Other useful blocks. Differentiator i = CdV/dt. = -RCdV/dt or /v in. Summing amplifier weighted sum of inputs (consider currents)

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Other useful blocks Differentiator i = CdV/dt = RCdV/dt or /v in = jωrc C R + Summing amplifier weighted sum of inputs (consider currents) v 1 R 1 v 2 v 3 R 3 + R f Differential amplifier = ( /R 1 )(v 2 v 1 ) for matching need accurate component values nice feature: removes common mode signal v 1 R 1 v 2 R 1 + g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 12

Common mode Suppose two signals at differential amplifier input are v 1 & v 2 in many cases they may have a common component ie v 1 = u 1 + v cm v 2 = u 2 + v cm v cm is called the common mode, remainder is normal mode The nice feature of a differential amplifier is = G(v 2 v 1 ) = G(u 2 u 1 ) this is a very effective way of subtracting interference which affects both signals equally eg power supply ripple can't be used as universal remedy: lose dynamic range Common Mode Rejection Ratio CMRR CMRR = differential gain/common mode gain ~ 100140dB for precision opamps g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 13

Many other possibilities Not restricted to using resistors only in circuit eg gain at low f (or DC) with different value at high f v in + R 1 R C differentiator/high pass filter with gain & inversion C R 1 + g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 14

Nonideal opamp behaviour Just seen one example inputs do draw small currents input impedances are finite real amplifiers do not have infinite gain but very high values can be obtained some examples of consequences later Practical considerations easy to assume zero output for zero input may be true for ac, but not dc opamps have nulling connections, and recommended compensation to adjust often simple potentiometer (screwdriver adjustment) output impedance ideal opamp has openloop R out 0 slew rate how fast can output voltage change? applied voltages are limited certainly can t expect to exceed supply voltages! behaviour can change with temperature powered circuits need cooling! frequency response and bandwidth discuss further most parameters are clearly specified so should use manufacturer s data to select best component for application many of these are important in precision applications g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 15

Specifications & typical values Along with obvious parameters; R in, R out, CMRR, V S, bandwidth, power consumption, gain and phase shift, manufacturer's data sheets also give: Input bias current I B 0.5*(i + + i ) with v + = v = 0 ~pa na Input offset current I B i + i with v + = v = 0 ~fraction of I B Input offset voltage V OS & adjustment range NB some of these are T dependent with v + = v = 0 ~ 10µV 5mV so take care in assumptions when adjusted Input voltage range ~ ± V S 1V Slew rate (f dependent) maximum dv 0 /dt ~ V/µs Power Supply Rejection Ratio (PSRR) small changes in V S can resemble signals db or µv/v Noise voltage & current (for later) typical nulling circuit g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 16

Real opamp data OP77 g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 17

Advantages of feedback Why sacrifice gain? even if amplifier gain is defined component gain is not a reliable quantity gain in feedback circuits fixed by components can choose precision negative feedback improves performance stability, linearity, distortion 10 0 some components approaching ideal can be designed eg current sources with very high output impedance real gain depends on frequency designing for lower closed loop gain extends f range where gain is uniform up to some limit frequency dependent feedback can be used simplifies some designs Gain 10 5 10 3 10 1 10 1 10 2 10 4 f (Hz) gain = 10 to ~1MHz 10 6 positive feedback has uses eg oscillators g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 18

Opamp frequency response Reason for falling gain with frequency low pass filters in different stages formed by natural capacitances present in circuit Poles Gain 10 5 10 3 10 1 1/f gain > 1 amplifier illustrated has poles at f 1, f 2, f 3 can give stability problems if phase shift > 180 negative feedback becomes positive must ensure gain < 1 at frequency at which phase shift > 180 some opamps have this built in if not, reduce gain if feedback network introduces phase changes, then this must be included in discussion φ (deg) 10 1 50 100 150 200 250 10 0 0 10 0 g.hall@ic.ac.uk www.hep.ph.ic.ac.uk/~hallg/ 19 f 10 2 1 10 4 f 2 f 3 10 6 f (Hz) φ < 180 10 2 10 4 10 6 10 8 f (Hz)