Outcome 9 Review Foundations and Pre-Calculus 10

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Outcome 9 Review Foundations and Pre-Calculus 10 Level 2 Example: Writing an equation in slope intercept form Slope-Intercept Form: y = mx + b m = slope b = y-intercept Ex : Write the equation of a line that has a y-intercept of 3 and a slope of -4 in slope-intercept form Y = mx + b Our m = -4 our b = 3 so: y = -4x + 3 Ex : Write the equation of a line in slope-intercept form that has a slope of 2 and a y-intercept of -5 3 Our m = 2 3 and b = -5 so: y = 2 3 x 5 1. Write the equation of the following lines in slope intercept form a) Slope of -8, y-intercept of 6 c) Slope of 4 and a y-intercept of -2 b) Slope of 5 and y-intercept of 0 d) Slope of 1 and a y-intercept of 5 3 2 Example: Writing the equation of a line in slope-point form Slope-Point form: y y 1 = m(x x 1 ) m = slope (x 1, y 1 ) = point ***Remember to change the signs on the point coordinates only Ex: Write the equation of a line in slope-point form passing through (-4,7) and a slope of -3 y y 1 = m(x x 1 ) Our m is -3 with a point of (-4, 7) so: y 7 = 3(x + 4)

Ex: Write the equation of a line in slope-point form passing through (2,-5) and a slope of 9 y y 1 = m(x x 1 ) Our m is 9 with a point of (2,-5) so: y + 5 = 9(x 2) 2. Write the equations of the following lines in slope-point form a) Slope of -5 and goes through (-3, -6) c) Slope of 3 and goes through (9,-7) Level 3 b) Slope of -1 and goes through (3,7) d) Slope of 7 and goes through (-8,2) Example: Writing equations from a graph Step number 1: Determine the b value. Remember b = y-intercept. On our graph the b = 2 Step number 2: Determine the slope. Find two points and do rise/run. On our graph the m = -2/4 = -1/2 Step number 3: Substitute into y = mx + b. For out graph: y = 1 x + 2 2

3. Determine the equation of each graph below a) b) Example: Writing the equation of a line in General Form General Form: Ax + By + C = 0 Rules: 1. Must = 0 2. No fractions or decimals allowed 3. First term (Ax) must be positive Ex. Write the equation of a line in general form with a slope of 4 and goes through the point (-5, 8) Step 1: Write equation in slope: point form y y 1 = m(x x 1 ) y 8 = 4(x + 5) Step 2: Distribute through the brackets (Multiply) y 8 = 4x + 20 Step 3: Move terms on right hand side to left hand side by doing inverse operations to make it =0 y 8 = 4x + 20-4x + 20-4x - 20-4x + y + 12 = 0 Step 4 Check first term. Since -4x is negative, you must either multiply or divide the entire equation by -1-1(-4x + y + 12 = 0) 4x y 12 = 0

4. Write the following equations in general form a) Slope of 9 and goes through (-6, 2) b) Slope of -4 and goes through (2, -3) c) Slope of 3 and with an x-intercept of -7 Example: Writing the equation of a line in slope-intercept form ( y = mx + b) Ex. Write the equation of a line with a slope of 6 and goes through (-3, -5) in slope-intercept form Step 1: Write equation in slope: point form y y 1 = m(x x 1 ) y + 5 = 6(x + 3) Step 2: Distribute through the brackets y 8 = 6x + 18 Step 3: Now get the y by itself y 8 = 6x + 18 +8 + 8 y = 6x + 26 5. Write the following equation in slope intercept form a) Slope of 5 and goes through (4, -6)

b) Slope of -2 and goes through (-3, 4) c) Slope of 4 with an x-intercept of 5 Example: Writing the equation of a line in General form with a fractional slope Ex. Write the equation of a line with a slope of 2 and goes through (8, -5) 3 Step 1: Write equation in slope: point form y y 1 = m(x x 1 ) y + 5 = 2 (x 8) 3 Step 2: Distribute through the brackets (Multiply numerator only) y + 5 = 2 16 x + 3 3 Step 3: Get rid of the fraction by multiply each term with the common denominator -in our example, the denominator is 3 3(y + 5 = 2 3 x + 16 3 ) 3y + 15 = 6 48 x + 3 3 Now divide your fractions 3y + 15 = 2x + 16

