Interference: An Information Theoretic View

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Transcription:

Interference: An Information Theoretic View David Tse Wireless Foundations U.C. Berkeley ISIT 2009 Tutorial June 28 Thanks: Changho Suh.

Context Two central phenomena in wireless communications: Fading Interference Much progress on information theory of fading channels in the past 15 years Led to important communication techniques: MIMO Opportunistic communication Already implemented in many wireless systems.

Interference These techniques improve point-to-point and single cell (AP) performance. But performance in wireless systems are often limited by interference between multiple links. Two basic approaches: orthogonalize into different bands full sharing of spectrum but treating interference as noise What does information theory have to say about the optimal thing to do?

State-of-the-Art The capacity of even the simplest two-user interference channel (IC) is open for 30 years. But significant progress has been made in the past few years through approximation results. Some new ideas: generalized degrees of freedom deterministic modeling interference alignment. Goal of the tutorial is to explain these ideas.

Outline Part 1: two-user Gaussian IC. Part 2: Resource-sharing view and role of feedback and cooperation. Part 3: Multiple interferers and interference alignment.

Part I: 2-User Gaussian IC

Two-User Gaussian Interference Channel message m 1 want m 1 message m 2 want m 2 Characterized by 4 parameters: Signal-to-noise ratios SNR 1, SNR 2 at Rx 1 and 2. Interference-to-noise ratios INR 2->1, INR 1->2 at Rx 1 and 2.

Related Results If receivers can cooperate, this is a multiple access channel. Capacity is known. (Ahlswede 71, Liao 72) If transmitters can cooperate, this is a MIMO broadcast channel. Capacity recently found. (Weingarten et al 05) When there is no cooperation of all, it s the interference channel. Open problem for 30 years.

State-of-the-Art in 2006 If INR 1->2 > SNR 1 and INR 2->1 > SNR 2, then capacity region C int is known (strong interference, Han- Kobayashi 1981, Sato 81) Capacity is unknown for any other parameter ranges. Best known achievable region is due to Han- Kobayashi (1981). Hard to compute explicitly. Unclear if it is optimal or even how far from capacity. Some outer bounds exist but unclear how tight (Sato 78, Costa 85, Kramer 04).

Review: Strong Interference Capacity INR 1->2 > SNR 1, INR 2->1 > SNR 2 Key idea: in any achievable scheme, each user must be able to decode the other user s message. Information sent from each transmitter must be common information, decodable by all. The interference channel capacity region is the intersection of the two MAC regions, one at each receiver.

Han-Kobayashi Achievable Scheme common private decode common private decode Problems of computing the HK region: - optimal auxillary r.v. s unknown - time-sharing over many choices of auxillary r.v, s may be required.

Interference-Limited Regime At low SNR, links are noise-limited and interference plays little role. At high SNR and high INR, links are interferencelimited and interference plays a central role. Classical measure of performance in the high SNR regime is the degree of freedom.

Baselines (Symmetric Channel) Point-to-point capacity: Achievable rate by orthogonalizing: Achievable rate by treating interference as noise:

Generalized Degrees of Freedom Let both SNR and INR to grow, but fixing the ratio: Treating interference as noise:

Dof plot Optimal Gaussian HK

Dof-Optimal Han-Kobayashi Only a single split: no time-sharing. Private power set so that interference is received at noise level at the other receiver.

Why set INR p = 0 db? This is a sweet spot where the damage to the other link is small but can get a high rate in own link since SNR > INR.

Can we do Better? We identified the Gaussian HK scheme that achieves optimal gdof. But can one do better by using non-gaussian inputs or a scheme other than HK? Answer turns out to be no. The gdof achieved by the simple HK scheme is the gdof of the interference channel. To prove this, we need outer bounds.

Upper Bound: Z-Channel Equivalently, x 1 given to Rx 2 as side information.

How Good is this Bound?

What s going on? Scheme has 2 distinct regimes of operation: Z-channel bound is tight. Z-channel bound is not tight.

New Upper Bound Genie only allows to give away the common information of user i to receiver i. Results in a new interference channel. Capacity of this channel can be explicitly computed!

New Upper Bound + Z-Channel Bound is Tight

Back from Infinity In fact, the simple HK scheme can achieve within 1 bit/s/hz of capacity for all values of channel parameters: For any rates in C int, this scheme can achieve (Etkin, T. & Wang 06)

Symmetric Weak Interference The scheme achieves a symmetric rate per user: The symmetric capacity is upper bounded by: The gap is at most one bit for all values of SNR and INR. Gap (bits/hz/s) 1 0.8 0.6 0.4 0.2 0 60 40 60 40 20 0 0 20 INR (db) -20-20 SNR (db)

From 1-Bit to 0-Bit The new upper bound can further be sharpened to get exact results in the low-interference regime (α < 1/3). (Shang,Kramer,Chen 07, Annaprueddy & Veeravalli08, Motahari&Khandani07)

From Low-Noise to No-Noise The 1-bit result was obtained by first analyzing the dof of the Gaussian interference channel in the lownoise regime. Turns out there is a deterministic interference channel which captures exactly the behavior of the interference-limited Gaussian channel. Identifying this underlying deterministic structure allows us to generalize the approach.

