Honors Statistics Aug 23-8:26 PM 3. Review Homework C5#4 Conditional Probabilities Aug 23-8:31 PM 1
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A Skip 43, 45 How do you want it - the crystal mumbo-jumbo or statistical probability? Apr 25-10:55 AM Role-playing games Computer games in which the players take the roles of characters are very popular. They go back to earlier tabletop games such as Dungeons & Dragons. These games use many different types of dice. A foursided die has faces with 1, 2, 3, and 4 spots (a) List the sample space for rolling the die twice (spots showing on first and second rolls). 1 2 3 4 1 2 3 4 5 2 3 4 5 6 3 4 5 6 7 4 5 6 7 8 (b) What is the assignment of probabilities to outcomes in this sample space? Assume that the die is perfectly balanced. 2 3 4 5 6 7 8 Nov 15-4:10 PM 4
Role-playing games Refer to Exercise 39. Define event A: sum is 5. Find P(A). 2 3 4 5 6 7 8 P(5) = P(1,4) + P(2,3) + P(3,2) + P(4,1) = 0.0625 x 4 = 0.25 Nov 15-3:07 PM Probability models? In each of the following situations, state whether or not the given assignment of probabilities to individual outcomes is legitimate, that is, satisfies the rules of probability. If not, give specific reasons for your answer. (a) Roll a 6-sided die and record the count of spots on the up-face: P(1) = 0, P(2) = 1/6, P(3) = 1/3, P(4) = 1/3,P(5) = 1/6, P(6) = 0. 0 + 1/6 + 1/3 + 1/3 + 1/6 + 0 = 1 so this is a legitimate assignment of probabilities (b) Choose a college student at random and record gender and enrollment status: P(female full-time) = 0.56, P(male full-time) = 0.44, P(female part-time) = 0.24, P(male part-time) = 0.17. 0.56 + 0.44 + 0.24 + 0.17 = 1.41 This is NOT a legitimate assignment of probabilities because the sum is greater than 1 (c) Deal a card from a shuffled deck: P(clubs) = 12/52,P(diamonds) = 12/52, P(hearts) = 12/52, P(spades) = 16/52. 12/52 + 12/52 + 12/52 + 16/52 = 52/52 = 1 This is a legitimate assignment of probabilities. Nov 15-3:07 PM 5
Rolling a die The following figure displays several possible probability models for rolling a die. Some of the models are not legitimate. That is, they do not obey the rules. Which are legitimate and which are not? In the case of the illegitimate models, explain what is wrong 6/7 6/6 7/6 8 NOT YES NOT NOT Nov 15-3:06 PM Blood types All human blood can be typed as one of O, A, B, or AB, but the distribution of the types varies a bit with race. Here is the distribution of the blood type of a randomly chosen black American: (a) What is the probability of type AB blood? Why? P(AB blood) = 1 - P(not AB blood) = 1 - (.49+.27+.20) = 1 -.96 =.04 (b) What is the probability that the person chosen does not have type AB blood? P(not AB blood) = 1 - P(AB blood) = 1 - (.04) = 0.96 (c) Maria has type B blood. She can safely receive blood transfusions from people with blood types O and B. What is the probability that a randomly chosen black American can donate blood to Maria? P(donate to Maria) = P( type O or type B)=.49 +.20 =.69 Nov 15-4:40 PM 6
Languages in Canada Canada has two official languages, English and French. Choose a Canadian at random and ask, What is your mother tongue? Here is the distribution of responses, combining many separate languages from the broad Asia/Pacific region: 7 > (a) What probability should replace? in the distribution? Why? P(other) = 1 - P(not other) = 1 - (0.63 + 0.22 + 0.06) = 1 -.91 =.09 > (b) What is the probability that a Canadian s mother tongue is not English? P(not ENGLISH) = 1 - P(ENGLISH) = 1 - (0.63) = 0.37 > (c) What is the probability that a Canadian s mother tongue is a language other than English or French? P(not ENGLISH and not FRENCH) = 1 - P(ENGLISH or FRENCH) = 1 - (0.85) = 0.15 Nov 15-4:40 PM Education among young adults Choose a young adult (aged 25 to 29) at random. The probability is 0.13 that the person chosen did not complete high school, 0.29 that the person has a high school diploma but no further education, and 0.30 that the person has at least a bachelor s degree. P(not high school) = 0.13 P(high school only) = 0.29 P(at least bachelor's degree) = 0.30 (a) What must be the probability that a randomly chosen young adult has some education beyond high school but does not have a bachelor s degree? Why? P(some education but not a bachelor's degree) = 1 - (0.13 + 0.29 + 0.30) (b) = 1-0.72 = 0.28 What is the probability that a randomly chosen young adult has at least a high school education? Which rule of probability did you use to find the answer? Law of Complements P(at least high school education) = 1 - P(not high school) = 1-0.13 = 0.87 Nov 15-4:41 PM 7
