Number Patterns - Grade 10 [CAPS] *

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OpenStax-CNX module: m38376 1 Number Patterns - Grade 10 [CAPS] * Free High School Science Texts Project Based on Number Patterns by Rory Adams Free High School Science Texts Project Mark Horner Heather Williams This work is produced by OpenStax-CNX and licensed under the Creative Commons Attribution License 30 1 Number Patterns - Grade 10 In earlier grades you saw patterns in the form of pictures and numbers In this chapter, we learn more about the mathematics of patterns Patterns are recognisable as repetitive sequences and can be found in nature, shapes, events, sets of numbers and almost everywhere you care to look For example, seeds in a sunower, snowakes, geometric designs on quilts or tiles, the number sequence 0; 4; 8; 12; 16; 11 Investigation : Patterns Can you spot any patterns in the following lists of numbers? 1 2; 4; 6; 8; 10; 2 1; 2; 4; 7; 11; 3 1; 4; 9; 16; 25; 4 5; 10; 20; 40; 80; 2 Common Number Patterns Numbers can have interesting patterns Here we list the most common patterns and how they are made Examples: 1 1; 4; 7; 10; 13; 16; 19; 22; 25; This sequence has a dierence of 3 between each number The pattern is continued by adding 3 to the last number each time * Version 13: Jun 13, 2011 9:23 pm -0500 http://cnxorg/content/m31342/14/ http://creativecommonsorg/licenses/by/30/

OpenStax-CNX module: m38376 2 2 3; 8; 13; 18; 23; 28; 33; 38; This sequence has a dierence of 5 between each number The pattern is continued by adding 5 to the last number each time 3 2; 4; 8; 16; 32; 64; 128; 256; This sequence has a factor of 2 between each number The pattern is continued by multiplying the last number by 2 each time 4 3; 9; 27; 81; 243; 729; 2187; This sequence has a factor of 3 between each number The pattern is continued by multiplying the last number by 3 each time 21 Special Sequences 211 Triangular Numbers 1; 3; 6; 10; 15; 21; 28; 36; 45; This sequence is generated from a pattern of dots which form a triangle By adding another row of dots (with one more dot in each row than in the previous row) and counting all the dots, we can nd the next number of the sequence 212 Square Numbers 1; 4; 9; 16; 25; 36; 49; 64; 81; The next number is made by squaring the number of the position in the pattern The second number is 2 squared (2 2 or 2 2 ) The seventh number is 7 squared (7 2 or 7 7 ) etc 213 Cube Numbers 1; 8; 27; 64; 125; 216; 343; 512; 729; The next number is made by cubing the number of the position in the pattern The second number is 2 cubed (2 3 or 2 2 2 ) The seventh number is 7 cubed (7 3 or 7 7 7 ) etc 214 Fibonacci Numbers 0; 1; 1; 2; 3; 5; 8; 13; 21; 34; The next number is found by adding the two numbers before it together The 2 is found by adding the two numbers in front of it (1 + 1) The 21 is found by adding the two numbers in front of it (8 + 13) The next number in the sequence above would be 55 (21 + 34) Can you gure out the next few numbers? Khan Academy video on Number Patterns - 1 This media object is a Flash object Please view or download it at <http://wwwyoutubecom/v/zj-a_9cd5jc&rel=0> Figure 1 Exercise 1: Study Table (Solution on p 8) Say you and 3 friends decide to study for Maths, and you are seated at a square table A few minutes later, 2 other friends join you and would like to sit at your table and help you study Naturally, you move another table and add it to the existing one Now 6 of you sit at the table Another 2 of your friends join your table, and you take a third table and add it to the existing tables Now 8 of you can sit comfortably

