non-inverting amplifiers have positive voltage gain.

Voltage-Amplifier Model Input Output The input resistance R i is the equivalent resistance we see when looking into the input terminals of the amplifier. R o is the output resistance. It causes the output voltage to decrease as the load resistance becomes smaller. A voc is the open circuit voltage gain.

Current Gain

Power Gain Upper case V and I indicate Root Mean Square (RMS) values, i.e. the effective values of a fluctuating current or voltage.

Root Mean Square (RMS) Values V (t) = V m cos(ωt +ϑ) The average value of cos (ωt+ϕ) is zero. This is the squared version of the signal, and its mean value is ½. P Average = 1 T T 0 pdt = 1 T T 0 V m 2 cos 2 (ωt +ϑ) R dt = 1 R 1 T T V m 0 2 cos 2 (ωt +ϑ) = V 2 rms R For house power the 110 to 120 volts we are familiar with is the RMS value and the peak value is (110/0.707) or ~ 156 volts. Meters typically read RMS on the AC voltage scale unless noted otherwise.

Example I i Find the voltage gain, the current gain and the power gain:

Impedance Match for Max Power into Load 500Ω 25Ω 20 mv rms 2000Ω 500V i 25Ω What load resistance maximizes the power gain? From the Thevenin equivalent model we know that the maximum power delivered to a load is when the load resistance is equal to the Thevenin resistance of 25Ω. A v = V o R = A L 25 V voc = (500) i R o + R L 25 + 25 = 250 G = (A v ) 2 R i R L = (250) 2 2000 25 = 5x106

CASCADED AMPLIFIERS

Example 11.2 Find the voltage gain for each stage and for the overall cascade connection:

Simplified Models for Cascaded Amplifier Stages First, determine the voltage gain of the first stage accounting for loading by the second stage. The overall voltage gain is the product of the gains of the separate stages. The input impedance is that of the first stage, and the output impedance is that of the last stage.

Input resistance and output resistance of the cascade:

Simplified Model A voc =1.5x10 4 R i =1MΩ R o =100Ω But how do we find this?

Finding the combined open circuit voltage gain A voc2 A v1 = A voc1 R i2 1500 = 200 R i2 + R o1 1500 + 500 =150 (same as before) A v2 = v o2 v i2 = 100v i2 v i2 = A voc 2 A voc = A v1 A v2 = (150)(100) =1.5x10 4 =100 ( for open output circuit) ( for combination)

Heat P o >P i The additional power comes from the power supply. The efficiency is given by:

Find the input power, output power, supply power and the power dissipated in the amplifier. Also find the efficiency of the amplifier.

Input power: Output power: Supply power