Properties of Chords

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Properties of Chords Say Thanks to the Authors Click http://www.ck12.org/saythanks (No sign in required)

To access a customizable version of this book, as well as other interactive content, visit www.ck12.org CK-12 Foundation is a non-profit organization with a mission to reduce the cost of textbook materials for the K-12 market both in the U.S. and worldwide. Using an open-content, webbased collaborative model termed the FlexBook textbook, CK-12 intends to pioneer the generation and distribution of high-quality educational content that will serve both as core text as well as provide an adaptive environment for learning, powered through the FlexBook Platform. Copyright 2015 CK-12 Foundation, www.ck12.org The names CK-12 and CK12 and associated logos and the terms FlexBook and FlexBook Platform (collectively CK-12 Marks ) are trademarks and service marks of CK-12 Foundation and are protected by federal, state, and international laws. Any form of reproduction of this book in any format or medium, in whole or in sections must include the referral attribution link http://www.ck12.org/saythanks (placed in a visible location) in addition to the following terms. Except as otherwise noted, all CK-12 Content (including CK-12 Curriculum Material) is made available to Users in accordance with the Creative Commons Attribution-Non-Commercial 3.0 Unported (CC BY-NC 3.0) License (http://creativecommons.org/ licenses/by-nc/3.0/), as amended and updated by Creative Commons from time to time (the CC License ), which is incorporated herein by this reference. Complete terms can be found at http://www.ck12.org/about/ terms-of-use. Printed: March 19, 2015

www.ck12.org Chapter 1. Properties of Chords CHAPTER 1 Properties of Chords Learning Objectives Find the lengths of chords in a circle. Discover properties of chords and arcs. Review Queue 1. Draw a chord in a circle. 2. Draw a diameter in the circle from #1. Is a diameter a chord? 3. ABC is an equilateral triangle in A. Find m BC and m BDC. 4. ABC and ADE are equilateral triangles in A. List a pair of congruent arcs and chords. Know What? To the right is the Gran Teatro Falla, in Cadiz, Andalucía, Spain. This theater was built in 1905 and hosts several plays and concerts. It is an excellent example of circles in architecture. Notice the five windows, A E. A = E and B = C = D. Each window is topped with a 240 arc. The gold chord in each circle connects the rectangular portion of the window to the circle. Which chords are congruent? How do you know? 1

www.ck12.org Recall from the first section, that a chord is a line segment whose endpoints are on a circle. A diameter is the longest chord in a circle. There are several theorems that explore the properties of chords. Congruent Chords & Congruent Arcs c c This leads to our first theorem. From #4 in the Review Queue above, we noticed that BC = DE and BC = DE. Theorem 10-3: In the same circle or congruent circles, minor arcs are congruent if and only if their corresponding chords are congruent. Notice the if and only if in the middle of the theorem. This means that Theorem 10-3 is a biconditional statement. Taking this theorem one step further, any time two central angles are congruent, the chords and arcs from the endpoints of the sides of the central angles are also congruent. c In the second picture, we have 4BAE c In both of these pictures, BE = CD and BE = CD. = 4CAD because the AC = AD = AE because they are all radii (SAS). By CPCTC, BE = CD. central angles are congruent and BA = Example 1: Use J A to answer the following. c c = 125, find mcd. a) If mbd 2

www.ck12.org Chapter 1. Properties of Chords b) If m BC = 80, find mĉd. Solution: a) From the picture, we know BD = CD. Because the chords are equal, the arcs are too. mĉd = 125. b) To find mĉd, subtract 80 from 360 and divide by 2. mĉd = 360 80 2 = 280 2 = 140 Investigation 9-2: Perpendicular Bisector of a Chord Tools Needed: paper, pencil, compass, ruler 1. Draw a circle. Label the center A. 2. Draw a chord in A. Label it BC. 3. Find the midpoint of BC by using a ruler. Label it D. 4. Connect A and D to form a diameter. How does AD relate to the chord, BC? Theorem 10-4: The perpendicular bisector of a chord is also a diameter. 3

www.ck12.org In the picture to the left, AD BC and BD = DC. From this theorem, we also notice that AD also bisects the corresponding arc at E, so BE = ÊC. Theorem 10-5: If a diameter is perpendicular to a chord, then the diameter bisects the chord and its corresponding arc. Example 2: Find the value of x and y. Solution: The diameter here is also perpendicular to the chord. From Theorem 10-5, x = 6 and y = 75. Example 3: Is the converse of Theorem 10-4 true? Solution: The converse of Theorem 10-4 would be: A diameter is also the perpendicular bisector of a chord. This is not a true statement, see the counterexample to the right. Example 4: Algebra Connection Find the value of x and y. Solution: Because the diameter is perpendicular to the chord, it also bisects the chord and the arc. Set up an equation for x and y. (3x 4) = (5x 18) y + 4 = 2y + 1 14 = 2x 3 = y 7 = x 4