Part 2: Resource, Feedback and Cooperation

Basic Questions 1) How to abstract a higher view of the 2-user IC result? 2) In particular: how to quantify the resource being shared? The key is deterministic modeling of the IC.

Point-to-Point Communication: An Abstraction Transmit a real number Least significant bits are truncated at noise level. Matches approx:

A Deterministic Model (Avestimehr,Diggavi & T. 07)

Superposition Gaussian Deterministic user 2 mod 2 addition user 1 sends cloud centers, user 2 sends clouds. user 1

Comparing Multiple Access Capacity Regions Gaussian Deterministic user 2 user 1 mod 2 addition accurate to within 1 bit per user

Broadcast Gaussian Deterministic user 1 user 2 log(1 +SNR 2 ) R 2 n 2 To within 1 bit R 1 n 1 log(1 +SNR 1 )

Interference Gaussian Deterministic In symmetric case, channel described by two parameters: SNR, INR Capacity can be computed using a result by El Gamal and Costa 82.

Symmetric Capacity (Bresler & T. 08) time/freq orthogonalization Tx 1 Rx 1 Tx 1 Rx 1 Tx 1 Rx 1 Tx 2 Rx 2 Tx 2 Rx 2 Tx 2 Rx 2

A Resource Sharing View The two communication links share common resources via interference. But what exactly is the resource being shared? We can quantify this using the deterministic model.

Resource: Traditional View time-frequency grid as a common ether. freq. time Each transmission costs one time-frequency slot. If a tree falls in a forest and no one is around to hear it, does it make a sound?

Resource is at the Receivers The action is at the receivers. No common ether: each Rx has its own resource. Signal strengths have to come into picture. Signal level provides a new dimension.

A New Dimension freq. freq. time time signal level Resource at a receiver: # of resolvable bits per sample bandwidth time W T

Resource and Cost Resource available at each Rx = max(m,n) signal levels ($) Cost to transmit 1 bit: = $2 if visible to both Rx. = $1 if visible to only own Rx.

Symmetric Capacity cost increases resource increases (Bresler & T. 08) time/freq orthogonalization Tx 1 Rx 1 Tx 1 Rx 1 Tx 1 Rx 1 Tx 2 Rx 2 Tx 2 Rx 2 Tx 2 Rx 2

Follow-Up Questions How does feedback and cooperation improve resource utilization?

Feedback Delay Tx 1 Rx 1 Tx 2 Rx 2 Delay

Can Feedback Help? cost increases resource increases w/ feedback w/o feedback (Suh & T. 09) Feedback does not reduce cost, but it maximizes resource utilization.

Example: α = 0.5 w/o feedback Tx 1 Rx 1 Tx 2 Rx 2 consumption: 2 levels resource: 4 levels Potential to squeeze 1 more bit in with feedback

Example: α = 0.5 decode Tx 1 feedback cost $0 Rx 1 Tx 2 cost $2 Rx 2 decode 1 bit feedback buys 1 bit Tx 1 sending b1 helps Rx 1 to recover a1 without causing interference to Rx 2.

Gaussian Case There is a natural analog of this feedback scheme for the Gaussian case. Using this scheme, the feedback capacity of the 2- user IC can be achieved to within 1 bit/s/hz. To find out, go to Changho Suh s talk on Thurs!

Can We Do Better than the V-curve??? w/ feedback (Wang & T. 09) Tx 1 Rx 1 2 cooperation bits buys 1 bit Backhaul Tx 2 Rx 2 Cooperation reduces cost.

Cheaper Cooperation Tx 1 Rx 1 1 cooperation bit buys 1 bit Backhaul Tx 2 Rx 2

Conferencing Capacity Devised a cooperation scheme for the Gaussian IC with conferencing decoders. Achieves capacity region to within 2 bits. Related work: cooperation via wireless links (Prabhakaran & Viswanath 08)

Part 3: Multiple Interferers and Interference Alignment

IC With More than 2 Users So far we have focused on the two-user interference channel. What happens where there are more than 2 users? Do the ideas generalize in a straightforward way? Not at all. We are far from a complete theory for K-user IC s. We will go through a few examples to get a sense of what s going on.

