Exam Time. Final Exam Review. TR class Monday December 9 12:30 2:30. These review slides and earlier ones found linked to on BlackBoard

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Final Exam Review These review slides and earlier ones found linked to on BlackBoard Bring a photo ID card: Rocket Card, Driver's License Exam Time TR class Monday December 9 12:30 2:30 Held in the regular classroom. Extra office hours in UHall 3014 Monday 10:00-12:30 1 2 Covers: 12.1 Counting Methods 12.2 Fundamental Counting Principle 12.3 Permutations and Combinations 13.1 The Basics of Probability 13.2 Complements and Unions of Events 13.3 Conditional Probability 14.1 Organization and Visualizing of Data 14.2 Measures of Central Tendancy 14.3 Measures of Dispersion 14.4 The Normal Distribution 3 Know the basic vocabulary of the sections. The test will be multiple choice. The test will be like the online HW rather than the lab assignments. 4 In a selection where repetition is allowed, the phrase with repetition is used. In a selection where repetition is not allowed, the phrase without repetition is used. There is a graphical way to organize and count. A tree diagram is a visual method for each new choice at a step we get a new branch. Work from left to right. Choice 1 Start Choice 2 5 Choice 3 6

Example: A bag has R, G, B, Y marbles. Draw the tree diagram for removing 2 without replacement. Example: A bag has R, G, B, Y marbles. Draw the tree diagram for removing 2 with replacement. 7 8 At an Ice Cream shop they have 5 different flavors of ice cream and you can pick one of 4 toppings. How many choices do you have? 9 10 At an Ice Cream shop they have 5 different flavors of ice cream and you can pick one of 4 toppings. How many choices do you have? Example: A license plate has 3 letters followed by three numbers. Every letter and number must be unique. How many different license plates are there? 5 choices of flavors, 4 choices of toppings 5x4 = 20 11 12

Example: A license plate has 3 letters followed by three numbers. Every letter and number must be unique. How many different license plates are there? A permutation of n objects r at a time is the number of ways r things (out of n) can be chosen in an ordered way. A combination of n objects r at a time is the number of ways r things (out of n) can be chosen in an unordered way. 26 x 25 x 24 x 10 x 9 x 8 = 11,232,000 13 14 Shortcut/Defintion Example: 5! = 5x4x3x2x1 15 12/04/13 16 Example: How many ways are there to make a 2 topping pizza if you have 5 toppings to choose from? Example: How many ways are there to make a 2 topping pizza if you have 5 toppings to choose from? Order does not matter = combination. C(5,2) = 5! = 5 x 4 x 3 x 2 x 1 = 10 (5-2)! 2! 3 x 2 x 1 x 2 x 1 17 18

An experiment is a controlled operation that yields a set of results. The possible results of an experiment are called its outcomes. The set of outcomes are the sample space. An event is a subcollection of the outcomes of an experiment. 19 Probability is a fraction (or decimal) between 0 (doesn't happen) and 1 (always happens). Probability of Event E = P(E) Theoretical = found mathmatically number of times event happens number of possible outcomes Empirical = found by running experiments number of times event happens number of times experiment run 20 Example: Experiment is roll a die. Sample space: { 1, 2, 3, 4, 5, 6 } What is the probability of rolling an odd number? Example: Experiment is roll a die. Sample space: { 1, 2, 3, 4, 5, 6 } What is the probability of rolling an odd number? Event E = { 1, 3, 5 } P(E) = 3/6 = 1/2 21 22 Odds and probability are similar. Probability #(it happens) / #(total) If a family has three children, what are the odds against all three children being the same gender? Odds for #(it happens) : #(it does not happen) Odds against #(it does not happen) : #(it happens) 23 24

If a family has three children, what are the odds against all three children being the same gender? E = same gender = { bbb, ggg } E' = complement = not all the same = { bbg, bgb, bgg, gbb, gbg, ggb } Recall: The complement of a set is the collection of elements not in that set. A' = { elements not in A } The complement of an event E, is the collection of outcomes not in E. E' = { outcomes not in E } 6:2 against or 3:1 against 25 26 If an outcome is in the sample space, it must be in E or E'. Unions of Events So E and E' give all outcomes. So P(E) + P(E') = 1 (100%) 27 12/04/13 28 2010 Pearson Education, reserved. Inc. All rights Section 14.2, Slide 28 Unions of Events Unions of Events Example: If we select a single card from a standard 52-card deck, what is the probability that we draw either a heart or a face card? Solution: Let H be the event draw a heart and F be the event draw a face card. We are looking for P(H U F). There are 13 hearts, 12 face cards, and 3 cards that are both hearts and face cards. 12/04/13 (continued 29 on next slide) 12/04/13 30 2010 Pearson Education, reserved. Section 14.2, Slide 29 2010 Pearson Education, reserved. Inc. All rights Inc. All rights Section 14.2, Slide 30

