ALGEBRA: Chapter I: QUESTION BANK

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1 ALGEBRA: Chapter I: QUESTION BANK Elements of Number Theory Congruence One mark questions: 1 Define divisibility 2 If a b then prove that a kb k Z 3 If a b b c then PT a/c 4 If a b are two non zero integers such that a b b a then (Apr90,Oct-95, MQP, Mar-10 ) PT a= ± b (MQP, Apr-88, Apr-95) 5 If a b a c then PT (i)a (b+c) (Apr -06) (ii) a (b-c) iii) a bc 6 If a b a c then for any integers m n, PT a (mb+nc) 7 If ac bc c 0 then prove that a b 8 If a b c d then PT ac bd 9 PT an integer a 0 divides a 10 State division algorithm 11 Define GCD 12 Find the GCD of the following pairs of numbers i) 32 54 (Oct 96) (Apr 96) ii) 70 30 iii) 75 243 13 iv) 475 495 Express in terms of divisibility i) a b (mod m) ii)28 4 (mod 8) (Oct95) 14 Why is Congruences mod m is an equivalence relation 15 Find the least non-negative remainder when 16 (Oct 83, Apr 84) (Apr 91) i) 76 x 204 is divided by 7 (Apr 96) ii) 175 x 365 x 69 is divided by 17 (Oct 93) Find the total number of incongruent solutions for i) 6x 3 (mod 15) (Apr 06) ii) 6x 9 (mod 15) iii) 9x 21 (mod30) (Mar 08) iv) 7x 9 (mod 15) 17 The linear congruence 8x 23 (mod 24) has no solution why? 18 Find the least positive integer x satisfying 2x+5 x + 4(mod 5) 19 Find a value of x which satisfying the congruence i) 2x 3 (mod 3) ii) 2x-1 (x + 5) (mod 5) 20 Find any three values of k such that -18 3 (mod k) 21 Find a value of x if 22 Find the number of incongruent solutions of 23 Examine where has solution If so, find it 1 KHV (MQP) (Mar 08)

2 Two marks questions: 1 If a = b+c d c, d b then PT d c 2 PT product of r consecutive integers is divisible by r! (Apr 91) 3 ST (m+n)! is divisible by m! n! (Oct 89) 4 ST n(n+1) (2n+1) is divisible by 6 5 If n is even, ST n(n+1) (n+2) is divisible by 24 6 If n is any integer, ST n2+2 is not divisible by 4 7 If (a,b) = x, a y b y, PT ab xy 8 Using Euclid s Algorithm, find the GCD of the following pairs of numbers i) 305 720 (Apr 87) ii) 352 891 (Mar 08) iii) 595 252 9 Define relative Prime integers, give example 10 If prove that then prove that Or If c a relatively prime then 11 If (a, bc) =1 then PT (a, c) = 1 12 Let a b be integers if there exists integers x y such that ax+by =1 then PT (a,b) =1 13 Let a,b,c be three integers such that (a,c) = 1 (b,c) = 1 then PT (ab,c)=1 (Apr 87) 14 If (a, b) = 1, a c b c then PT ab c 15 Define Prime Composite numbers 16 PT least divisor >1 of any integer is a prime number 17 PT smallest positive divisor > 1 of a composite number a does not exceed 18 If a b are positive integer such that a2-b2 is a prime number, then ST a2-b2= a+b 19 Find number of positive divisors of the numbers sum of all positive divisors of (Oct 93) (MQP) a number ii) a= 345372 i) a= 72 iv) a= 756 20 (Jun08) ii) a=432 iii) a=39744 iv) a=756 If a b (mod m) x is any integer then PT i) (a+x) (b + x) (mod m) 22 v)a=960 Find the sum of all positive divisors except 1 it self for the following i) a= 960 21 iii) a=432 (Apr 08) (Apr 92) If a b( mod m ) c d (mod m) PT i) ac bd (mod m) (Oct 92) ii) a+c b+d(mod m) iii) a - c b d (mod m) 23 PT a b (mod m) iff a b leave the same remainder when divided by m 24 If ac bc(mod m) (c, m) = 1 then PT a b (mod m) (Apr89, Oct 91, Jul 06) 25 If a b (mod m) n>1 then PT a b (mod n) (Apr 89, Oct 91, Jul 06) 26 If 28 a (mod 5) then ST 3 a (mod 5) 2 KHV