Many-to-One IC In the 2 user case a Han- Kobayashi achievable scheme with Gaussian inputs is 1-bit optimal. Is Han-Kobayashi scheme with Gaussian inputs optimal for more than 2 users?

Deterministic Many to One IC Gaussian Deterministic

Achievable Scheme. Interference alignment: two (or more) users transmit on a level, cost to user 0 is same of that for a single interferer. Equivalently, cost of transmitting 1 bit for interferer is 1.5 levels. Turns out that scheme achieves capacity on the deterministic channel.

Example Tx 0 Rx 0 Tx 1 Rx 1 Tx 2 Rx 2 Interference from users 1 and 2 is aligned at the MSB at user 0 s receiver in the deterministic channel. How can we mimic it for the Gaussian channel?

Gaussian Lattice codes Han-Kobayashi can achieve Not constant Optimal gap Suppose users 1 and 2 use a random Gaussian codebook: Tx 0 Rx 0 Random Code Sum of Two Random Codebooks Lattice Code for Users 1 and 2 Tx 1 Tx 2 Rx 1 Rx 2 Interference from users 1 and 2 fills the space: no room for user 0. User 0 Code

Approximate Capacity Theorem: (Approximate Capacity of K-user Many-to-One Gaussian IC). Achievable scheme is within log 2 K bits of capacity, for any channel gains. (Bresler, Parekh and T. 07)

What Have we Learnt In two-user case, we showed that an existing strategy can achieve within 1 bit to optimality. In many-to-one case, we showed that a new strategy can do much better. Two elements: Structured coding instead of random coding Interference alignment

Interference Alignment: History First observed in the analysis of the X-Channel (Maddah-Ali et al 06) Concept crystallized by Jafar & Shamai 06 Applied to the K-user parallel interference channel (Cadambe & Jafar 07) Applied to the many-to-one scalar IC (Bresler et al 07) Two types of interference alignment: along time/frequency/space dimension along signal scale

2-User MIMO X Channel MIMO XIC Tx 1 Rx a Enc1 Dec a Tx 2 Rx b Enc2 Dec b

2-User MIMO X Channel Tx 1 Rx a Tx 2 Rx b

MIMO X-Channel vs Interference Channel total dof of a 2-user MIMO with M antennas: Interference Channel: M (Jafar and Fakhereddin 06) X- Channel: 4M/3 (Jafar and Shamai 06) Interference alignment gain.

3-User MIMO IC a 1 Tx 1 Need Simultaneous Interference Alignment Rx 1 a 1 a 1 Tx 2 Rx 2 b 1 1 c 1 Tx 3 Rx 3 c 1 b a 1 a b 1 + c 1 1 b 1 b + c 1 1 c 1 a 1 a + b 1 1 3 conditions 3 vectors # of conditions matches # of variables c 1 b 1 c 1

3-User MIMO IC Rx 1 :eigenvector of a 1 Rx 2 b 1 b + c 1 1 Rx 3 a + c 1 1 a + b 1 1 Check rank condition: MIMO channel: rank=2 w.h.p. c 1

3-User Parallel IC Rx 1 Use 2 subcarriers :eigenvector of a 1 Rx 2 b 1 b + c 1 1 Check rank condition: a + c 1 1 All matrices are diagonal. Rx 3 a + b 1 1 rank=1 c 1

3-User IC: Summary With MIMO, can achieve optimal total dof of 3/2 per antenna. With finite number of parallel sub-channels, cannot. (Cadambe & Jafar 07) As the number of parallel sub-channels grows, 3/2 can be achieved asymptotically. Key idea: partial subspace alignment In general, for K-user IC, K/2 can be achieved asymptotically. However, number of sub-channels scales like (K 2 ) K2

Interference Alignment can still be useful a 1 Tx 1 Use 2 subcarriers Rx 1 a 1 Gallokota et al 09 a 1 Tx 2 Rx 2 b 1 1 b c 1 b 1 b 1 b + c 1 1 a 1 Backha ul Tx 3 Rx 3 c c 1 + a 1 1 c 1 a 1 b 1 a 1 c 1 b 1

Capacity For 2 user IC and many-to-one IC, we have constant gap capacity approximation. For 2-user X-channel and 3-user fully connected IC, we do not, even for single antenna. In fact, we don t even know the d.o.f. Interference alignment on signal scale is useful for very specific channel parameter values (Cadambe, Jafar & Shamai 08, Huang, Cadambe & Jafar 09, Etkin & Ordentlich 09) But we don t know if it s useful for many parameter values.

Conclusions A good understanding of the 2-user IC, even with feedback and cooperation. Deterministic modeling is a useful technique. Interference alignment has been shown to be a useful technique when there are multiple interfererers. But we don t have a good understanding on the capacity when there are multiple interferers.