If you are given 3 out of the 4 terms in the equation P(E U F) = P(E) + P(F) P(E F) Then you can use algebra to find the remaining term. This can also be read as P(E or F) = P(E) + P(F) P(E and F) 31 Conditional probability is the probability of one event (F) happening assuming that another event (E) does. Examples: - probability that someone is happy given that they just won $$$. - probability that someone passes an exam given that they did not study. The probability that F happens given that E does is denoted P(F E) It is read probability of F given E 32 Example: Roll a die for an experiment. What is the probability it is odd given that the value was a prime number? Example: Roll a die for an experiment. What is the probability it is odd given that the value was a prime number? The event assumed to happen was that the value was prime. Among those the event is when is it odd. 33 34 Example: Roll a die for an experiment. What is the probability it is odd given that the value was a prime number? The previous examples lead to a way to count P( F E ) by a formula: The event assumed to happen was that the value was prime. { 2, 3, 5 } Among those the event is when is it odd. { 3, 5 } P(odd prime) = 2/3 35 36

Counting how often a data value occurs is its frequency. Counting the percent (%) is its relative frequency. Frequency distribution (or table) is the collection of data with its frequency. Similar for Relative frequency distribution. Data can also be grouped in ranges. Data: 51 56 58 53 60 53 61 53 59 57 53 56 61 54 58 59 52 55 56 56 Range Frequency Rel Freq 50 52 2 10% 53 55 6 30% 56 58 7 35% 59 61 5 25% Total Data: 20 37 38 Data Visualizing A bar graph is 2 dimensional - x-axis is data (or ranges) - y-axis is (relative) frequency - draw the height of a rectangle equal to its (relative frequency) A stem-and-leaf plot splits numerical data into two pieces: - stem = first digit - leaf = last digit 46 43 40 47 49 70 65 50 73 49 47 48 51 58 50 39 40 There are 3 types of center: Ex 1, 2, 3, 3, 3, 6, 7, 9, 9, 10, 10 Mean x = Σx/x Median After ordering, its the # in the middle (if two #s in the middle, take average) Mode The number which occurs the most (if more than one multimodal) Mean x = (1+2+3+3+3+6+7+9+9+10+10)/11 = 5.72727 Median Middle = 6 Mode Most = 3 (if none no mode) 41 42

Given a frequency table, - find the total number of data points, which is the sum of the frequencies So find Σf - find the sum of all values, if freq f occurs x times it contributes xf So find Σxf Example: What is the mean temperature? The mean is: 43 44 Five Number Summary 1. Order the data Example: 3 4 5 5 6 7 8 8 9 9 9 2. Find the smallest, largest and median. 3. Find the median of the lower half, Q1 4. Find the median of the upper half, Q3 5. The Five Number Summary is: Lower half Upper half Median Smallest = 3 Q1 = 5 Median = 7 Q3 = 9 Largest = 9 smallest, Q1, median, Q3, 45 largest 46 Summary: 3, 5, 7, 9, 9 The Box and Whiskers Plot is a visual representation of the Five Number Summary Example: Summary = 42, 51, 55, 60.5 69 Definition: Std. Deviation = Σ (x-x) 2 n-1 47 Data x x- x (x-x) 2 2-3 9 variance 4-1 1 = 24/5 7 2 4 = 1.2 5 0 0 4-1 1 std. dev. 8 3 9 = (1.2) 1/2 48= 1.09544 Sum (Σ) 0 24

Overall idea for Normal Distributions: Raw data x z-score areas use: Table Example: Suppose the mean of a normal distribution is 20 and its std dev is 3. Find the z-score of 25. µ (mu) = population mean σ (sigma) = population standard deviation Find the z-score of 16. 49 50 The area between z-scores gives the percent of data values between them. Below is a table that gives the area between the mean (µ) and a given z-score. Find the percent of data between z=0 and z=1.3 For z = 1.3 A = 0.40 Area between = 0.403 or 40.3% 51 52