GCE A level 1145/01 ELECTRONICS ET5

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Surname Centre Number Candidate Number Other Names 2 GCE A level 1145/01 ELECTRONICS ET5 S16-1145-01 A.M. FRIDAY, 17 June 2016 1 hour 30 minutes For s use ADDITIONAL MATERIALS In addition to this examination paper, you will need a calculator. Question Maximum Mark 1. 14 2. 8 3. 6 4. 8 5. 5 6. 9 7. 9 8. 11 Total 70 Mark Awarded 1145 010001 INSTRUCTIONS TO CANDIDATES Use black ink or black ball-point pen. Write your name, centre number and candidate number in the spaces at the top of this page. Answer all questions. Write your answers in the spaces provided in this booklet. INFORMATION FOR CANDIDATES The total number of marks available for this paper is 70. The number of marks is given in brackets at the end of each question or part-question. You are reminded of the necessity for good English and orderly presentation in your answers. You are reminded to show all working. Credit is given for correct working even when the final answer given is incorrect. SJJ*(S16-1145-01)

2 Preferred Values for resistors INFORMATION FOR THE USE OF CANDIDATES The figures shown below and their decade multiples and sub-multiples are the E24 series of preferred values. 10, 11, 12, 13, 15, 16, 18, 20, 22, 24, 27, 30, 33, 36, 39, 43, 47, 51, 56, 62, 68, 75, 82, 91. Standard Multipliers Prefix Multiplier Prefix Multiplier T 10 12 G 10 9 M 10 6 k 10 3 m 10 3 μ 10 6 n 10 9 p 10 12 Alternating Voltages Silicon Diode V o = V rms V F 0.7 V 2 R F R IN RF Operational amplifier G = Inverting amplifier G = 1 + R 1 Non-inverting amplifier V OUT = V DIFF V V OUT = R F R 1 1 R R F 1 V2 V3 + + R R 2 3 Difference amplifier Summing amplifier Emitter follower R V L V Z 1 + R F 1 V OUT = V IN 0.7 V Stabilised power supply 1 Filters f b = Break frequency for high pass 2 RC and low pass filters 1 X C = 2 fc Thyristor phase control φ = tan 1 R R tan φ = X C i/p voltage range Signal conversion resolution = ADC X C 2 Capacitive reactance V Power amplifier P MAX = where V S is the rail-to-rail 8R S L voltage 2 n

3 PIC Information The PIC programs include equate statements that define the following labels: Label Description PORTA input / output port A PORTB input / output port B TRISA the control register for port A TRISB the control register for port B STATUS the status register INTCON the interrupt control register W the working register (= h 0 ) F the file register (= h 1 ) RP0 the register page selection bit 0 Z the zero flag status bit GIE the global interrupt controller bit INTE the external interrupt enable bit Pinout for 16F84 PIC IC: List of commands: RA2 RA3 RA4 MCLR VSS RB0/INT RB1 RB2 RB3 16F84 RA1 RA0 CLK IN CLK OUT VDD RB7 RB6 RB5 RB4 1145 010003 Mnemonic bcf bsf btfss call clrf goto movf movlw movwf retfie Operands f, b f, b f, b k f k f, d k f Description Clear bit b of file f Set bit b of file f Test bit b of file f, skip next instruction if bit is set Call subroutine k Clear file f Branch to label k Move file f (to itself if d = 1, or to working register if d = 0) Move literal k to working register Move working register to file f Return from interrupt service routine and set global interrupt enable bit GIE Comparison of TASM and MPASM languages: Number system notation Version Opcode Notation Structure of the INTCON register Decimal Hex Binary TASM 153 $2B %10010110.equ.org.end label: MPASM d'153' h'2b' or 0x2B b'10010110' equ org end label Bit 7 Bit 6 Bit 5 Bit 4 Bit 3 Bit 2 Bit 1 Bit 0 GIE EEIE TOIE INTE RBIE TOIF INTF RBIF Structure of the STATUS register Bit 7 Bit 6 Bit 5 Bit 4 Bit 3 Bit 2 Bit 1 Bit 0 IRP RP1 RP0 TO PD Z DC C Turn over.

