Poker: Probabilities of the Various Hands

Similar documents
Poker: Probabilities of the Various Hands

Poker: Further Issues in Probability. Poker I 1/29

More Probability: Poker Hands and some issues in Counting

Poker Hands. Christopher Hayes

ABE/ASE Standards Mathematics

Counting integral solutions

Unit 6: Probability. Marius Ionescu 10/06/2011. Marius Ionescu () Unit 6: Probability 10/06/ / 22

Unit 6: Probability. Marius Ionescu 10/06/2011. Marius Ionescu () Unit 6: Probability 10/06/ / 22

DISCUSSION #8 FRIDAY MAY 25 TH Sophie Engle (Teacher Assistant) ECS20: Discrete Mathematics

Math 166: Topics in Contemporary Mathematics II

MAT104: Fundamentals of Mathematics II Summary of Counting Techniques and Probability. Preliminary Concepts, Formulas, and Terminology

Here are two situations involving chance:

{ a, b }, { a, c }, { b, c }

GAMBLING ( ) Name: Partners: everyone else in the class

6/24/14. The Poker Manipulation. The Counting Principle. MAFS.912.S-IC.1: Understand and evaluate random processes underlying statistical experiments

Compound Probability. Set Theory. Basic Definitions

The point value of each problem is in the left-hand margin. You must show your work to receive any credit, except on problems 1 & 2. Work neatly.

POKER (AN INTRODUCTION TO COUNTING)

CMPSCI 240: Reasoning Under Uncertainty First Midterm Exam

2.5 Sample Spaces Having Equally Likely Outcomes

Probability Homework Pack 1

JIGSAW ACTIVITY, TASK # Make sure your answer in written in the correct order. Highest powers of x should come first, down to the lowest powers.

Introductory Probability

Honors Precalculus Chapter 9 Summary Basic Combinatorics

Counting Poker Hands

Combinatorial Proofs

Probability & Expectation. Professor Kevin Gold

Developed by Rashmi Kathuria. She can be reached at

3 The multiplication rule/miscellaneous counting problems

November 6, Chapter 8: Probability: The Mathematics of Chance

Week 1: Probability models and counting

Chapter 2. Permutations and Combinations

CS1800: Intro to Probability. Professor Kevin Gold

Probability. The MEnTe Program Math Enrichment through Technology. Title V East Los Angeles College

Shuffle Up and Deal: Should We Have Jokers Wild?

Probability Review 41

LAMC Junior Circle February 3, Oleg Gleizer. Warm-up

MC215: MATHEMATICAL REASONING AND DISCRETE STRUCTURES

Classical vs. Empirical Probability Activity

Pan (7:30am) Juan (8:30am) Juan (9:30am) Allison (10:30am) Allison (11:30am) Mike L. (12:30pm) Mike C. (1:30pm) Grant (2:30pm)

The student will explain and evaluate the financial impact and consequences of gambling.

MATH 13150: Freshman Seminar Unit 4

TEST A CHAPTER 11, PROBABILITY

If you roll a die, what is the probability you get a four OR a five? What is the General Education Statistics

CISC-102 Fall 2017 Week 8

Conditional Probability Worksheet

10.2.notebook. February 24, A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit.

Advanced Intermediate Algebra Chapter 12 Summary INTRO TO PROBABILITY

Unit 9: Probability Assignments

Important Distributions 7/17/2006

Venn Diagram Problems

Suppose you are supposed to select and carry out oneof a collection of N tasks, and there are T K different ways to carry out task K.

Such a description is the basis for a probability model. Here is the basic vocabulary we use.

Multiplication and Probability

4.1 Sample Spaces and Events

Problem Set 2. Counting

Section 6.1 #16. Question: What is the probability that a five-card poker hand contains a flush, that is, five cards of the same suit?

