856 SALT LAKE COURT SAN JOSE, CA 95133 (408) 251 5329 Single Part Tolerance Analysis 1 2X Ø.250 ±.005 D 3.075-3.175.500 2.000.250 ±.005 E.375 C 2.050 1.950.609.859 1.375 G 1.125 B.375.750 1.125 1.500 1.875 28X Ø.125 ±.005 A Figure 8-1 A pattern of features located to a second pattern of features The engineer who designed the part above may want to determine how close the bottom row of the Ø.125 holes is to the bottom edge of the plate. This procedure is demonstrated in the 3 steps shown below. Step 1: Determine what characteristic is to be analyzed. In this case, the gap in question is the shortest distance between the bottom hole and the bottom edge of the part. 1 Cogorno, Gene R., Geometric Dimensioning and Tolerancing for Mechanical Design, Second Edition, McGraw-Hill, New York, 2011, p. 120. 2.250
Step 2: Draw the loop analysis diagram. The loop analysis diagram is the circuit that connects all of the features that contribute to the gap under investigation. Step 3: Determine the boundaries of each feature and convert them to equal bilateral plus or minus tolerances. Ø.250 ±.005 B Ø.130 @ LMC.125 ±.005 Gap End Start Figure 8-1A The loop analysis diagram is used to investigate the gap between the bottom hole and the bottom edge of the part for the drawing in Figure 8-1
The overall height of the part, 1.950 2.050, has a zero perpendicularity tolerance at MMC to datum feature A. The worst-case boundaries of this dimension are the virtual and the resultant conditions. Convert the part height to an equal bilateral plus or minus tolerance. 2.050 1.950 Resultant Condition Virtual Condition 1.950 Height @ LMC 2.050 Height @ MMC -.000 Geo. Tol. +.000 Geo. Tol. -.100 Bonus Tol. 2.050 Total 1.850 Total Result. Condition 2.050 2.050 Virtual Condition + 1.850 1.850 2) 3.900 2).200 1.950.100 The equal bilateral ± tolerance is: 1.950 ±.100
The Ø.125 hole is located from the Ø.250 hole, datum feature B. Calculate the positional tolerance and the pattern shift of the Ø.250 hole at its LMC size. Ø.250 ±.005 Total positional tolerance Positional tolerance equals.050 Bonus at LMC equals +.010 Total positional tolerance at LMC equals.060 Pattern shift: The Ø.250 hole at LMC equals.255 The virtual condition of datum feature B with respect to datum feature A equals.245 Pattern shift equals The sum of the positional tolerance and the pattern shift equals.010.070 Since the Ø.125 hole is located to the Ø.250 hole, the worst-case boundaries consist of the resultant and virtual conditions of the Ø.125 hole combined with the positional tolerance and the pattern shift (.070) of the Ø.250 hole. Ø.125 ±.005 Resultant Condition Virtual Condition.130 Hole @ LMC.120 Hole @ MMC +.000 Geo. Tol. -.000 Geo. Tol. +.010 Bonus Tol..120 Total.140 Total +.070.070.210.050 Pos. Tol. + Pattern Shift
Result. Condition.210.210 Virtual Condition +.050.050 2).260 2).160.130.080 Dimension with ± tolerance =.130 ±.080 Dimension with ± tolerance/2 =.065 ±.040 Ø.250 ±.005 B Ø.060 Position Tol. @ LMC.375 1.950 ±.100 Ø.255 @ LMC Ø.245 Virtual Condition to A 1.375 Ø.130 @ LMC.125 ±.005.065 ±.040 Gap End Start Figure 8-1B The loop analysis diagram with dimensions and tolerances All of the positive and negative vectors are placed in the numbers chart. The positive vectors are dimensions that are measured from the bottom up and from the left to the right. The negative vectors are dimensions that are measured from the top down and from the right to the left. The tolerances are placed in the ± tolerance column. The vectors and the tolerances are totaled at the bottom. The sums of the vectors are added algebraically. The sum of the tolerances is added to, and subtracted from, the algebraic sum of all of the vectors to determine the MAX GAP and the MIN GAP.
Numbers Chart Vectors Tolerances + ± 1.950.100.375.000 1.375.000.065.040 1.815 + 1.950.140 Σ Of VECTORS MAX GAP MIN GAP + 1.950 +.135 +.135 1.815 +.140.140 +.135 +.275.005 Although not a factor in this problem, it is possible that the rotation of the hole pattern controlled by datum feature C contributes to the gap dimensions. If that is the case, the rotation must be determined and the largest effect must be included in the analysis calculations. Of the three steps in this analysis, step 2, drawing the loop analysis diagram, is the most critical and sometimes the most difficult to accomplish. It may take more than one try to determine the worst-case condition.