3 27 If a b(mod m) (a, m) = 1 then ST(b, m) = 1 28 PT (a+b)n bn (mod a) 29 PT (a+b)n an (mod b) 30 Find the least non-negative remainder when i) 730 is divided by 5 (Mar 09) ii) 3200 x 250 is divided by 5 202 iii) 2 is divided by 11 (Jul 08) v) 2 is divided by 7 (Oct 90) 31 Viii) is divided by 23 is divided by 19 X) is divided by 67 Find the digit in the unit place of i) 212 (Apr 88) ii) 313 (Apr 95) iii) 3101 (Oct 96) iv) 7123 (MQP, Mar 08) viii) 3127 (Jul 07) vii) 312 (Jul 06) 32 (Oct 96) vi) 5 is divided by 7 is divided by 7 ix) (Oct 91) 20 iv) 3 is divided by 7 31 vii) (Apr 93) 50 Solve the linear congruence i) 3x 5 (mod 7) ii) 51x 32(mod 7) iii) 15x 6 (mod 21) iv) 12x 6 (mod 3) v) 4x 5 (mod 6) vi) 2x 2 (mod 6) vii) 3x 4 (mod 5) + 24 (Mar 10) viii) 37 2x (mod 11) (Apr 11) (Oct 88) 2n+1 (Jul 07) n+1 33 If x is any positive integer, ST 7 34 + ST 352n+1+23n+1 0 (mod 17), n Z 35 Find the unit digit in 36 Find a value of x satisfying is divisible by 11 write the solution set Three marks questions: 1 2 3 4 5 Prove that the divisibility relation is reflexive transitive but not symmetry in Z0 If P is a prime P ab then PT P a or P b (Apr93, MQP) PT there are infinitely many Primes (Apr 83, MQP) If prove that PT the relation Congruence mod m is an equivalence relation (Oct 86, Mar-08) Five marks questions: 1 2 3 4 Find (506,1155) express it in the form 506m+1155n Also ST expression is not unique Find the GCD of a= 495 b=675 using Euclid Algorithm method express it in the form 495x + 675y Also ST x y are not unique ST the integer a= 216 b=6125 are co-prime if 1=216x+6125y then find x y ST 14 25 are co-prime to each other if 1=14+25y, find x y 5 Find the G C D of 408 1032 Express in the form integers) Also, show that this expression is not unique 6 Find the number of all positive divisors the sum of all positive divisors of 39744 NOTE: One should not neglect questions of the type having fonts with bold letters 3 KHV (where m n are

4 SOLUTIONS: One mark questions: 1Define Divisibility Definition: Let a b be two integer with there exists an integer k such that denoted as thus we have 3 If prove that We say a divides b if (Transitive law) Proof: 1 2 Using (1) (2) we get, 4 If a b are two nonzero integers such that, then prove that 1 2 Multiplying (1) (2) we get, Thus, 5 If then i ii Proof: iii [each carries 1 mark] 1 2 i Adding (1) (2) we get, ii Subtracting (1) (2) we get, iii Multiplying (1) (2) we get, 7 Prove that, If Proof: On dividing both sides by, we get, 10 State Division algorithm Definition: Given two integers unique integers q r such that where, there exist In this, a is called the dividend, b the divisor, q the quotient r the remainder 11Define Greatest Common Divisor (G C D) Definition: Let a b be two integers with at least one of them being non - zero A non negative integer d is said to be a greatest common divisor of a b if (i) (ii), 12) i)2 ii) 10 iii) 3 iv) 5 13) i) m (a-b) ii)8 (28-4) 15) i) 6 ii) 6 4 KHV

5 16) i) 3 ii) 3 iii) 3 iv) 1 17) (8,24)=8 23 is not divisible by 818) 4 19) i) x=3 ii) x=120) 3, 7, -21 21) Find a value of x if 22) Find the number of incongruent solutions of In this, There are three incongruent solutions 23) Examine where has solution If so, find it In this, The solution does not exist Two marks questions: 8) i) GCD=5 ii) GCD=11 iii) Find the G C D of 595 252 (2 marks) By division algorithm 252)595(2 504 91 91)252(2 182 70 70)91(1 70 21 21)70(3 63 7 7)21(3 21 0 5 KHV