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

Permutations: The number of arrangements of n objects taken r at a time is. P (n, r) = n (n 1) (n r + 1) =

November 11, Chapter 8: Probability: The Mathematics of Chance

Dungeon Crawler Card Game

2. Combinatorics: the systematic study of counting. The Basic Principle of Counting (BPC)

Simple Probability. Arthur White. 28th September 2016

Discrete probability and the laws of chance

Math 447 Test 1 February 25, Spring 2016

Contemporary Mathematics Math 1030 Sample Exam I Chapters Time Limit: 90 Minutes No Scratch Paper Calculator Allowed: Scientific

Intermediate Math Circles November 1, 2017 Probability I

CMPSCI 240: Reasoning Under Uncertainty First Midterm Exam

Functional Skills Mathematics

n(s)=the number of ways an event can occur, assuming all ways are equally likely to occur. p(e) = n(e) n(s)

7.1 Experiments, Sample Spaces, and Events

Unit Nine Precalculus Practice Test Probability & Statistics. Name: Period: Date: NON-CALCULATOR SECTION

Define and Diagram Outcomes (Subsets) of the Sample Space (Universal Set)

Simulations. 1 The Concept

Homework 8 (for lectures on 10/14,10/16)

3 The multiplication rule/miscellaneous counting problems

1. More on Binomial Distributions

Math 14 Lecture Notes Ch. 3.3

Grade 6 Math Circles Fall Oct 14/15 Probability

Probability: introduction

Chapter 4: Introduction to Probability

Def: The intersection of A and B is the set of all elements common to both set A and set B

LISTING THE WAYS. getting a total of 7 spots? possible ways for 2 dice to fall: then you win. But if you roll. 1 q 1 w 1 e 1 r 1 t 1 y

Probability, Continued

UNIT 9B Randomness in Computa5on: Games with Random Numbers Principles of Compu5ng, Carnegie Mellon University - CORTINA

UNIT 4 APPLICATIONS OF PROBABILITY Lesson 1: Events. Instruction. Guided Practice Example 1

CSE 21 Mathematics for Algorithm and System Analysis

Key Concepts. Theoretical Probability. Terminology. Lesson 11-1

Counting Methods and Probability

A Probability Work Sheet

c. If you roll the die six times what are your chances of getting at least one d. roll.

Probability (Devore Chapter Two)

Mixed Counting Problems

Fundamentals of Probability

Discrete Finite Probability Probability 1

Permutations and Combinations Practice Test

(a) Suppose you flip a coin and roll a die. Are the events obtain a head and roll a 5 dependent or independent events?

Conditional Probability Worksheet

COUNTING AND PROBABILITY

Problem Set 8 Solutions R Y G R R G

Transcription:

Poker: Probabilities of the Various Hands 22 February 2012 Poker II 22 February 2012 1/27

Some Review from Monday There are 4 suits and 13 values. The suits are Spades Hearts Diamonds Clubs There are 13 values: 2 through 10, Jack, Queen, King, and Ace. 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A Poker II 22 February 2012 2/27

Poker Hands A poker hand is made up of 5 cards. The different poker hands are, from best to worst, are: Hand Example Royal Flush A, K, Q, J, 10 Straight Flush J, 10, 9, 8, 7 4 of a kind 8, 8, 8, 8, 7 Full House 4, 4, 4, J, J Flush K, 10, 8, 7, 3 Straight Q, J, 10, 9, 8 3 of a kind 8, 8, 8, J, 6 2 pair K, K, 9, 9, A 1 pair 7, 7, 10, J, 4 Poker II 22 February 2012 3/27

Number of Poker Hands There are nearly 2.6 million poker hands. If n C r represents the number of ways to choose r things out of n, then 52 C 5 is the number of poker hands. Poker II 22 February 2012 4/27

Number of Poker Hands There are nearly 2.6 million poker hands. If n C r represents the number of ways to choose r things out of n, then 52 C 5 is the number of poker hands. The formula for n C r is nc r = n! r! (n r)! Poker II 22 February 2012 4/27