Who eats breakfast? Students in an urban school were curious about how many children regularly eat breakfast. They conducted a survey, asking, Do you eat breakfast on a regular basis? All 595 students in the school responded to the survey. The resulting data are shown in the two-way table below. 8 If we select a student from the school at random, what is the probability that the student is (a) a female? 275 P(female) = = 0.462 595 (b) someone who eats breakfast regularly? 300 P(breakfast) = = 0.504 595 (c) a female and eats breakfast regularly? P(female and breakfast) = = 0.185 (d) a female or eats breakfast regularly? OR P(female or breakfast) = = 0.782 275 + 300-110 P(female or breakfast) = = 0.782 595 110 595 165 + 190 + 110 595 465 595 465 595 Nov 15-4:41 PM Roulette An American roulette wheel has 38 slots with numbers 1 through 36, 0, and 00, as shown in the figure. Of the numbered slots, 18 are red, 18 are black, and 2 the 0 and 00 are green. When the wheel is spun, a metal ball is dropped onto the middle of the wheel. If the wheel is balanced, the ball is equally likely to settle in any of the numbered slots. Imagine spinning a fair wheel once. Define events B: ball lands in a black slot, and E: ball lands in an even-numbered slot. (Treat 0 and 00 as even numbers.) > (a) Make a two-way table that displays the sample space in terms of events B and E. (b) Find P(B) and P(E). 18 P(black) = = 0.474 38 (c) Describe the event B and E in words. Then find P(Band E). (d) Explain why P(B or E) P(B) + P(E). 20 P(even) = = 0.526 38 What is the probability that the metal ball lands in a slot that is black and an even number? 10 P(black and even) = = 0. 263 38 Then use the general addition rule to compute P(B or E). There are some slots that are black and even. These events are not mutually exclusive so we must be careful not to count the black and even slots twice. P(black or even) = = 0. 737 OR 8 + 10 + 10 38 18 + 20-10 P(black or even) = = 0. 737 38 Nov 15-4:42 PM 8
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Card Facts: 52 cards in a deck two colors in a deck: 26 BLACK Cards red and black 26 RED Cards four suits in a deck: hearts, diamonds, spades, and clubs 13 cards in a suit 3 different face cards: total 12 face cards King, Queen, Jack numbered cards are 2 thru 10 four aces in a deck: or a low card (1) Nov 18-1:40 PM 1. Make a two-way table that displays the sample space. 2. Find P(F and H). 3. Explain why P(F or H) P(F) + P(H). Then use the general addition rule to find P(F or H). Nov 15-6:05 PM 15
kahoot.it Apr 13-3:44 PM A Skip 52, 55 How do you want it - the crystal mumbo-jumbo or statistical probability? v = venn diagram needed Apr 25-10:55 AM 16
Preparing for the GMAT A company that offers courses to prepare students for the Graduate Management Admission Test (GMAT) has the following information about its customers: 20% are currently undergraduate students in business; 15% are undergraduate students in other fields of study; 60% are college graduates who are currently employed; and 5% are college graduates who are not employed. Choose a customer at random. P(Undergrad and Business) = 0.20 P(Undergrad and other) = 0.15 P(Grad and Employed) = 0.60 P(Grad and not employed) = 0.05 Notice that all the Probabilities add up to 1.00 (a) What s the probability that the customer is currently an undergraduate? Which rule of probability did you use to find the answer? P(Undergrad) = P(Undergrad and Business) + P(Undergrad and other) = 0.35 or 35% I can add these because the events (Undergrad Bus) and (Undergrad other) are mutually exclusive. (b) What s the probability that the customer is not an undergraduate business student? Which rule of probability did you use to find the answer? NOT Law of complements P(Undergrad Business c ) = 1-0.20 = 0.80 Nov 15-6:28 PM Sampling senators The two-way table below describes the members of the U.S Senate in a recent year. 83 17 100 If we select a U.S. senator at random, what s the probability that the senator is 60 40 (a) a Democrat? (b) a female? 60 P(Democrat) = --------- = 0.60 100 17 P(Female) = --------- = 0.17 100 (c) a female and a Democrat? 13 P(Female and Democrat) = --------- = 0.13 100 (d) a female or a Democrat? Two ways to do this problem Way 1 - Using the General Addition formula Way 2 - Using the table counts P(Female or Democrat) = P(Female) + P(Democrat) - P(Female and Democrat) 17 60 13 64 P(Female or Democrat) = -------- + -------- - -------- = ------- = 0.64 100 100 100 100 13 + 4 + 47 64 P(Female or Democrat) = --------------------- = ------- = 0.64 100 100 Nov 15-6:09 PM 17