OpenStax-CNX module: m38376 3 Figure 2: Two more people can be seated for each table added Examine how the number of people sitting is related to the number of tables 3 Notation Khan Academy video on Number Patterns This media object is a Flash object Please view or download it at <http://wwwyoutubecom/v/_3bnyer5fg4&rel=0> Figure 3 The n th -term of a sequence is written as a n So for example, the 1 st -term of a sequence is a 1, the 10 th -term is a 10 A sequence does not have to follow a pattern but when it does, we can often write down a formula to calculate the n th -term, a n In the sequence 1; 4; 9; 16; 25; (3) where the sequence consists of the squares of integers, the formula for the n th -term is You can check this by looking at: a n = n 2 (3) a 1 = 1 2 = 1 a 2 = 2 2 = 4 a 3 = 3 2 = 9 a 4 = 4 2 = 16 a 5 = 5 2 = 25 Therefore, using (3), we can generate a pattern, namely squares of integers We can also dene the common dierence for a pattern (3)

OpenStax-CNX module: m38376 4 Denition 3: Common dierence The common dierence is the dierence between successive terms and is denoted by d For example, consider the sequence 10; 7; 4; 1; To nd the common dierence, we simply subtract each successive term: 7 10 = 3 4 7 = 3 1 4 = 3 (3) Exercise 2: Study Table continued (Solution on p 8) As before, you and 3 friends are studying for Maths, and you are seated at a square table A few minutes later, 2 other friends join you and add another table to the existing one Now 6 of you can sit together A short time later 2 more of your friends join your table, and you add a third table to the existing tables Now 8 of you can sit comfortably as shown: Figure 4: For each table added, two more people can be seated Find the expression for the number of people seated at n tables Then, use the general formula to determine how many people can sit around 12 tables and how many tables are needed for 20 people It is also important to note the dierence between n and a n n can be compared to a place holder, while a n is the value at the place held by n Like our Study Table example above, the rst table (Table 1) holds 4 people Thus, at place n = 1, the value of a 1 = 4 and so on: n 1 2 3 4 a n 4 6 8 10 Table 1 31 Investigation : General Formula 1 Find the general formula for the following sequences and then nd a 10, a 50 and a 100 : a 2; 5; 8; 11; 14; b 0; 4; 8; 12; 16; c 2; 1; 4; 7; 10; 2 The general term has been given for each sequence below Work out the missing terms a 0; 3; ; 15; 24 n 2 1 b 3; 2; 1; 0; ; 2 n + 4 c 11; ; 7; ; 3 13 + 2n

OpenStax-CNX module: m38376 5 32 Patterns and Conjecture Khan Academy video on Number Patterns - 2 This media object is a Flash object Please view or download it at <http://wwwyoutubecom/v/zicxrhyjs6m&rel=0> Figure 5 In mathematics, a conjecture is a mathematical statement which appears to be true, but has not been formally proven to be true A conjecture can be seen as an educated guess or an idea about a pattern A conjecture can be thought of as the mathematicians way of saying I believe that this is true, but I have no proof For example: Make a conjecture about the next number based on the pattern 2; 6; 11; 17; The numbers increase by 4, 5, and 6 Conjecture: The next number will increase by 7 So, it will be 17 + 7 or 24 Exercise 3: Number patterns (Solution on p 9) Consider the following pattern: 1 2 + 1 = 2 2 2 2 2 + 2 = 3 2 3 3 2 + 3 = 4 2 4 4 2 + 4 = 5 2 5 (5) 1 Add another two rows to the end of the pattern 2 Make a conjecture about this pattern Write your conjecture in words 3 Generalise your conjecture for this pattern (in other words, write your conjecture algebraically) 4 Prove that your conjecture is true 4 Summary There are several special sequences of numbers: Triangular numbers 1; 3; 6; 10; 15; 21; 28; 36; 45; Square numbers 1; 4; 9; 16; 25; 36; 49; 64; 81; Cube numbers 1; 8; 27; 64; 125; 216; 343; 512; 729; Fibonacci numbers 0; 1; 1; 2; 3; 5; 8; 13; 21; 34; We represent the n th -term with the notation a n We can dene the common dierence of a sequence as the dierence between successive terms We can work out a general formula for each number pattern and use that to predict what any number in the pattern will be