Number of Poker Hands There are nearly 2.6 million poker hands. If n C r represents the number of ways to choose r things out of n, then 52 C 5 is the number of poker hands. The formula for n C r is nc r = n! r! (n r)! The explanation point is spoken factorial; that is, 5! is spoken as 5 factorial. The numbers n C r are called combinations or binomial coefficients. Poker II 22 February 2012 4/27

Factorials The factorial n! means to multiply all the whole numbers between 1 and n. For example, 1! = 1 2! = 2 1 = 2 3! = 3 2 1 = 6 4! = 4 3 2 1 = 24 5! = 5 4 3 2 1 = 120 Poker II 22 February 2012 5/27

Factorials The factorial n! means to multiply all the whole numbers between 1 and n. For example, 1! = 1 2! = 2 1 = 2 3! = 3 2 1 = 6 4! = 4 3 2 1 = 24 5! = 5 4 3 2 1 = 120 Scientific calculators have a factorial button. More basic calculators do not. There are websites for calculating n C r. Poker II 22 February 2012 5/27

Pascal and his Triangle Blaise Pascal, a mathematician and physicist, lived in the 17th century. We heard his name last week with regard to the origins of probability theory. Perhaps he is best known today for the so-called Pascal s Triangle: Poker II 22 February 2012 6/27

Pascal and his Triangle Blaise Pascal, a mathematician and physicist, lived in the 17th century. We heard his name last week with regard to the origins of probability theory. Perhaps he is best known today for the so-called Pascal s Triangle: Poker II 22 February 2012 6/27

The picture above shows the first 9 rows of Pascal s Triangle. The full triangle goes on forever. Poker II 22 February 2012 7/27

The picture above shows the first 9 rows of Pascal s Triangle. The full triangle goes on forever. The significance of the triangle is it contains the various binomial coefficients. The numbering convention for using it is that the rows are numbered 0, 1, 2,..., and the entries, from left to right, in a row are numbered 0, 1, 2,.... If you want n C r, you go to the n-th row and find the r-th entry of that row; this gives you n C r. Poker II 22 February 2012 7/27

One can generate as many rows of the triangle as one wishes. The way to build a new row is to start and end with the number 1. Then, for any other number, add the two numbers immediately above the one you want. Poker II 22 February 2012 8/27

One can generate as many rows of the triangle as one wishes. The way to build a new row is to start and end with the number 1. Then, for any other number, add the two numbers immediately above the one you want. Poker II 22 February 2012 8/27

Last time we computed how many ways are there to choose r things out of 4 for all possible r (except for 0). The numbers we got were r 4C r 0 1 1 4 2 6 3 4 4 1 These are the numbers in row 4 of Pascal s triangle. Poker II 22 February 2012 9/27

The reason these numbers are called binomial coefficients is because they arise as coefficients in expanding (x + y) n into binomials. For example, (x + y) 2 = x 2 + 2xy + y 2 Poker II 22 February 2012 10/27

The reason these numbers are called binomial coefficients is because they arise as coefficients in expanding (x + y) n into binomials. For example, (x + y) 2 = x 2 + 2xy + y 2 and (x + y) 3 = x 3 + 3x 2 y + 3xy 2 + y 3 Poker II 22 February 2012 10/27

The reason these numbers are called binomial coefficients is because they arise as coefficients in expanding (x + y) n into binomials. For example, (x + y) 2 = x 2 + 2xy + y 2 and (x + y) 3 = x 3 + 3x 2 y + 3xy 2 + y 3 and (x + y) 4 = x 4 + 4x 3 y + 6x 2 y 2 + 4xy 3 + y 4 Poker II 22 February 2012 10/27

The reason these numbers are called binomial coefficients is because they arise as coefficients in expanding (x + y) n into binomials. For example, (x + y) 2 = x 2 + 2xy + y 2 and (x + y) 3 = x 3 + 3x 2 y + 3xy 2 + y 3 and (x + y) 4 = x 4 + 4x 3 y + 6x 2 y 2 + 4xy 3 + y 4 The enries in row n of Pascal s triangle gives the coefficients that show up in expanding (x + y) n. Poker II 22 February 2012 10/27