[if the remainder is not equal to zero then divide the divisor with the remainder until to get r=0) when the remainder r=0 then divisor itself is the GCD] Thus GCD is 7 10 If then Or If c a relatively prime then Proof: since Multiplying both the sides by b 15 Define prime composite number Definition: An integer is called a prime, if its only divisors are [A positive integer p>1 is said to be prime if its divisors are one itself] An integer, which is not a prime, is called a Composite number 19) i) T(a) = 12, S(a)=210 ii) T(a)=60, S(a)=1075932 iii) T(a)=20, S(a)=1240 iv) T(a)=56, S(a)=121920 v) Find the sum of all positive divisors of 960 is the canonical form T(960)=(1+6)(1+1)(1+1)=28 In this 20) i) 2087 ii) 807 iii) 82175 iv)1483 24) If ac bc(mod m) (c, m) = 1 then PT a b (mod m) Proof: Given Since ( c m are relatively primes) We must have 25) If a b (mod m) n>1 then PT a b (mod n) Proof: Given By data But Then by the transitive property ( 30) i)4 ii) 5 iii) 4 iv)2 ) v) 1 vi) 4 6 KHV

30) vii) Find the remainder when is divided by 7 We have Remainder is 4 30) viii) Find the remainder when is divided by 19 We have Remainder is 1 30)ix) Find the remainder when 23)71(3 23)73(3 69 23)75(3 69 2 is divided by 23 69 4 } 6 Remainder is 2 30) x) Find the remainder when is divided by 67 Remainder is 61 31) i) 6 ii)3 iii) 3 iv) Find the unit digit in unit digit is 3 31 v) 7 vi) 1 vii) 1 32) i) x 2 (mod 7) viii) 7 ii) x 2 (mod 7) iii) x 13 (mod 21), x 20 (mod 21), x 27 (mod 21) iv) x 0 (mod 3), x 1 (mod 3), x 2 (mod 3) vi) x 1 (mod 6), x 4 (mod 6) vii) x 3 (mod 5) viii) x 2 (mod 11) 7 KHV

35) Find the unit digit in (1) Also 2 From (1) (2), we have, unit digit is 7 36) Find a value of x satisfying write the solution set In this, solution Thus, it has a unique is the solution The solution set is Three marks questions: 2 : P is a prime P ab then PT P a or P b Proof: Given If Suppose, we shall prove that When since the theorem is proved, p a relatively primes, Multiplying both the sides by b 3 Prove that there are infinite primes: Let if possible the number of primes be finite say p1 p2 p3 pn let pn be the largest primeconsider N= p1 p2 p3 pn +1 When we divide N by any pi remainder is 1 hence N is not divisible by any of the primes p1 p2 p3 pn N cannot be composite N should be new prime N>pn the greatest prime, which contradicts assumption Hence there are infinitely many primes(proof was given by famous mathematician Euclid) 8 KHV

4 : If prove that Proof: since 1 since Multiplying 1 2 we get 2 6 PT the relation Congruence mod m is an equivalence relation Proof: Given relation is i Reflexive: We know that The relation is reflexive ii Symmetric: Let The relation is symmetric iii Transitive: Let The relation is transitive The relation congruence modulo m is an equivalence relation on the set of all integers Five marks questions: 1) GCD =11, m=16, n=-7 m=1171, n= -513 2) GCD=45, x=-4, y=3 x=-679, y=498 3) x=-2864, y=101 4) x=9, y=-5 5) Find the G C D of 408 1032 Express in the form (where m n are integers) Also, show that this expression is not unique ( 5 marks ) By division algorithm 408)1032(2 1032 408 2 216 816 216 216)408(1 408 216 1 192 216 192 192)216(1 192 24 9 KHV

24)192(8 192 0 Thus GCD of 408 1032 is 24 (1) To show that this expression is not unique: We have Adding Subtracting, we get (2) From (1) (2) the expression is not unique 6 Find the number of all positive divisors the sum of all positive divisors of 39744 (5 marks) is the prime power factorization form In this 10 KHV