4 Answer all questions. 1. The main sequence for a sequence generator is shown in the following incomplete state diagram. S 0 111 S 4 011 S 1 100 S 3 001 S 2 101 (a) Use this information to complete the truth table for this sequence generator. (The unused states have already been entered. There are no stuck states in this system.) [3] Current Outputs Next Outputs State C B A D C D B D A 0 1 2 3 4 5 0 0 0 1 1 1 6 0 1 0 1 1 1 7 1 1 0 1 0 0

5 (b) Complete the state diagram opposite by adding the unused states. [1] (c) What is meant by the term unused state? [1] (d) What is meant by the term stuck state? [1] (e) (i) Determine the simplest Boolean expressions for the inputs D B and D C in terms of the outputs C, B and A. [3] D B =...... D C =...... 1145 010005 (ii) The Boolean expression for D A is: D A = B.C. Complete the circuit diagram by adding appropriate logic gates and connections. [5] (Extra credit will be given for using the smallest number of gates possible.) C B A D C Q D B Q D A Q Q Q Q Clock input Turn over.

6 2. (a) Complete the circuit diagram for an active bass cut filter. [3] Input Output 0 V (b) Here is the circuit diagram for a different type of active filter. C = 16 nf 120 kω Input 10 kω Output 0 V

7 (i) Calculate the break frequency of this filter. [2] (ii) Calculate the low frequency voltage gain of this filter. [1] (c) The graph shows the characteristics of another active filter. Voltage gain 100 50 1145 010007 10 5 1 10 50 100 500 1000 5000 10 000 Frequency / Hz (i) What type of filter does the graph represent? [1] (ii) What is the break frequency for this filter? [1] Turn over.

8 3. (a) The circuit diagram for a two-bit flash ADC is shown below. The binary output increases uniformly as V IN increases. V REF = +0.4 V Y 100 kω 100 kω B 100 kω X Priority Encoder Binary Output A 100 kω 0 V Analogue input V IN (i) What is the voltage at input X? [1] (ii) A light sensing unit connected to the analogue input produces an output voltage of 0.25 V. What binary output is produced by the ADC? [1] (iii) What is the smallest value of V IN that causes output Y to go to logic 1? [1]

(b) 9 A different flash ADC has an input voltage range of 1 V and a four-bit output. (i) Calculate the resolution of the new ADC. [1] (ii) What reference voltage V REF will be needed? [1] (iii) How many resistors are needed in the resistor chain? [1] 1145 010009 Turn over.

10 4. A microcontroller system controls security in a bank. As part of this, it monitors the bank vault door using a magnetic switch. When the door is opened without authorisation, an interrupt service routine is activated. A buzzer sounds until a security guard cancels it by pressing a reset switch. The system is set up as follows: the buzzer is connected to Port A bit 2; the reset switch is connected to Port A bit 0; other input and output devices are connected to other bits of the microcontroller. (a) Which one of the following binary numbers should be loaded into register TRISA to configure Port A appropriately? [1] A. 11100 B. 11000 C. 11010 D. 00011 E. 00111 Answer... (b) Complete the following code to configure the INTCON register to enable an external interrupt on Port B bit 0, while disabling all unused interrupt sources. [2] movlw b... movwf INTCON (c) The Interrupt Service Routine is outlined below, including line numbers. It includes a subroutine called tensec, which causes a ten second delay. Complete lines 220 to 224, using the comments and the commands given in the Information Sheet. [5] 220 alarm......; store contents of W in register called protect ; 221......; output logic 1 to switch on buzzer; 222......; call ten second delay subroutine; 223......; test reset switch ignore next instruction if pressed; 224......; jump back to line 220; 225 bcf INTCON, 1 226 movf protect,0 227 retfie