Probabilities of Being Dealt a Given Poker Hand We ll now look at what is the probability of being dealt a given poker hand when dealt 5 cards at random. Each hand of 5 cards is just as likely as any other to be dealt. Since there are 2, 598, 960 total hands, to compute the probability we need to compute how many of these represent the given type of hand. Poker II 22 February 2012 11/27

Probabilities of Being Dealt a Given Poker Hand We ll now look at what is the probability of being dealt a given poker hand when dealt 5 cards at random. Each hand of 5 cards is just as likely as any other to be dealt. Since there are 2, 598, 960 total hands, to compute the probability we need to compute how many of these represent the given type of hand. We can then use the formula probability = number of ways the outcome can occur. total number of outcomes Poker II 22 February 2012 11/27

Probability of a Royal Flush What is the probability of getting a royal flush when dealt 5 cards? Let s first ask: how many different royal flushes there are? Enter the number you think with your clicker. Poker II 22 February 2012 12/27

Probability of a Royal Flush What is the probability of getting a royal flush when dealt 5 cards? Let s first ask: how many different royal flushes there are? Enter the number you think with your clicker. There are 4 ways to get a royal flush, since the only choice is which suit you get. They are A K Q J 10, A K Q J 10, A K Q J 10 A K Q J 10 Poker II 22 February 2012 12/27

Probability of a Royal Flush What is the probability of getting a royal flush when dealt 5 cards? Let s first ask: how many different royal flushes there are? Enter the number you think with your clicker. There are 4 ways to get a royal flush, since the only choice is which suit you get. They are A K Q J 10, A K Q J 10, A K Q J 10 A K Q J 10 So, the probability is 4/2598960, or about 1 out of 600,000 deals. Poker II 22 February 2012 12/27

Probability of a Straight Flush There are few enough straight flushes that we can list them all. This is a bit tedious, but not too bad. Here they are: Poker II 22 February 2012 13/27

Probability of a Straight Flush There are few enough straight flushes that we can list them all. This is a bit tedious, but not too bad. Here they are: A2345 A 2 3 4 5 A 2 3 4 5 A 2 3 4 5 23456 2 3 4 5 6 2 3 4 5 6 2 3 4 5 6 34567 3 4 5 6 7 3 4 5 6 7 3 4 5 6 7 45678 4 5 6 7 8 4 5 6 7 8 4 5 6 7 8 56789 5 6 7 8 9 5 6 7 8 9 5 6 7 8 9 678910 6 7 8 9 10 6 7 8 9 10 6 7 8 9 10 78910J 7 8 9 10 J 7 8 9 10 J 7 8 9 10 J 8910JQ 8 9 10 J Q 8 9 10 J Q 8 9 10 J Q 910JQK 9 10 J Q K 9 10 J Q K 9 10 J Q K Poker II 22 February 2012 13/27

Probability of a Straight Flush There are few enough straight flushes that we can list them all. This is a bit tedious, but not too bad. Here they are: A2345 A 2 3 4 5 A 2 3 4 5 A 2 3 4 5 23456 2 3 4 5 6 2 3 4 5 6 2 3 4 5 6 34567 3 4 5 6 7 3 4 5 6 7 3 4 5 6 7 45678 4 5 6 7 8 4 5 6 7 8 4 5 6 7 8 56789 5 6 7 8 9 5 6 7 8 9 5 6 7 8 9 678910 6 7 8 9 10 6 7 8 9 10 6 7 8 9 10 78910J 7 8 9 10 J 7 8 9 10 J 7 8 9 10 J 8910JQ 8 9 10 J Q 8 9 10 J Q 8 9 10 J Q 910JQK 9 10 J Q K 9 10 J Q K 9 10 J Q K There are 36 straight flushes. Note that we are not counting the royal flushes. Poker II 22 February 2012 13/27