Playing cards Shuffle a standard deck of playing cards and deal one card. Define events J: getting a jack, and R: getting a red card. (a) Construct a two-way table that describes the sample space in terms of events J and R. Jack Jack C Red 2 24 26 Red C 2 24 26 4 48 52 (b) Find P(J) and P(R). 4 P(J) = -------- = 0.077 26 P(R) = ---------- = 0.5 52 52 (c) Describe the event J and R in words. Then find P(J and R). 2 The card is a red jack or the card is red and a jack. P(J and R) = -------- = 0.038 52 (d) Explain why P(J or R) P(J) + P(R). Then use the general addition rule to compute P(J or R). The events card is red and card is a jack are not mutually exclusive... thus one will count two cards twice unless using the general probability addition formula. 2 + 2 + 24 28 P(J U R) = ---------------- = ------- = 0.538 52 52 4 26 2 28 P(J U R) = ------ + ------- -------- = ------- = 0.538 52 52 52 52 OR Nov 15-6:00 PM Who eats breakfast? Refer to Exercise 49. (a) Construct a Venn diagram that models the chance process using events B: eats breakfast regularly, and M: is male. B M 110 190 130 165 (b) Find P(B M). Interpret this value in context. 110+ 190+130 430 P(B U M) = ---------------- = ------- = 0.723 595 595 300 320 190 430 P(B U M) = ------ + ------- -------- = ------- = 0.723 595 595 595 595 OR the probabililty that person is a male or eats breakfast regularly (or both) = 72.3% (c) Find P(B C M C ). Interpret this value in context. P(B C M C 165 ) = -------- = 0.277 595 the probabililty that a person is not a male and does not eat breakfast is 27.7% Nov 15-6:33 PM 18
Sampling senators Refer to Exercise 50. 83 17 100 (a) Construct a Venn diagram that models the chance process using events R: is a Republican, and F: is female. 60 40 R F 36 4 13 47 (b) Find P(R F). Interpret this value in context. 36 +4 + 13 53 P(R U F) = ----------- = ------- = 0.53 100 100 83 17 4 53 P(R U F) = ------ + ------- -------- = ------- = 0.53 100 100 100 100 OR the probabililty that a senator is a Republican or a Female (or both) = 53% (c) Find P(R C F C ). Interpret this value in context. P(R C F C 47 ) = -------- = 0.47 100 the probabililty that a senator is a not Republican and not Female = 47% Nov 15-6:33 PM Facebook versus YouTube A recent survey suggests that 85% of college students have posted a profile on Facebook, 73% use YouTube regularly, and 66% do both. Suppose we select a college student at random. (a) Make a two-way table for this chance process. FACE N F UTube 0.66 0.07 N U 0.19 0.08 0.73 0.27 0.85 0.15 1.00 (b) Construct a Venn diagram to represent this setting. U T 0.07 Face 0.66 0.19 0.23 (c) Consider the event that the randomly selected college student has posted a profile on Facebook or uses YouTube regularly. Write this event in symbolic form based on your Venn diagram in part (b). P(Face or UTube) = P(F U T) = (d) Find the probability of the event described in part (c). Explain your method. P(F U T) = P(F) + P(T) - P(F T) = 0.85 + 0.73-0.66 = 0.92 OR USing VENN DIAGRAM P(F U T) = 0.07 + 0.66 + 0.19 = 0.92 Nov 15-6:33 PM 19
Mac or PC? A recent census at a major university revealed that 40% of its students mainly used Macintosh computers (Macs). The rest mainly used PCs. At the time of the census, 67% of the school s students were undergraduates. The rest were graduate students. In the census, 23% of respondents were graduate students who said that they used PCs as their main computers. Suppose we select a student at random from among those who were part of the census. (a) Make a two-way table for this chance process. MAC PC Und 0.30 Grad 0.10 0.37 0.23 0.67 0.33 0.40 0.60 1.00 (b) Construct a Venn diagram to represent this setting. Und 0.37 MAC 0.30 0.10 0.23 (c) Consider the event that the randomly selected student is a graduate student and uses a Mac. Write this event in symbolic form based on your Venn diagram in part (b). P(Graduate and MAC) = P(U c and MAC) (d) Find the probability of the event described in part (c). Explain your method. P(Graduate and MAC) = P(U c and MAC) = 0.10 ALTERNATIVE VENN DIAGRAM Grad 0.23 MAC 0.10 0.30 0.37 c and d) P(G and MAC) = P(G M) = 0.10 Nov 15-6:33 PM Apr 14-9:07 AM 20