Physics 1520, Spring 2013 Quiz 2, Form: A

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Physics 1520, Spring 2013 Quiz 2, Form: A Name: Date: Section 1. Exercises 1. The index of refraction of a certain type of glass for red light is 1.52. For violet light, it is 1.54. Which color of light, red or violet, travels slower in glass. red violet neither; they travel at the same speed. 2. Red light of wavelength 650 nm (in air) travels through glass of index of refraction 1.5. What is the light s frequency in the glass? 3.1 10 14 Hz 6.9 10 14 Hz 2.1 10 14 Hz 4.6 10 14 Hz 3. Green laser light shines on a double slit, creating a pattern of bright and dark spots on a screen some distance away. Which one of the following changes, carried out separately, would increase the distance between the bright spots on the screen? Replace the green laser with a red laser. Replace the green laser with a blue laser. Increase the spacing between the slits. Decrease the distance between the double slit and the screen. 4. Light passes through two slits and produces the interference pattern shown below. The distance between fringe A and fringe E in the picture is 1.0 cm. What is the fringe spacing, y? 4.0 cm 1.0 cm 0.50 cm 0.25 cm 0.20 cm 1

5. Light from a helium-neon laser (λ = 633 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen 3.0 m behind the slits. Adjacent fringes are 4 mm apart. How far apart are the two slits? 7.60 10 4 m 7.60 10 9 m 475 m 4.75 10 7 m 4.75 10 4 m 6. Two different diffraction patterns for light of different wavelengths are shown below. How was each pattern created? In both cases, light passed through 2 slits. In both cases, light passed through 1 slit. Questions 7 8: The figure shows four situations in which light is incident perpendicularly on a thin film (the middle layer in each case). The indices of refraction are n 1 = 1.50 and n 2 = 2.00. Air is also one of the layers in each case. 7. For the two reflected rays (off the top surface of the film and the bottom surface of the film) in Case A, there is a total of 0 phase changes 1 phase change 2 phase changes 8. In Case D above, there are 2 total phase changes for light reflected from the top and bottom surfaces of the film, and the film s thickness is 153 nm. Which one of these wavelengths of light will constructively interfere for this thickness? 612 nm 410 nm 459 nm 579 nm 536 nm 2

Questions 9 10: Two plane mirrors are at a 90 angle. Light is incident on the side mirror as shown below. 1.0 m 9. At what distance from the side mirror does the ray hit the bottom mirror? 1.4 m 0.57 m 1.0 m 0.82 m 0.70 m 10. At what angle, with respect to the normal, does the ray hit the bottom mirror? θ < 35 35 35 < θ < 55 55 θ > 55 3

Questions 11 12: A ray travels along the path shown below. n 1 = 2.0. 11. What is n 2? 2.2 1.5 1.4 3.9 1.2 12. Which of the following is true? n 3 = n 1 n 3 > n 1 n 3 < n 1 none of the above because it cannot be determined from the given information 13. A ray of light is incident on a glass-water interface as shown below. What is the critical angle? (n glass = 1.5 and n water = 1.33) Glass Water 62 49 42 28 none of the above because it is impossible for light traveling from glass to water to undergo total internal reflection 4

14. Trace the easy rays for the object and lens shown below. 1 2 3 4 5 15. Trace the easy rays for the object and lens shown below. 1 2 3 4 5 5

16. Trace the easy rays for the object and lens shown below. 1 2 3 4 5 17. Trace the easy rays for the object and mirror shown below. 1 2 3 4 5 Questions 18 19: A dentist uses a curved mirror to view the back side of teeth on the upper jaw. Suppose she wants an upright virtual image with a magnification of 2.0 when the mirror is 1.2 cm from a tooth. (Assume that the object and image are along a straight line.) 18. What is the image distance? 0.6 cm 2.4 cm -0.6 cm -1.2 cm -2.4 cm 6

19. What is the focal length of the mirror? 0.42 cm 2.4 cm 0.8 cm 1.25 cm -2.4 cm Questions 20 22: A 1.0-cm tall object is 75 cm in front of a converging lens that has a 30 cm focal length. 20. What is the image distance? 21 cm -21 cm 45 cm 50 cm -50 cm 21. Is the image real or virtual? real virtual 22. Calculate the magnification. Is the image reduced or enlarged? reduced enlarged neither because m = 1 23. A lens used to correct farsighted or nearsighted vision produces either a virtual image or a real image depending on whether you are farsighted or nearsighted. always produces a real image. always produces a virtual image. 24. Suppose that a patient is farsighted. Her near point is 150 cm. She would like to be able to focus on objects (like a book) that is at a normal near point is 25 cm. What focal length lens is needed? -21 cm -30 cm 21 cm 25 cm 30 cm 25. Lens A has a focal length of 20 cm. Lens B has a focal length of 5 cm. Which lens has a greater refractive power? Lens A Lens B Neither, they have the refractive power. 7