Some General Ideas About Counting Writing down all the straight flushes wasn t too bad, but it isn t a great general method. Poker II 22 February 2012 14/27

Some General Ideas About Counting Writing down all the straight flushes wasn t too bad, but it isn t a great general method. In order to compute the probability of other hands, one approach is to decide what things you need to choose in order to write down a hand, and then determine how many ways each of the choices can occur. Poker II 22 February 2012 14/27

Some General Ideas About Counting Writing down all the straight flushes wasn t too bad, but it isn t a great general method. In order to compute the probability of other hands, one approach is to decide what things you need to choose in order to write down a hand, and then determine how many ways each of the choices can occur. For example, to count royal flushes, you only have to choose a suit because we must then take 10, J, Q, K, A of that suit. Poker II 22 February 2012 14/27

Counting Independent Events If one event does not affect the outcome of another, they are called independent. To count the number of ways a pair of independent events can occur, multiply the number of ways each way can occur. Poker II 22 February 2012 15/27

Counting Independent Events If one event does not affect the outcome of another, they are called independent. To count the number of ways a pair of independent events can occur, multiply the number of ways each way can occur. This is basically the same mathematical idea as multiplying probabilities in a probability tree we used last week. Poker II 22 February 2012 15/27

Counting Independent Events If one event does not affect the outcome of another, they are called independent. To count the number of ways a pair of independent events can occur, multiply the number of ways each way can occur. This is basically the same mathematical idea as multiplying probabilities in a probability tree we used last week. Rolling two dice is an example of two independent events: what you get on one die does not affect what can happen on the other. Since there are 6 outcomes for rolling one die, there are 6 6 = 36 outcomes for rolling two dice. Poker II 22 February 2012 15/27

Probability of a Straight Flush, Revisited How can we use the idea above to count the number of straight flushes? Poker II 22 February 2012 16/27

Probability of a Straight Flush, Revisited How can we use the idea above to count the number of straight flushes? To choose a given straight flush, you must choose a suit, and a starting (or ending) value for the 5 in a row. There are 4 choices for the suit. Poker II 22 February 2012 16/27

Probability of a Straight Flush, Revisited How can we use the idea above to count the number of straight flushes? To choose a given straight flush, you must choose a suit, and a starting (or ending) value for the 5 in a row. There are 4 choices for the suit. Q How many ways are there to choose the starting value of a straight flush (which is not a royal flush)? Enter the number with your clicker. Poker II 22 February 2012 16/27

Probability of a Straight Flush, Revisited How can we use the idea above to count the number of straight flushes? To choose a given straight flush, you must choose a suit, and a starting (or ending) value for the 5 in a row. There are 4 choices for the suit. Q How many ways are there to choose the starting value of a straight flush (which is not a royal flush)? Enter the number with your clicker. A There are 9 values. It would appear that there are 10 possible starting values (A through 10). However, if we want a straight flush which is not a royal flush, we cannot start at 10, so there are 9 choices. Poker II 22 February 2012 16/27

Choosing the suit and the starting value are independent events. So, to count the number of straight flushes, we need to multiply the number of choices of suit and the number of choices of starting value. Poker II 22 February 2012 17/27

Choosing the suit and the starting value are independent events. So, to count the number of straight flushes, we need to multiply the number of choices of suit and the number of choices of starting value. Therefore, there are 4 9 = 36 total straight flushes. Poker II 22 February 2012 17/27

Choosing the suit and the starting value are independent events. So, to count the number of straight flushes, we need to multiply the number of choices of suit and the number of choices of starting value. Therefore, there are 4 9 = 36 total straight flushes. The probability of a straight flush (which is not a royal flush) is then 36/2, 598, 960, which is about 1 out of 72,000. Poker II 22 February 2012 17/27

4 of a Kind What is the probability of a 4 of a kind? An example is 8, 8, 8, 8, J Poker II 22 February 2012 18/27

4 of a Kind What is the probability of a 4 of a kind? An example is 8, 8, 8, 8, J To get a 4 of a kind, you must choose the value of the 4 of a kind, and choose the remaining card. Poker II 22 February 2012 18/27