11 5. Here is part of the specification for a two-channel mixer: Channel Minimum input impedance Maximum voltage gain 1 10 kω 2 2 10 kω 1 The circuit for the mixer is based on a summing amplifier. It has a fixed resistor in the feedback circuit and a series combination of a fixed and a 250 kω variable resistor in each channel input. (a) Complete the circuit diagram for a mixer that meets this specification. Label all components with their values. [3] Channel 1 Output Channel 2 0 V (b) The mixer is tested by applying DC signals to the inputs. Channel 1 and channel 2 are both set to give maximum voltage gain. A DC signal of + 10 mv is applied to channel 1 while a DC signal of 4 mv is applied to channel 2. Calculate the output voltage, showing all working. [2] Turn over.

12 6. A temperature control system for a small furnace uses two identical thermistors. (a) This first diagram shows one of these connected in a simple voltage divider circuit. 12 V V OUT 0 V At 60 C, the thermistor has a resistance of 1 kω and the variable resistor is set to a resistance of 1.5 kω. (i) Calculate the output voltage V OUT at 60 C. [1] (ii) The power supply voltage changes to 11.6 V. What is the new output voltage at 60 C? [1]

(b) The next diagram shows both thermistors connected in a bridge circuit. 13 12 V A B V DIFF 0 V (i) Calculate the output voltage, V DIFF, when: thermistor A has a resistance of 1 kω, and its variable resistor has a resistance of 1.5 kω; thermistor B has a resistance of 1.5 kω, and its variable resistor has a resistance of 1.5 kω. [2] (ii) The power supply voltage drops to 11.6 V. What is the new value of V DIFF? [1] (c) The calculations in part (b) show that a bridge circuit is less susceptible to changes in power supply variations. Describe one other advantage. [1] Turn over.

14 (d) Draw the circuit diagram for a difference amplifier that would amplify the output, V DIFF, with a voltage gain of 100. Label all resistors with appropriate resistance values. [3] V DIFF Output 0 V

15 7. The diagram shows the incomplete circuit for a switching sub-system used to control a highpower heater. + 48 V Heater X 0 V (a) Complete the circuit diagram by adding: (i) a push-switch and a resistor to switch on the heater. Label the switch A. [1] (ii) a second push-switch, a capacitor and any other components needed to switch off the heater using capacitor commutation. Label this switch B. [3] (b) (i) What is the voltage at point X when the heater is switched on? [1] (ii) Use your answer to (b)(i), and the voltage drop across the capacitor to explain how pressing switch B turns off the heater. [3] (c) What is the advantage of using a thyristor to control the heater rather than using a relay? [1] Turn over.

16 8. The block diagram for an audio system is shown below: Microphone P Q Preamplifier Tone R Power S controls amplifier Speaker The links between sub-systems are labelled P, Q, R and S. (a) Which link(s) should be designed to maximise power transfer between sub-systems? [1] (b) The diagram shows the equivalent circuit for two sub-systems within this audio system. R 1 R 2 What is the relationship between R 1 and R 2 in order to maximise power transfer between the sub-systems? [1]

(c) 17 An emitter follower circuit is shown below. 6 V 220 kω X 220 kω 8 Ω V OUT 0 V (i) With no signal present at X, calculate V OUT. [1] (ii) With no signal present at X, calculate the power dissipation in the 8 Ω loudspeaker. [1] (iii) The AC signal shown in the graph is now applied to X. On the same axes, draw the new output signal, V OUT. [2] Voltage / V 6 4 2 0 Time 2 4 6 Turn over.

18 (d) (i) The emitter follower is replaced by a push-pull power amplifier. Complete the circuit diagram. [3] 6 V X V IN 8 Ω 0 V 0 V 6 V (ii) Calculate the maximum power dissipation in the 8 Ω loudspeaker. [1] (e) Describe one advantage of a push-pull power amplifier over an emitter follower power amplifier. [1] END OF PAPER

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