Chapter 6 Kinetic energy and work

Similar documents
Sinusoidal Steady State Analysis

stanchion paper roll mandrel base FIGURE P3-12 ramp

c The scaffold pole EL is 8 m long. How far does it extend beyond the line JK?

EE 215A Fundamentals of Electrical Engineering Lecture Notes Resistive Circuits 10/06/04. Rich Christie

Superposition, Thevenin and Norton. Superposition

THE USE OF MATLAB AND SIMULINK AS A TOOL FOR CONTROL SYSTEM DESIGN. Rajesh Rajamani

Study Guide # Vectors in R 2 and R 3. (a) v = a, b, c = a i + b j + c k; vector addition and subtraction geometrically using parallelograms

WI1402-LR Calculus II Delft University of Technology

REVIEW, pages

Diffraction and Interference. 6.1 Diffraction. Diffraction grating. Diffraction grating. Question. Use of a diffraction grating in a spectrometer

Vector Calculus. 1 Line Integrals

CHAPTER 35 MAGNETIC FIELD DUE TO CURRENT

Using a Rotating DC Magnetic Field to Create an AC Magnetic Field

Polar Coordinates. July 30, 2014

5 October 2015 Stereo Cross-feed Network for Headphones 1 of 12 Copyright 2015 Peter H. Lehmann. All Rights Reserved.

Kirchhoff s Rules. Kirchhoff s Laws. Kirchhoff s Rules. Kirchhoff s Laws. Practice. Understanding SPH4UW. Kirchhoff s Voltage Rule (KVR):

Skyshine photon doses from 6 and 10 MV medical linear accelerators

Chapter 12 Vectors and the Geometry of Space 12.1 Three-dimensional Coordinate systems

Exercise 1-1. The Sine Wave EXERCISE OBJECTIVE DISCUSSION OUTLINE. Relationship between a rotating phasor and a sine wave DISCUSSION

A Control Strategy Based on UTT and ISCT for 3P4W UPQC

Adaptive modified backpropagation algorithm based on differential errors

1 tray of toffee 1 bar of toffee. 10 In the decimal number, 0 7, the 7 refers to 7 tenths or

Skills Practice Skills Practice for Lesson 4.1

ELECTRONICS & COMMUNICATIONS DEP. 3rd YEAR, 2010/2011 CONTROL ENGINEERING SHEET 4 PID Controller

PreCalc 11 Chapter 6 Rev Pack v1 Answer Section

(CATALYST GROUP) B"sic Electric"l Engineering

He Is The God Of Abram (BLIND SIGHT - Scene 1 - Ben, Deborah and Chorus)

Math 116 Calculus II

ECE 274 Digital Logic. Digital Design. Datapath Components Shifters, Comparators, Counters, Multipliers Digital Design

VI.C CIRCUIT BREAKERS

Adaptive Playout Adjustment Algorithm to Improve QOS for Voice Streaming over Wireless Ad-hoc Networks

University of North Carolina-Charlotte Department of Electrical and Computer Engineering ECGR 4143/5195 Electrical Machinery Fall 2009

A Musical. from Something Rotten! WAYNE KIRKPATRICK and KAREY KIRKPATRICK. Published Under License From. WAMA, Inc.

REVIEW QUESTIONS. Figure 2.63 For Review Question 2.6. Figure 2.64 For Review Question The reciprocal of resistance is:

CS 135: Computer Architecture I. Boolean Algebra. Basic Logic Gates

9.4. ; 65. A family of curves has polar equations. ; 66. The astronomer Giovanni Cassini ( ) studied the family of curves with polar equations

Guidelines for CCPR and RMO Bilateral Key Comparisons CCPR Working Group on Key Comparison CCPR-G5 October 10 th, 2014

Homework #1 due Monday at 6pm. White drop box in Student Lounge on the second floor of Cory. Tuesday labs cancelled next week

Experiment 8 Series DC Motor (II)

Contributors: Sean Holt Adam Parke Tom Turner. Solutions Manual. Edition: 25 April Editors: Adam W. Parke, Thomas B. Turner, Glen Van Brummelen

DEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING, THE UNIVERSITY OF NEW MEXICO ECE-238L:

Regular languages can be expressed as regular expressions.