Step 4: The question wanted general form (Ax + By + C = 0). So follow the rules of general form 3y + 15 = -2x + 16 +2x - 16 +2x - 16 2x + 3y 1 = 0 6. Write the following equations in general form a) Slope of 5 and goes through (4, 6) 7 b) Slope of 2 and goes through (-2, 3) 5 Example: Writing the equation of al line in slope-intercept form with a fractional slope Ex. Write the equation of a line with a slope of 5 and goes through (-5, 2) 4 Step 1: Write equation in slope: point form y y 1 = m(x x 1 ) y 2 = 5 (x + 5) 4 Step 2: Distribute through the brackets (Multiply numerator only) y 2 = 5 25 x 4 4

Step 3: Get rid of the fraction by multiply each term with the common denominator -in our example, the denominator is 4 4(y 2 = 5 4 x 25 4 ) 4y 8 = 20 100 x 4 4 Now divide your fractions: 4y 8 = 5x 25 Step 4: The question wanted slope intercept form (y = mx + b), so get y by itself 4y 8 = -5x 25 +8 + 8 4y = - 5x 17 4 4 4 y = 5 17 x 4 4 7. Write the following equations in slope intercept form a) Slope of 3 and goes through (-5, 9) 4 b) Slope of 2 and goes through (-4, -1) 5

Example: Finding the equation of a line in slope intercept form or general form given two points Ex: Determine the equation of a line in both slope-intercept form and general form going though (2, - 3) and (4,3) Step 1: Find the slope using the formula: y 2 y 1 x 2 x 1 For our equation: 3 ( 3) 4 2 = 6 2 = 3 Step 2: Slope Point form (Pick one of the points to use), and simplify I will use (4,3) y 3 = 3(x - 4) y 3= 3x 12 Slope Intercept (get y by itself) (y = mx + b) General (Ax + By + c = 0) y 3= 3x 12 y 3= 3x 12 +3 +3-3x + 12-3x + 12 Y = 3x 9 (-3x + y + 9 = 0)-1 3x y 9 = 0 8. Write the following equations in both slope intercept form and general form a) Goes through (3,7) and (4, 5) b) Goes through (-2, 4) and (3, -5)

Example: Finding the equation of a line in slope-intercept form or general form given that the line is parallel Parallel Lines: Slope is the same Ex. Determine the equation of a line in slope intercept form and general form that is parallel to y = -3x + 7 and goes through (5, -6) Step 1: Determine the slope Our slope will be -3 (number in front of x) Step 2: Use slope point y + 6 = -3(x 5) Distribute y + 6 = -3x + 15 Slope Intercept (get y by itself) (y = mx + b) General (Ax + By + c = 0) y + 6 = -3x + 15 Y + 6 = -3x + 15-6 -6 + 3x - 15 + 3x - 15 Y = -3x + 9 3x + y 9 = 0 Ax is positive so you are done 9. Write the equation of line in both slope-intercept and general from that a) Is parallel to y = 2x 8 and goes through (-7, 3) b) Is parallel to y 4 = -9(x + 3) and goes through (-3, -1)

Example: Finding the equation of a line in slope-intercept form or general form given that the line is perpendicular Perpendicular slopes Negative Reciprocals (Flip the slope, make sure one is positive one is negative) Ex. Determine the equation of a line in slope intercept form and general form that is perpendicular to y = -2x -5 and has an x intercept of 4 Step 1: Determine the slope: Our slope will be + 1 2 Step 2: Use slope point ***x-intercept means point is (4,0) y = 1 (x 4) 2 Distribute y = 1 2 x 4 2 Slope Intercept (get y by itself) (y = mx + b) General (Ax + By + c = 0) y = 1 2 x 4 2 2( y = 1 2 x 4 2 ) Y is by itself by you can divide 4 by 2 2y = 2 2 x 8 2 y = 1 x 2 2y = 1x 4 2-1x + 4-1x + 4 (-1x + 2y + 4 = 0) -1 1x 2y 4 = 0 We don t normally write coefficients of 1 so: x 2y 4 = 0 10. Write the following equation of a line in both slope-intercept and general form a) Perpendicular to y = -4x + 5 and goes through (-2. 9) b) Perpendicular to y = 2 x 2 and goes through (4 7) 3