4 of a Kind What is the probability of a 4 of a kind? An example is 8, 8, 8, 8, J To get a 4 of a kind, you must choose the value of the 4 of a kind, and choose the remaining card. There are 13 choices for the value of the 4 of a kind. Poker II 22 February 2012 18/27

4 of a Kind What is the probability of a 4 of a kind? An example is 8, 8, 8, 8, J To get a 4 of a kind, you must choose the value of the 4 of a kind, and choose the remaining card. There are 13 choices for the value of the 4 of a kind. Q How many choices are there for the remaining card? Poker II 22 February 2012 18/27

4 of a Kind What is the probability of a 4 of a kind? An example is 8, 8, 8, 8, J To get a 4 of a kind, you must choose the value of the 4 of a kind, and choose the remaining card. There are 13 choices for the value of the 4 of a kind. Q How many choices are there for the remaining card? A 48. The 5th card can be any of the remaining 48 cards. Poker II 22 February 2012 18/27

Because we can view writing down a 4 of a kind as choosing the value of the 4 of a kind and picking the last card, which are independent events, we need to multiply the number of choices together. Poker II 22 February 2012 19/27

Because we can view writing down a 4 of a kind as choosing the value of the 4 of a kind and picking the last card, which are independent events, we need to multiply the number of choices together. The number of four of a kinds is then 13 48 = 624. The probability of a 4 of a kind is then 624/2598960, or about 1 out of 4200. Poker II 22 February 2012 19/27

Full House A full house consists of a 3 of a kind and a 2 of a kind. What is the probability of getting a full house? An example is 4, 4, 4, J, J Poker II 22 February 2012 20/27

Full House A full house consists of a 3 of a kind and a 2 of a kind. What is the probability of getting a full house? An example is 4, 4, 4, J, J To have a full house you must choose the value of a 3 of a kind and the value of a 2 of a kind. You must also choose which 3 cards make up the 3 of a kind and which 2 make up the 2 of a kind. This is one of the more complicated counts. Poker II 22 February 2012 20/27

Clicker Questions Q How many ways are there to choose the value of the 3 of a kind? Poker II 22 February 2012 21/27

Clicker Questions Q How many ways are there to choose the value of the 3 of a kind? A There are 13 C 1 = 13 ways to choose the value of the 3 of a kind. Poker II 22 February 2012 21/27

Clicker Questions Q How many ways are there to choose the value of the 3 of a kind? A There are 13 C 1 = 13 ways to choose the value of the 3 of a kind. Q How many ways area there to choose the value of the 2 of a kind? Poker II 22 February 2012 21/27

Clicker Questions Q How many ways are there to choose the value of the 3 of a kind? A There are 13 C 1 = 13 ways to choose the value of the 3 of a kind. Q How many ways area there to choose the value of the 2 of a kind? A There are 12 C 1 = 12 ways to choose the value of the pair. You can choose any value other than the value of the 3 of a kind. Poker II 22 February 2012 21/27

More Clicker Questions Q For sake of argument, say we choose Jacks for the 3 of a kind and 7 for the 2 of a kind. How many ways are there to choose the 3 jacks? Poker II 22 February 2012 22/27

More Clicker Questions Q For sake of argument, say we choose Jacks for the 3 of a kind and 7 for the 2 of a kind. How many ways are there to choose the 3 jacks? A There are 4 C 3 = 4 ways to choose the 3 Jacks. They are J J J J J J J J J J J J Poker II 22 February 2012 22/27

More Clicker Questions Q For sake of argument, say we choose Jacks for the 3 of a kind and 7 for the 2 of a kind. How many ways are there to choose the 3 jacks? A There are 4 C 3 = 4 ways to choose the 3 Jacks. They are J J J J J J J J J J J J Q How many ways are there to choose the two 7s? Poker II 22 February 2012 22/27