Direct Current Circuits

TIME: 1 hour 30 minutes

b = and their properties: b 1 b 2 b 3 a b is perpendicular to both a and 1 b = x = x 0 + at y = y 0 + bt z = z 0 + ct ; y = y 0 )

CAL. NX15 DUO-DISPLAY QUARTZ

Experiment 3: The research of Thevenin theorem

Digital Transmission

PT7M CL/CH /NL Voltage Detector

Example. Check that the Jacobian of the transformation to spherical coordinates is

STUDY GUIDE, CALCULUS III, 2017 SPRING

Nordic - 2 Door 2 Drawer Tallboy

IDENTIFICATION OF THE PARAMETERS OF MULTI-MASS DIRECT DRIVE SYSTEM

lt s an easy-wear top, just perfect for pairing with jeans or a skirt

Experiment 3: Non-Ideal Operational Amplifiers

Wild Animals. Lesson at a Glance. Animals. Lesson Objectives. Lesson Plan. Bible Story Text. Bible Truth. Lesson 3

Section 10.2 Graphing Polar Equations

Soc 3811 Basic Social Statistics First Midterm Exam Spring 2010 ANSWERS

LECTURE 9: QUADRATIC RESIDUES AND THE LAW OF QUADRATIC RECIPROCITY

METHOD OF LOCATION USING SIGNALS OF UNKNOWN ORIGIN. Inventor: Brian L. Baskin

Algorithms for Memory Hierarchies Lecture 14

& Y Connected resistors, Light emitting diode.

ELEC353 Practice Problem Set #6

Algorithms Airline Scheduling. Airline Scheduling. Design and Analysis of Algorithms Andrei Bulatov

CONTENTS. 2 Mastering Ukulele

Unit 1: Chapter 4 Roots & Powers

MTBF PREDICTION REPORT

Model-Based Framework for Real-Time Dynamic Structural Performance Evaluation

CHAPTER 2 LITERATURE STUDY

Vocabulary Check. Section 10.8 Graphs of Polar Equations not collinear The points are collinear.

Section 17.2: Line Integrals. 1 Objectives. 2 Assignments. 3 Maple Commands. 1. Compute line integrals in IR 2 and IR Read Section 17.

ALUMINUM ELECTROLYTIC CAPACITORS

z z" z v 2 ft = 2k ft. 328 Concepts of Physics The energy dissipated in 1000 s = P * 1000 s

Safety Relay Unit. Main contacts Auxiliary contact Number of input channels Rated voltage Model Category. possible 24 VAC/VDC G9SA-501.

1. REVIEW 2. DELIVERY SET

Direct solenoid and solenoid pilot operated valves

Thank you for auditioning for KINKY BOOTS NATIONAL TOUR ROLE: PAT/TRISH/MARGE/FEMALE ENSEMBLE

Experiment 3: Non-Ideal Operational Amplifiers

MATHCOUNTS. 100 Classroom Lessons. August Prepared by

Understanding the ChordMaps2 Screen

Shunt Active Filters (SAF)

High Speed ADC Sampling Transients

A Substractive Clustering Based Fuzzy Hybrid Reference Control Design for Transient Response Improvement of PID Controller

Unit 7. Gates. Checkers / Decoders. Fundamental Digital Building Blocks: Decoders & Multiplexers CHECKERS / DECODERS

Locator Pin Indexing Pin. Wire Size Marking CAUTION NOTE TOOLING ASSISTANCE CENTER PRODUCT INFORMATION

SOLVING TRIANGLES USING THE SINE AND COSINE RULES

Compared to generators DC MOTORS. Back e.m.f. Back e.m.f. Example. Example. The construction of a d.c. motor is the same as a d.c. generator.