www.ck12.org Chapter 1. Properties of Chords Equidistant Congruent Chords Investigation 9-3: Properties of Congruent Chords Tools Needed: pencil, paper, compass, ruler 1. Draw a circle with a radius of 2 inches and two chords that are both 3 inches. Label as in the picture to the right. This diagram is drawn to scale. 2. From the center, draw the perpendicular segment to AB and CD. You can either use your ruler, a protractor or Investigation 3-2 (Constructing a Perpendicular Line through a Point not on the line. We will show arc marks for Investigation 3-2. 3. Erase the arc marks and lines beyond the points of intersection, leaving FE and EG. Find the measure of these segments. What do you notice? Theorem 10-6: In the same circle or congruent circles, two chords are congruent if and only if they are equidistant from the center. Recall that two lines are equidistant from the same point if and only if the shortest distance from the point to the line is congruent. The shortest distance from any point to a line is the perpendicular line between them. In this theorem, the fact that FE = EG means that AB and CD are equidistant to the center and AB = CD. Example 5: Algebra Connection Find the value of x. 5

www.ck12.org Solution: Because the distance from the center to the chords is congruent and perpendicular to the chords, then the chords are equal. 6x 7 = 35 6x = 42 x = 7 Example 6: BD = 12 and AC = 3 in A. Find the radius and m BD. Solution: First find the radius. In the picture, AB is a radius, so we can use the right triangle ABC, such that AB is the hypotenuse. From 10-5, BC = 6. 3 2 + 6 2 = AB 2 9 + 36 = AB 2 AB = 45 = 3 5 In order to find m BD, we need the corresponding central angle, BAD. We can find half of BAD because it is an acute angle in ABC. Then, multiply the measure by 2 for m BD. tan 1 ( 6 3 ) = m BAC m BAC 63.43 This means that m BAD 126.9 and m BD 126.9 as well. Know What? Revisited In the picture, the chords from A and E are congruent and the chords from B, C, and D are also congruent. We know this from Theorem 10-3. All five chords are not congruent because all five circles are not congruent, even though the central angle for the circles is the same. 6

www.ck12.org Chapter 1. Properties of Chords Review Questions 1. Two chords in a circle are perpendicular and congruent. Does one of them have to be a diameter? Why or why not? Fill in the blanks. 2. = DF 3. ÂC = 4. DJ = 5. = EJ 6. AGH = 7. DGF = 8. List all the congruent radii in G. Find the value of the indicated arc in A. 9. m BC 10. m BD 11. m BC 7

www.ck12.org 12. m BD 13. m BD 14. m BD Algebra Connection Find the value of x and/or y. 15. 8 16.

www.ck12.org Chapter 1. Properties of Chords 18. AB = 32 17. 19. 20. 21. 22. 9

www.ck12.org 23. 24. Find mâb in Question 18. Round your answer to the nearest tenth of a degree. 25. Find mâb in Question 23. Round your answer to the nearest tenth of a degree. In problems 26-28, what can you conclude about the picture? State a theorem that justifies your answer. You may assume that A is the center of the circle. 26. 27. 28. 29. Trace the arc below onto your paper then follow the steps to locate the center using a compass and straightedge. 10 a. Use your straightedge to make a chord in the arc. b. Use your compass and straightedge to construct the perpendicular bisector of this chord. c. Repeat steps a and b so that you have two chords and their perpendicular bisectors. d. What is the significance of the point where the perpendicular bisectors intersect? e. Verify your answer to part d by using the point and your compass to draw the rest of the circle. 30. Algebra Connection Let s repeat what we did in problem 29 using coordinate geometry skills. Given the points A( 3,5),B(5,5) and C(4, 2) on the circle (an arc could be drawn through these points from A to C). The following steps will walk you through the process to find the equation of the perpendicular bisector of

www.ck12.org Chapter 1. Properties of Chords a chord, and use two of these perpendicular bisectors to locate the center of the circle. Let s first find the perpendicular bisector of chord AB. a. Since the perpendicular bisector passes through the midpoint of a segment we must first find the midpoint between A and B. b. Now the perpendicular line must have a slope that is the opposite reciprocal of the slope of AB. Find the slope of AB and then its opposite reciprocal. c. Finally, you can write the equation of the perpendicular bisector of AB using the point you found in part a and the slope you found in part b. d. Repeat steps a-c for chord BC. e. Now that we have the two perpendicular bisectors of the chord we can use algebra to find their intersection. Solve the system of linear equations to find the center of the circle. f. Find the radius of the circle by finding the distance from the center (point found in part e) to any of the three given points on the circle. 31. Find the measure of ÂB in each diagram below. a. b. Review Queue Answers 1 & 2. Answers will vary 11

www.ck12.org 3. m BC = 60,m BDC = 300 4. BC = DE and BC = DE 12