OpenStax-CNX module: m38376 6 5 Exercises 1 Find the n th term for: 3, 7, 11, 15, Click here for the solution 1 2 Find the general term of the following sequences: a 2; 1; 4; 7; b 11; 15; 19; 23; c sequence with a 3 = 7 and a 8 = 15 d sequence with a 4 = 8 and a 10 = 10 Click here for the solution 2 3 The seating in a section of a sports stadium can be arranged so the rst row has 15 seats, the second row has 19 seats, the third row has 23 seats and so on Calculate how many seats are in the row 25 Click here for the solution 3 4 A single square is made from 4 matchsticks Two squares in a row need 7 matchsticks and 3 squares in a row need 10 matchsticks Determine: a the rst term b the common dierence c the formula for the general term d how many matchsticks are in a row of 25 squares Figure 6 Click here for the solution 4 5 You would like to start saving some money, but because you have never tried to save money before, you have decided to start slowly At the end of the rst week you deposit R5 into your bank account Then at the end of the second week you deposit R10 into your bank account At the end of the third week you deposit R15 After how many weeks do you deposit R50 into your bank account? Click here for the solution 5 6 A horizontal line intersects a piece of string at four points and divides it into ve parts, as shown below 1 http://wwwfhsstorg/lcq 2 http://wwwfhsstorg/lcl 3 http://wwwfhsstorg/lci 4 http://wwwfhsstorg/loe 5 http://wwwfhsstorg/lco

OpenStax-CNX module: m38376 7 Figure 7 If the piece of string is intersected in this way by 19 parallel lines, each of which intersects it at four points, nd the number of parts into which the string will be divided Click here for the solution 6 6 http://wwwfhsstorg/lcc

OpenStax-CNX module: m38376 8 Solutions to Exercises in this Module Solution to Exercise (p 2) Step 1 Number of Tables, n Number of people seated 1 4 = 4 2 4 + 2 = 6 3 4 + 2 + 2 = 8 4 4 + 2 + 2 + 2 = 10 n 4 + 2 + 2 + 2 + + 2 Table 2 Step 2 We can see that for 3 tables we can seat 8 people, for 4 tables we can seat 10 people and so on We started out with 4 people and added two each time Thus, for each table added, the number of persons increased by 2 Solution to Exercise (p 4) Step 1 Number of Tables, n Number of people seated Formula 1 4 = 4 = 4 + 2 (0) 2 4 + 2 = 6 = 4 + 2 (1) 3 4 + 2 + 2 = 8 = 4 + 2 (2) 4 4 + 2 + 2 + 2 = 10 = 4 + 2 (3) n 4 + 2 + 2 + 2 + + 2 = 4 + 2 (n 1) Step 2 The number of people seated at n tables is: Table 3 a n = a 1 + d (n 1) (7) Notice how we have used d to represent the common dierence We could also have written a 2 in place of the d We also used a 1 to represent the rst term, rather than using the actual value (4) Step 3 Considering the example from the previous section, how many people can sit around say 12 tables? We are looking for a 12, that is, where n = 12: a n = a 1 + d (n 1) a 12 = 4 + 2 (12 1) = 4 + 2 (11) = 4 + 22 = 26 (7)

OpenStax-CNX module: m38376 9 Step 4 a n = a 1 + d (n 1) 20 = 4 + 2 (n 1) 20 4 = 2 (n 1) 16 2 = n 1 8 + 1 = n n = 9 Step 5 26 people can be seated at 12 tables and 9 tables are needed to seat 20 people (7) Solution to Exercise (p 5) Step 1 5 2 + 5 = 6 2 6 6 2 + 6 = 7 2 7 Step 2 Squaring a number and adding the same number gives the same result as squaring the next number and subtracting that number Step 3 We have chosen to use x here You could choose any letter to generalise the pattern (7) Step 4 x 2 + x = (x + 1) 2 (x + 1) (7) Left side : x 2 + x (7) Right side : (x + 1) 2 (x + 1) (7) Right side = x 2 + 2x + 1 x 1 = x 2 + x = Left side x 2 + x = (x + 1) 2 (x + 1) (7)