SERVICE MANUAL

Alternating-Current Circuits

POLYTECHNIC UNIVERSITY Electrical Engineering Department. EE SOPHOMORE LABORATORY Experiment 1 Laboratory Energy Sources

I.G.C.S.E. Solving Linear Equations. You can access the solutions from the end of each question

Differentiable functions (Sec. 14.4)

Lecture (11) Three Phase Transformers

Calculus IV Math 2443 Review for Exam 2 on Mon Oct 24, 2016 Exam 2 will cover This is only a sample. Try all the homework problems.

Protection components

ETSI TS V8.4.0 ( )

First Round Solutions Grades 4, 5, and 6

INSTITUTE OF AERONAUTICAL ENGINEERING (Autonomous) Dundigal, Hyderabad

13.1 Double Integral over Rectangle. f(x ij,y ij ) i j I <ɛ. f(x, y)da.

Translate and Classify Conic Sections

Transcription:

Chpter 6 Kc energy nd wor I. Kc energy. II. or. III. or - Kc energy theorem. IV. or done by contnt orce - Grttonl orce V. or done by rble orce. VI. Power - Sprng orce. - Generl. D-Anly 3D-Anly or-kc Energy Theorem. Energy: clr quntty octed wth tte (or condton o one or more obect. I. Kc energy Energy octed wth the tte o moton o n obect. K m (7. Unt: Joule J gm / N m II. or Energy trnerred to or rom n obect by men o orce ctng on the obect. To + rom - - Contnt orce: m + d d ( ( m m md m d m( K K d d or done by the orce Energy trner due to the orce.

- To clculte the wor done on n obect by orce durng dplcement, we ue only the orce component long the obect dplcement. The orce component perpendculr to the dplcement doe zero wor. d co ϕ d d (7.3 coφ d - Aumpton: cte, Obect prtcle-le. Unt: Joule J gm / ϕ < 9 + 8 > ϕ > 9 ϕ 9 A orce doe + when t h ector component n the me drecton the dplcement, nd when t h ector component n the oppote drecton. when t h no uch ector component. Net wor done by eerl orce Sum o wor done by nddul orce. Clculton: + + 3 + d II. or-kc Energy Theorem K K K (7.4 Chnge n the c energy o the prtcle Net wor done on the prtcle III. or done by contnt orce - Grttonl orce: d d coϕ (7.5 Rng obect: d co8º -d g trner d energy rom the obect c energy. llng obect: d co º +d g trner d energy to the obect c energy.

- Eternl ppled orce + Grttonl orce: K K K + g (7.6 Obect ttonry beore nd ter the lt: + g The ppled orce trner the me mount o energy to the obect the grttonl orce trner rom the obect. IV. or done by rble orce - Sprng orce: d (7.7 Hooe lw prng contnt meure prng tne. Unt: N/m Hooe lw D or done by prng orce: - Aumpton: Sprng mle m prng << m bloc Idel prng obey Hooe lw ectly. Contct between the bloc nd loor rctonle. Bloc prtcle-le. - Clculton: The bloc dplcement mut be dded nto mny egment o nnteml wdth,. ( cte wthn ech hort egment. 3

4 or done by n ppled orce + prng orce: d d ( I Bloc end up t. K K K + Bloc ttonry beore nd ter the dplcement: K - The wor done by the ppled orce dplcng the bloc the negte o the wor done by the prng orce. [ ] ( S d or done by generl rble orce: D-Anly (7. ( lm,,,, g g g d more ppromton better Geometrclly: or the re between the cure ( nd the -.

3D-Anly ˆ ˆ ˆ + y + z ; (, y ( y, z dr d ˆ + dy ˆ + dz ˆ d dr d + dy + dz or-kc Energy Theorem - Vrble orce ( d m d m d dt y d z m d d m d md d r ( z d d + ydy + zdz r y y z z d d d d dt d dt d m d m d m m K K K V. Power Tme rte t whch the ppled orce doe wor. - Aerge power: mount o wor done n n mount o tme t by orce. P g t (7. - Intntneou power: ntntneou tme rte o dong wor. d P dt (7.3 φ d coϕ d d P coϕ coϕ dt dt dt (7.4 Unt: tt J/ lowtt-hour h 3.6 6 J 3.6 MJ 5