More Clicker Questions Q For sake of argument, say we choose Jacks for the 3 of a kind and 7 for the 2 of a kind. How many ways are there to choose the 3 jacks? A There are 4 C 3 = 4 ways to choose the 3 Jacks. They are J J J J J J J J J J J J Q How many ways are there to choose the two 7s? A There are 4 C 2 = 6 ways to choose the two 7s. They are 7 7 7 7 7 7 7 7 7 7 7 7 Poker II 22 February 2012 22/27

To find the number of full houses, we then have to multiply the numbers of our various choices (value of the 3 of a kind, value of the pair, the three cards for the 3 of a kind, the two cards for the pair). Poker II 22 February 2012 23/27

To find the number of full houses, we then have to multiply the numbers of our various choices (value of the 3 of a kind, value of the pair, the three cards for the 3 of a kind, the two cards for the pair). So, the number of full houses is 13 12 4 6 = 3744 Poker II 22 February 2012 23/27

To find the number of full houses, we then have to multiply the numbers of our various choices (value of the 3 of a kind, value of the pair, the three cards for the 3 of a kind, the two cards for the pair). So, the number of full houses is 13 12 4 6 = 3744 The probability of a full house is then 3744/2598960, which is about 1 out of 4000 hands. Poker II 22 February 2012 23/27

Probability of a Flush In order to have a flush, which is 5 cards of the same suit, we need to choose the suit, and then pick the five cards. Poker II 22 February 2012 24/27

Probability of a Flush In order to have a flush, which is 5 cards of the same suit, we need to choose the suit, and then pick the five cards. There are 4 choices for the suit. Poker II 22 February 2012 24/27

Probability of a Flush In order to have a flush, which is 5 cards of the same suit, we need to choose the suit, and then pick the five cards. There are 4 choices for the suit. Q Suppose we decide to get a flush with hearts. How many ways are there to pick 5 hearts? Poker II 22 February 2012 24/27

Probability of a Flush In order to have a flush, which is 5 cards of the same suit, we need to choose the suit, and then pick the five cards. There are 4 choices for the suit. Q Suppose we decide to get a flush with hearts. How many ways are there to pick 5 hearts? A We need to pick 5 of the 13 hearts. The number of ways is 13 C 5. This is equal to 1287. Poker II 22 February 2012 24/27

Probability of a Flush In order to have a flush, which is 5 cards of the same suit, we need to choose the suit, and then pick the five cards. There are 4 choices for the suit. Q Suppose we decide to get a flush with hearts. How many ways are there to pick 5 hearts? A We need to pick 5 of the 13 hearts. The number of ways is 13 C 5. This is equal to 1287. The number of flushes is then 4 1287 = 5148. However, this includes royal and straight flushes. Subtracting the 40 of them gives 5108 flushes. This means the probability of being dealt a flush is 5108/2598960, or about 1 out of every 500 hands. Poker II 22 February 2012 24/27

Probabilities of the Various Hands We could continue with the remaining types of hands. But, instead we summarize the results: Poker II 22 February 2012 25/27

Probabilities of the Various Hands We could continue with the remaining types of hands. But, instead we summarize the results: Type of Hand Number of that Type Percentage Royal Flush 4 0.00015% Straight Flush 36 0.001% 4 of a Kind 624 0.02% Full House 3,744 0.15% Flush 5,108 0.2% Straight 10,200 0.4% 3 of a Kind 54,912 2.1% 2 Pair 123,552 4.8% 1 Pair 1,098,240 42.3% Nothing 1,302,540 50.1% Poker II 22 February 2012 25/27

Next Time We will discuss some probabilities involved in playing poker. More specifically, we ll look at the game Texas Hold em, which is perhaps the most popular poker game. We will introduce the notion of expected value, which helps to determine good strategy. We ll use this idea next week when we discuss lotteries. Poker II 22 February 2012 26/27

Quiz Question How many ways are there to pick 2 of the four Aces in a deck? A 1 B 2 C 4 D 6 Poker II 22 February 2012 27/27