54. In the gure ( below N orce ppled to 4g bloc t downwrd ngle θ the bloc moe rghtwrd through m cro rctonle loor. nd n epreon or the peed t the end o tht dtnce the bloc ntl elocty : ( nd (b m/ to the rght. (c The tuton n (b mlr n tht the bloc ntlly mong t m/ to the rght, but now the N orce drected downwrd to the let. nd n epreon or the peed o the bloc t the end o the m dtnce. d ( coθ d N N K.5m( y y K.5m (N coθ.5(4g coθ m / ( b m / K.5m (N coθ.5(4g + coθ m / J.5 (4g (m / ( c m / K.5m (Ncoθ.5(4g coθ m / J J 8. In the gure below horzontl orce o mgntude N ppled to 3g pychology boo, the boo lde dtnce o d.5m up rctonle rmp. ( Durng the dplcement, wht the wor done on the boo by, the grttonl orce on the boo nd the norml orce on the boo? (b I the boo h zero c energy t the trt o the dplcement, wht the peed t the end o the dplcement? N d y g N gy Only g, g do wor g or (7.3 N 4.7N.5m.3J co3 n 3 d ( b K K K.3J.5m.93m / 6

55. A g lunchbo ent ldng oer rctonle urce, n the pote drecton o n long the urce. Begnnng t t, tedy wnd puhe on the lunchbo n the negte drecton o, g. below. Etmte the c energy o the lunchbo t ( t, (b t5. (c How much wor doe the orce rom the wnd do on the lunch bo rom t to t5? Moton conce downwrd t( t prbol d dt d dt t.m / cte m (g(.m / (.4N( t.t t K.8m /.5(g(.8m /.4N.64J ( b t 5 K J ( c K K (5 K.64.64J ( 74. ( nd the wor done on the prtcle by the orce repreented n the grph below the prtcle moe rom to 3m. (b The cure gen by /, wth 9Nm. Clculte the wor ung ntegrton Are under cure (.5qure(.5m( N 5.75J 3 9 ( b d 9 9( 6J 3 3 73. An eletor h m o 45g nd cn crry mmum lod o 8g. I the cb mong upwrd t ull lod t 3.8m/, wht power requred o the orce mong the cb to mntn tht peed? mtotl 45g + 8g 63g + (63g(9.8m / g 6.74N P (6.74N(3.8m / P 34.6 7

A ngle orce ct on body tht moe long n -. The gure below how the elocty component eru tme or the body. or ech o the nterl AB, BC, CD, nd DE, ge the gn (plu or mnu o the wor done by the orce, or tte tht the wor zero. K K K m ( A B C D E t AB BC CD B C D > < B C A > < DE E <, > D 5. A 5g bloc dropped onto reled ertcl prng tht h prng contnt o.5n/cm. The bloc become ttched to the prng nd compree the prng cm beore momentrly toppng. hle the prng beng compreed, wht wor done on the bloc by ( the grttonl orce on t nd (b the prng orce? (c ht the peed o the bloc ut beore t ht the prng? (rcton neglgble (d I the peed t mpct doubled, wht the mmum compreon o the prng? d g g d d (.5g(9.8m / (.m. 9J ( b d.5 (5N / m(.m. 8J ( c K K.5m.5m K K.5m g +.9J.8J.5 (.5g 3.47m / ( d I ' 6.95m / Mmum prng compreo n? d '.5d ' d '.3m K.5m ' 8

6. In the gure below, cord run round two mle, rctonle pulley; cnter wth m mg hng rom one pulley; nd you eert orce on the ree end o the cord. ( ht mut be the mgntude o you re to lt the cnter t contnt peed? (b To lt the cnter by cm, how r mut you pull the ree end o the cord? Durng tht lt, wht the wor done on the cnter by (c your orce ( the cord nd (d the grttonl orce on the cnter? P T T T P Pulley : Hnd cord : cte T T 98N T 98N (b To re m.m, two egment o the cord mut be horten by tht mount. Thu, the mount o the trng pulled down t the let end :.4m ( c d (98N (.4m 3. 9J ( d g d (.m(g(9.8m / 3. 9J + g There no chnge n c energy. 9